YES
We show the termination of the TRS R:

  app(app(minus(),|0|()),y) -> |0|()
  app(app(minus(),app(s(),x)),|0|()) -> app(s(),x)
  app(app(minus(),app(s(),x)),app(s(),y)) -> app(app(minus(),x),y)
  app(app(le(),|0|()),y) -> true()
  app(app(le(),app(s(),x)),|0|()) -> false()
  app(app(le(),app(s(),x)),app(s(),y)) -> app(app(le(),x),y)
  app(app(app(if(),true()),x),y) -> x
  app(app(app(if(),false()),x),y) -> y
  app(perfectp(),|0|()) -> false()
  app(perfectp(),app(s(),x)) -> app(app(app(app(f(),x),app(s(),|0|())),app(s(),x)),app(s(),x))
  app(app(app(app(f(),|0|()),y),|0|()),u) -> true()
  app(app(app(app(f(),|0|()),y),app(s(),z)),u) -> false()
  app(app(app(app(f(),app(s(),x)),|0|()),z),u) -> app(app(app(app(f(),x),u),app(app(minus(),z),app(s(),x))),u)
  app(app(app(app(f(),app(s(),x)),app(s(),y)),z),u) -> app(app(app(if(),app(app(le(),x),y)),app(app(app(app(f(),app(s(),x)),app(app(minus(),y),x)),z),u)),app(app(app(app(f(),x),u),z),u))
  app(app(map(),|fun|),nil()) -> nil()
  app(app(map(),|fun|),app(app(cons(),x),xs)) -> app(app(cons(),app(|fun|,x)),app(app(map(),|fun|),xs))
  app(app(filter(),|fun|),nil()) -> nil()
  app(app(filter(),|fun|),app(app(cons(),x),xs)) -> app(app(app(app(filter2(),app(|fun|,x)),|fun|),x),xs)
  app(app(app(app(filter2(),true()),|fun|),x),xs) -> app(app(cons(),x),app(app(filter(),|fun|),xs))
  app(app(app(app(filter2(),false()),|fun|),x),xs) -> app(app(filter(),|fun|),xs)

Instead we prove termination of the uncurried system:

  app(cons_0(),y) -> cons_1(y)
  app(cons_1(x1),y) -> cons_2(x1,y)
  app(f_0(),y) -> f_1(y)
  app(f_1(x1),y) -> f_2(x1,y)
  app(f_2(x1,x2),y) -> f_3(x1,x2,y)
  app(f_3(x1,x2,x3),y) -> f_4(x1,x2,x3,y)
  app(filter_0(),y) -> filter_1(y)
  app(filter_1(x1),y) -> filter_2(x1,y)
  app(filter2_0(),y) -> filter2_1(y)
  app(filter2_1(x1),y) -> filter2_2(x1,y)
  app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
  app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
  app(if_0(),y) -> if_1(y)
  app(if_1(x1),y) -> if_2(x1,y)
  app(if_2(x1,x2),y) -> if_3(x1,x2,y)
  app(le_0(),y) -> le_1(y)
  app(le_1(x1),y) -> le_2(x1,y)
  app(map_0(),y) -> map_1(y)
  app(map_1(x1),y) -> map_2(x1,y)
  app(minus_0(),y) -> minus_1(y)
  app(minus_1(x1),y) -> minus_2(x1,y)
  app(perfectp_0(),y) -> perfectp_1(y)
  app(s_0(),y) -> s_1(y)
  minus_2(|0|_0(),y) -> |0|_0()
  minus_2(s_1(x),|0|_0()) -> s_1(x)
  minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
  le_2(|0|_0(),y) -> true_0()
  le_2(s_1(x),|0|_0()) -> false_0()
  le_2(s_1(x),s_1(y)) -> le_2(x,y)
  if_3(true_0(),x,y) -> x
  if_3(false_0(),x,y) -> y
  perfectp_1(|0|_0()) -> false_0()
  perfectp_1(s_1(x)) -> f_4(x,s_1(|0|_0()),s_1(x),s_1(x))
  f_4(|0|_0(),y,|0|_0(),u) -> true_0()
  f_4(|0|_0(),y,s_1(z),u) -> false_0()
  f_4(s_1(x),|0|_0(),z,u) -> f_4(x,u,minus_2(z,s_1(x)),u)
  f_4(s_1(x),s_1(y),z,u) -> if_3(le_2(x,y),f_4(s_1(x),minus_2(y,x),z,u),f_4(x,u,z,u))
  map_2(|fun|,nil_0()) -> nil_0()
  map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs))
  filter_2(|fun|,nil_0()) -> nil_0()
  filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs)
  filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs))
  filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs)


-- SCC decomposition.

Consider the dependency pair problem (P, R), where P consists of

p1: app#(f_3(x1,x2,x3),y) -> f_4#(x1,x2,x3,y)
p2: app#(filter_1(x1),y) -> filter_2#(x1,y)
p3: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y)
p4: app#(if_2(x1,x2),y) -> if_3#(x1,x2,y)
p5: app#(le_1(x1),y) -> le_2#(x1,y)
p6: app#(map_1(x1),y) -> map_2#(x1,y)
p7: app#(minus_1(x1),y) -> minus_2#(x1,y)
p8: app#(perfectp_0(),y) -> perfectp_1#(y)
p9: minus_2#(s_1(x),s_1(y)) -> minus_2#(x,y)
p10: le_2#(s_1(x),s_1(y)) -> le_2#(x,y)
p11: perfectp_1#(s_1(x)) -> f_4#(x,s_1(|0|_0()),s_1(x),s_1(x))
p12: f_4#(s_1(x),|0|_0(),z,u) -> f_4#(x,u,minus_2(z,s_1(x)),u)
p13: f_4#(s_1(x),|0|_0(),z,u) -> minus_2#(z,s_1(x))
p14: f_4#(s_1(x),s_1(y),z,u) -> if_3#(le_2(x,y),f_4(s_1(x),minus_2(y,x),z,u),f_4(x,u,z,u))
p15: f_4#(s_1(x),s_1(y),z,u) -> le_2#(x,y)
p16: f_4#(s_1(x),s_1(y),z,u) -> f_4#(s_1(x),minus_2(y,x),z,u)
p17: f_4#(s_1(x),s_1(y),z,u) -> minus_2#(y,x)
p18: f_4#(s_1(x),s_1(y),z,u) -> f_4#(x,u,z,u)
p19: map_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x)
p20: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs)
p21: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs)
p22: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x)
p23: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs)
p24: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(f_0(),y) -> f_1(y)
r4: app(f_1(x1),y) -> f_2(x1,y)
r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y)
r6: app(f_3(x1,x2,x3),y) -> f_4(x1,x2,x3,y)
r7: app(filter_0(),y) -> filter_1(y)
r8: app(filter_1(x1),y) -> filter_2(x1,y)
r9: app(filter2_0(),y) -> filter2_1(y)
r10: app(filter2_1(x1),y) -> filter2_2(x1,y)
r11: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r12: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r13: app(if_0(),y) -> if_1(y)
r14: app(if_1(x1),y) -> if_2(x1,y)
r15: app(if_2(x1,x2),y) -> if_3(x1,x2,y)
r16: app(le_0(),y) -> le_1(y)
r17: app(le_1(x1),y) -> le_2(x1,y)
r18: app(map_0(),y) -> map_1(y)
r19: app(map_1(x1),y) -> map_2(x1,y)
r20: app(minus_0(),y) -> minus_1(y)
r21: app(minus_1(x1),y) -> minus_2(x1,y)
r22: app(perfectp_0(),y) -> perfectp_1(y)
r23: app(s_0(),y) -> s_1(y)
r24: minus_2(|0|_0(),y) -> |0|_0()
r25: minus_2(s_1(x),|0|_0()) -> s_1(x)
r26: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r27: le_2(|0|_0(),y) -> true_0()
r28: le_2(s_1(x),|0|_0()) -> false_0()
r29: le_2(s_1(x),s_1(y)) -> le_2(x,y)
r30: if_3(true_0(),x,y) -> x
r31: if_3(false_0(),x,y) -> y
r32: perfectp_1(|0|_0()) -> false_0()
r33: perfectp_1(s_1(x)) -> f_4(x,s_1(|0|_0()),s_1(x),s_1(x))
r34: f_4(|0|_0(),y,|0|_0(),u) -> true_0()
r35: f_4(|0|_0(),y,s_1(z),u) -> false_0()
r36: f_4(s_1(x),|0|_0(),z,u) -> f_4(x,u,minus_2(z,s_1(x)),u)
r37: f_4(s_1(x),s_1(y),z,u) -> if_3(le_2(x,y),f_4(s_1(x),minus_2(y,x),z,u),f_4(x,u,z,u))
r38: map_2(|fun|,nil_0()) -> nil_0()
r39: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs))
r40: filter_2(|fun|,nil_0()) -> nil_0()
r41: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs)
r42: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs))
r43: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs)

The estimated dependency graph contains the following SCCs:

  {p2, p3, p6, p19, p20, p21, p22, p23, p24}
  {p12, p16, p18}
  {p10}
  {p9}


-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: map_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x)
p2: app#(map_1(x1),y) -> map_2#(x1,y)
p3: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs)
p4: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y)
p5: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs)
p6: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x)
p7: app#(filter_1(x1),y) -> filter_2#(x1,y)
p8: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs)
p9: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(f_0(),y) -> f_1(y)
r4: app(f_1(x1),y) -> f_2(x1,y)
r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y)
r6: app(f_3(x1,x2,x3),y) -> f_4(x1,x2,x3,y)
r7: app(filter_0(),y) -> filter_1(y)
r8: app(filter_1(x1),y) -> filter_2(x1,y)
r9: app(filter2_0(),y) -> filter2_1(y)
r10: app(filter2_1(x1),y) -> filter2_2(x1,y)
r11: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r12: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r13: app(if_0(),y) -> if_1(y)
r14: app(if_1(x1),y) -> if_2(x1,y)
r15: app(if_2(x1,x2),y) -> if_3(x1,x2,y)
r16: app(le_0(),y) -> le_1(y)
r17: app(le_1(x1),y) -> le_2(x1,y)
r18: app(map_0(),y) -> map_1(y)
r19: app(map_1(x1),y) -> map_2(x1,y)
r20: app(minus_0(),y) -> minus_1(y)
r21: app(minus_1(x1),y) -> minus_2(x1,y)
r22: app(perfectp_0(),y) -> perfectp_1(y)
r23: app(s_0(),y) -> s_1(y)
r24: minus_2(|0|_0(),y) -> |0|_0()
r25: minus_2(s_1(x),|0|_0()) -> s_1(x)
r26: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r27: le_2(|0|_0(),y) -> true_0()
r28: le_2(s_1(x),|0|_0()) -> false_0()
r29: le_2(s_1(x),s_1(y)) -> le_2(x,y)
r30: if_3(true_0(),x,y) -> x
r31: if_3(false_0(),x,y) -> y
r32: perfectp_1(|0|_0()) -> false_0()
r33: perfectp_1(s_1(x)) -> f_4(x,s_1(|0|_0()),s_1(x),s_1(x))
r34: f_4(|0|_0(),y,|0|_0(),u) -> true_0()
r35: f_4(|0|_0(),y,s_1(z),u) -> false_0()
r36: f_4(s_1(x),|0|_0(),z,u) -> f_4(x,u,minus_2(z,s_1(x)),u)
r37: f_4(s_1(x),s_1(y),z,u) -> if_3(le_2(x,y),f_4(s_1(x),minus_2(y,x),z,u),f_4(x,u,z,u))
r38: map_2(|fun|,nil_0()) -> nil_0()
r39: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs))
r40: filter_2(|fun|,nil_0()) -> nil_0()
r41: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs)
r42: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs))
r43: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs)

The set of usable rules consists of

  r3, r4, r7, r13, r16, r17, r21, r23, r24, r25, r26, r27, r28, r29, r32, r34, r35, r38

Take the reduction pair:

  generalized weighted path order (>=MG, >G)
  
    base order 1:
  
      trivial reduction triple (T x T, T x T, Φ)
  
    base order 2:
  
      lexicographic combination of reduction triples:
      
        1. marked-algebra reduction triple (>=A, >=A!, >A!):
        
          max/plus interpretation on natural numbers:
          
            map_2#_A(x1,x2) = max{1, x1 - 23, x2 - 10}
            cons_2_A(x1,x2) = max{x1 + 5, x2}
            app#_A(x1,x2) = max{1, x1 - 72, x2 - 5}
            map_1_A(x1) = x1 + 49
            filter2_3_A(x1,x2,x3) = max{x1 - 21, x2 + 2, x3 + 7}
            filter2_4#_A(x1,x2,x3,x4) = max{1, x2 - 70, x3 - 65, x4 - 5}
            false_0_A = 13
            filter_2#_A(x1,x2) = max{1, x1 - 70, x2 - 5}
            filter_1_A(x1) = max{71, x1 + 2}
            app_A(x1,x2) = max{95, x1 - 6, x2 + 2}
            true_0_A = 13
            f_0_A = 5
            f_1_A(x1) = max{3, x1 - 1}
            f_2_A(x1,x2) = max{3, x1 - 7, x2 - 9}
            filter_0_A = 5
            if_0_A = 0
            if_1_A(x1) = max{3, x1 - 9}
            le_0_A = 5
            le_1_A(x1) = max{68, x1 - 9}
            le_2_A(x1,x2) = max{63, x2 - 15}
            minus_1_A(x1) = x1 + 19
            minus_2_A(x1,x2) = max{14, x1}
            s_0_A = 0
            s_1_A(x1) = x1
            |0|_0_A = 0
            perfectp_1_A(x1) = max{75, x1 - 16}
            f_4_A(x1,x2,x3,x4) = max{75, x2 - 15, x4 - 3}
            map_2_A(x1,x2) = max{x1 + 100, x2 + 43}
            nil_0_A = 101
            map_2#!_A(x1,x2) = max{72, x1 + 56}
            cons_2!_A(x1,x2) = max{80, x1 - 3}
            app#!_A(x1,x2) = x1 + 22
            map_1!_A(x1) = max{73, x1 + 57}
            filter2_3!_A(x1,x2,x3) = max{0, x1 - 15, x2 - 2, x3 - 98}
            filter2_4#!_A(x1,x2,x3,x4) = x2 + 23
            false_0!_A = 2
            filter_2#!_A(x1,x2) = x1 + 23
            filter_1!_A(x1) = x1 + 24
            app!_A(x1,x2) = max{x1 + 8, x2 + 77}
            true_0!_A = 1
            f_0!_A = 74
            f_1!_A(x1) = 73
            f_2!_A(x1,x2) = 72
            filter_0!_A = 1
            if_0!_A = 1
            if_1!_A(x1) = max{0, x1 - 3}
            le_0!_A = 77
            le_1!_A(x1) = max{76, x1 - 1}
            le_2!_A(x1,x2) = 75
            minus_1!_A(x1) = 2
            minus_2!_A(x1,x2) = 26
            s_0!_A = 1
            s_1!_A(x1) = 75
            |0|_0!_A = 3
            perfectp_1!_A(x1) = max{78, x1 - 1}
            f_4!_A(x1,x2,x3,x4) = max{76, x2 - 15, x3 - 18, x4 - 3}
            map_2!_A(x1,x2) = max{73, x1 + 57}
            nil_0!_A = 56
        
        2. marked-algebra reduction triple (>=A, >=A!, >A!):
        
          max/plus interpretation on natural numbers:
          
            map_2#_A(x1,x2) = max{1, x2 - 90}
            cons_2_A(x1,x2) = max{x1 + 7, x2 + 89}
            app#_A(x1,x2) = max{1, x2 - 83}
            map_1_A(x1) = max{25, x1 + 22}
            filter2_3_A(x1,x2,x3) = max{49, x1 - 25, x2 + 48, x3 + 48}
            filter2_4#_A(x1,x2,x3,x4) = max{1, x4 - 83}
            false_0_A = 91
            filter_2#_A(x1,x2) = max{1, x2 - 90}
            filter_1_A(x1) = 23
            app_A(x1,x2) = max{91, x1 - 24, x2 + 22}
            true_0_A = 0
            f_0_A = 23
            f_1_A(x1) = max{25, x1 - 1}
            f_2_A(x1,x2) = max{23, x1 - 25, x2 - 1}
            filter_0_A = 23
            if_0_A = 23
            if_1_A(x1) = max{23, x1 - 46}
            le_0_A = 23
            le_1_A(x1) = max{23, x1 - 1}
            le_2_A(x1,x2) = max{91, x1 - 92, x2 - 92}
            minus_1_A(x1) = max{25, x1 + 24}
            minus_2_A(x1,x2) = max{2, x1, x2 - 91}
            s_0_A = 40
            s_1_A(x1) = max{91, x1 + 22}
            |0|_0_A = 72
            perfectp_1_A(x1) = max{91, x1 - 95}
            f_4_A(x1,x2,x3,x4) = max{91, x1 - 95, x2 - 95, x3 - 95, x4 - 95}
            map_2_A(x1,x2) = max{23, x1 - 2, x2 + 22}
            nil_0_A = 24
            map_2#!_A(x1,x2) = max{2, x2 - 1}
            cons_2!_A(x1,x2) = max{12, x1 + 11}
            app#!_A(x1,x2) = 1
            map_1!_A(x1) = max{0, x1 - 14}
            filter2_3!_A(x1,x2,x3) = max{11, x1 - 25, x2 - 16, x3 - 16}
            filter2_4#!_A(x1,x2,x3,x4) = max{24, x3 + 5, x4 + 5}
            false_0!_A = 3
            filter_2#!_A(x1,x2) = max{4, x2 - 1}
            filter_1!_A(x1) = 3
            app!_A(x1,x2) = max{0, x1 - 24, x2 - 15}
            true_0!_A = 13
            f_0!_A = 2
            f_1!_A(x1) = max{1, x1 - 1}
            f_2!_A(x1,x2) = max{2, x1 + 1, x2 - 16}
            filter_0!_A = 1
            if_0!_A = 1
            if_1!_A(x1) = max{18, x1 - 16}
            le_0!_A = 1
            le_1!_A(x1) = max{0, x1 - 23}
            le_2!_A(x1,x2) = 14
            minus_1!_A(x1) = max{2, x1 + 1}
            minus_2!_A(x1,x2) = max{0, x1 - 90}
            s_0!_A = 1
            s_1!_A(x1) = max{15, x1 - 74}
            |0|_0!_A = 16
            perfectp_1!_A(x1) = max{18, x1 - 94}
            f_4!_A(x1,x2,x3,x4) = max{17, x1 - 73}
            map_2!_A(x1,x2) = max{0, x1 - 14}
            nil_0!_A = 3
        
  
    partial status:
  
      pi(map_2#) = [1]
      pi(cons_2) = [1]
      pi(app#) = [1]
      pi(map_1) = [1]
      pi(filter2_3) = [2, 3]
      pi(filter2_4#) = [2]
      pi(false_0) = []
      pi(filter_2#) = [1]
      pi(filter_1) = [1]
      pi(app) = [1, 2]
      pi(true_0) = []
      pi(f_0) = []
      pi(f_1) = [1]
      pi(f_2) = [1]
      pi(filter_0) = []
      pi(if_0) = []
      pi(if_1) = [1]
      pi(le_0) = []
      pi(le_1) = []
      pi(le_2) = []
      pi(minus_1) = [1]
      pi(minus_2) = [1]
      pi(s_0) = []
      pi(s_1) = [1]
      pi(|0|_0) = []
      pi(perfectp_1) = [1]
      pi(f_4) = [2, 4]
      pi(map_2) = []
      pi(nil_0) = []

The following rules are removed:

  p1, p2, p3, p4, p5, p6, p7, p8, p9

Then no dependency pair remains.

-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: f_4#(s_1(x),|0|_0(),z,u) -> f_4#(x,u,minus_2(z,s_1(x)),u)
p2: f_4#(s_1(x),s_1(y),z,u) -> f_4#(x,u,z,u)
p3: f_4#(s_1(x),s_1(y),z,u) -> f_4#(s_1(x),minus_2(y,x),z,u)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(f_0(),y) -> f_1(y)
r4: app(f_1(x1),y) -> f_2(x1,y)
r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y)
r6: app(f_3(x1,x2,x3),y) -> f_4(x1,x2,x3,y)
r7: app(filter_0(),y) -> filter_1(y)
r8: app(filter_1(x1),y) -> filter_2(x1,y)
r9: app(filter2_0(),y) -> filter2_1(y)
r10: app(filter2_1(x1),y) -> filter2_2(x1,y)
r11: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r12: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r13: app(if_0(),y) -> if_1(y)
r14: app(if_1(x1),y) -> if_2(x1,y)
r15: app(if_2(x1,x2),y) -> if_3(x1,x2,y)
r16: app(le_0(),y) -> le_1(y)
r17: app(le_1(x1),y) -> le_2(x1,y)
r18: app(map_0(),y) -> map_1(y)
r19: app(map_1(x1),y) -> map_2(x1,y)
r20: app(minus_0(),y) -> minus_1(y)
r21: app(minus_1(x1),y) -> minus_2(x1,y)
r22: app(perfectp_0(),y) -> perfectp_1(y)
r23: app(s_0(),y) -> s_1(y)
r24: minus_2(|0|_0(),y) -> |0|_0()
r25: minus_2(s_1(x),|0|_0()) -> s_1(x)
r26: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r27: le_2(|0|_0(),y) -> true_0()
r28: le_2(s_1(x),|0|_0()) -> false_0()
r29: le_2(s_1(x),s_1(y)) -> le_2(x,y)
r30: if_3(true_0(),x,y) -> x
r31: if_3(false_0(),x,y) -> y
r32: perfectp_1(|0|_0()) -> false_0()
r33: perfectp_1(s_1(x)) -> f_4(x,s_1(|0|_0()),s_1(x),s_1(x))
r34: f_4(|0|_0(),y,|0|_0(),u) -> true_0()
r35: f_4(|0|_0(),y,s_1(z),u) -> false_0()
r36: f_4(s_1(x),|0|_0(),z,u) -> f_4(x,u,minus_2(z,s_1(x)),u)
r37: f_4(s_1(x),s_1(y),z,u) -> if_3(le_2(x,y),f_4(s_1(x),minus_2(y,x),z,u),f_4(x,u,z,u))
r38: map_2(|fun|,nil_0()) -> nil_0()
r39: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs))
r40: filter_2(|fun|,nil_0()) -> nil_0()
r41: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs)
r42: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs))
r43: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs)

The set of usable rules consists of

  r24, r25, r26

Take the reduction pair:

  generalized weighted path order (>=MG, >G)
  
    base order 1:
  
      trivial reduction triple (T x T, T x T, Φ)
  
    base order 2:
  
      lexicographic combination of reduction triples:
      
        1. marked-algebra reduction triple (>=A, >=A!, >A!):
        
          max/plus interpretation on natural numbers:
          
            f_4#_A(x1,x2,x3,x4) = max{0, x1 - 59, x2 - 74, x3 - 38, x4 - 40}
            s_1_A(x1) = max{21, x1 + 11}
            |0|_0_A = 19
            minus_2_A(x1,x2) = max{37, x1, x2 - 22}
            f_4#!_A(x1,x2,x3,x4) = max{38, x1 - 1, x3}
            s_1!_A(x1) = 7
            |0|_0!_A = 6
            minus_2!_A(x1,x2) = max{9, x1 - 22, x2 - 284}
        
        2. marked-algebra reduction triple (>=A, >=A!, >A!):
        
          max/plus interpretation on natural numbers:
          
            f_4#_A(x1,x2,x3,x4) = max{0, x1 - 34, x2 - 19, x3 - 17, x4 - 19}
            s_1_A(x1) = x1 + 16
            |0|_0_A = 16
            minus_2_A(x1,x2) = max{16, x1, x2 - 17}
            f_4#!_A(x1,x2,x3,x4) = max{8, x1 - 7}
            s_1!_A(x1) = max{7, x1 - 60}
            |0|_0!_A = 7
            minus_2!_A(x1,x2) = max{7, x1 - 23, x2 - 60}
        
  
    partial status:
  
      pi(f_4#) = [3]
      pi(s_1) = [1]
      pi(|0|_0) = []
      pi(minus_2) = [1]

The following rules are removed:

  p1, p2



-- SCC decomposition.

Consider the dependency pair problem (P, R), where P consists of

p1: f_4#(s_1(x),s_1(y),z,u) -> f_4#(s_1(x),minus_2(y,x),z,u)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(f_0(),y) -> f_1(y)
r4: app(f_1(x1),y) -> f_2(x1,y)
r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y)
r6: app(f_3(x1,x2,x3),y) -> f_4(x1,x2,x3,y)
r7: app(filter_0(),y) -> filter_1(y)
r8: app(filter_1(x1),y) -> filter_2(x1,y)
r9: app(filter2_0(),y) -> filter2_1(y)
r10: app(filter2_1(x1),y) -> filter2_2(x1,y)
r11: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r12: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r13: app(if_0(),y) -> if_1(y)
r14: app(if_1(x1),y) -> if_2(x1,y)
r15: app(if_2(x1,x2),y) -> if_3(x1,x2,y)
r16: app(le_0(),y) -> le_1(y)
r17: app(le_1(x1),y) -> le_2(x1,y)
r18: app(map_0(),y) -> map_1(y)
r19: app(map_1(x1),y) -> map_2(x1,y)
r20: app(minus_0(),y) -> minus_1(y)
r21: app(minus_1(x1),y) -> minus_2(x1,y)
r22: app(perfectp_0(),y) -> perfectp_1(y)
r23: app(s_0(),y) -> s_1(y)
r24: minus_2(|0|_0(),y) -> |0|_0()
r25: minus_2(s_1(x),|0|_0()) -> s_1(x)
r26: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r27: le_2(|0|_0(),y) -> true_0()
r28: le_2(s_1(x),|0|_0()) -> false_0()
r29: le_2(s_1(x),s_1(y)) -> le_2(x,y)
r30: if_3(true_0(),x,y) -> x
r31: if_3(false_0(),x,y) -> y
r32: perfectp_1(|0|_0()) -> false_0()
r33: perfectp_1(s_1(x)) -> f_4(x,s_1(|0|_0()),s_1(x),s_1(x))
r34: f_4(|0|_0(),y,|0|_0(),u) -> true_0()
r35: f_4(|0|_0(),y,s_1(z),u) -> false_0()
r36: f_4(s_1(x),|0|_0(),z,u) -> f_4(x,u,minus_2(z,s_1(x)),u)
r37: f_4(s_1(x),s_1(y),z,u) -> if_3(le_2(x,y),f_4(s_1(x),minus_2(y,x),z,u),f_4(x,u,z,u))
r38: map_2(|fun|,nil_0()) -> nil_0()
r39: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs))
r40: filter_2(|fun|,nil_0()) -> nil_0()
r41: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs)
r42: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs))
r43: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs)

The estimated dependency graph contains the following SCCs:

  {p1}


-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: f_4#(s_1(x),s_1(y),z,u) -> f_4#(s_1(x),minus_2(y,x),z,u)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(f_0(),y) -> f_1(y)
r4: app(f_1(x1),y) -> f_2(x1,y)
r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y)
r6: app(f_3(x1,x2,x3),y) -> f_4(x1,x2,x3,y)
r7: app(filter_0(),y) -> filter_1(y)
r8: app(filter_1(x1),y) -> filter_2(x1,y)
r9: app(filter2_0(),y) -> filter2_1(y)
r10: app(filter2_1(x1),y) -> filter2_2(x1,y)
r11: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r12: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r13: app(if_0(),y) -> if_1(y)
r14: app(if_1(x1),y) -> if_2(x1,y)
r15: app(if_2(x1,x2),y) -> if_3(x1,x2,y)
r16: app(le_0(),y) -> le_1(y)
r17: app(le_1(x1),y) -> le_2(x1,y)
r18: app(map_0(),y) -> map_1(y)
r19: app(map_1(x1),y) -> map_2(x1,y)
r20: app(minus_0(),y) -> minus_1(y)
r21: app(minus_1(x1),y) -> minus_2(x1,y)
r22: app(perfectp_0(),y) -> perfectp_1(y)
r23: app(s_0(),y) -> s_1(y)
r24: minus_2(|0|_0(),y) -> |0|_0()
r25: minus_2(s_1(x),|0|_0()) -> s_1(x)
r26: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r27: le_2(|0|_0(),y) -> true_0()
r28: le_2(s_1(x),|0|_0()) -> false_0()
r29: le_2(s_1(x),s_1(y)) -> le_2(x,y)
r30: if_3(true_0(),x,y) -> x
r31: if_3(false_0(),x,y) -> y
r32: perfectp_1(|0|_0()) -> false_0()
r33: perfectp_1(s_1(x)) -> f_4(x,s_1(|0|_0()),s_1(x),s_1(x))
r34: f_4(|0|_0(),y,|0|_0(),u) -> true_0()
r35: f_4(|0|_0(),y,s_1(z),u) -> false_0()
r36: f_4(s_1(x),|0|_0(),z,u) -> f_4(x,u,minus_2(z,s_1(x)),u)
r37: f_4(s_1(x),s_1(y),z,u) -> if_3(le_2(x,y),f_4(s_1(x),minus_2(y,x),z,u),f_4(x,u,z,u))
r38: map_2(|fun|,nil_0()) -> nil_0()
r39: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs))
r40: filter_2(|fun|,nil_0()) -> nil_0()
r41: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs)
r42: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs))
r43: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs)

The set of usable rules consists of

  r24, r25, r26

Take the reduction pair:

  generalized weighted path order (>=MG, >G)
  
    base order 1:
  
      trivial reduction triple (T x T, T x T, Φ)
  
    base order 2:
  
      lexicographic combination of reduction triples:
      
        1. marked-algebra reduction triple (>=A, >=A!, >A!):
        
          max/plus interpretation on natural numbers:
          
            f_4#_A(x1,x2,x3,x4) = max{0, x1 - 4, x2 - 63, x3 - 2, x4 - 2}
            s_1_A(x1) = x1 + 2
            minus_2_A(x1,x2) = max{62, x1 + 2, x2 - 6}
            |0|_0_A = 5
            f_4#!_A(x1,x2,x3,x4) = 0
            s_1!_A(x1) = max{11, x1 - 23}
            minus_2!_A(x1,x2) = max{10, x1 - 48}
            |0|_0!_A = 8
        
        2. marked-algebra reduction triple (>=A, >=A!, >A!):
        
          max/plus interpretation on natural numbers:
          
            f_4#_A(x1,x2,x3,x4) = max{0, x1 - 25, x2 - 30, x3 - 2, x4 - 2}
            s_1_A(x1) = max{23, x1}
            minus_2_A(x1,x2) = max{29, x1, x2 - 2}
            |0|_0_A = 1
            f_4#!_A(x1,x2,x3,x4) = x4 + 1
            s_1!_A(x1) = max{23, x1 - 8}
            minus_2!_A(x1,x2) = max{18, x1 - 24, x2 - 6}
            |0|_0!_A = 18
        
  
    partial status:
  
      pi(f_4#) = [2]
      pi(s_1) = [1]
      pi(minus_2) = [1]
      pi(|0|_0) = []

The following rules are removed:

  p1

Then no dependency pair remains.

-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: le_2#(s_1(x),s_1(y)) -> le_2#(x,y)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(f_0(),y) -> f_1(y)
r4: app(f_1(x1),y) -> f_2(x1,y)
r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y)
r6: app(f_3(x1,x2,x3),y) -> f_4(x1,x2,x3,y)
r7: app(filter_0(),y) -> filter_1(y)
r8: app(filter_1(x1),y) -> filter_2(x1,y)
r9: app(filter2_0(),y) -> filter2_1(y)
r10: app(filter2_1(x1),y) -> filter2_2(x1,y)
r11: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r12: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r13: app(if_0(),y) -> if_1(y)
r14: app(if_1(x1),y) -> if_2(x1,y)
r15: app(if_2(x1,x2),y) -> if_3(x1,x2,y)
r16: app(le_0(),y) -> le_1(y)
r17: app(le_1(x1),y) -> le_2(x1,y)
r18: app(map_0(),y) -> map_1(y)
r19: app(map_1(x1),y) -> map_2(x1,y)
r20: app(minus_0(),y) -> minus_1(y)
r21: app(minus_1(x1),y) -> minus_2(x1,y)
r22: app(perfectp_0(),y) -> perfectp_1(y)
r23: app(s_0(),y) -> s_1(y)
r24: minus_2(|0|_0(),y) -> |0|_0()
r25: minus_2(s_1(x),|0|_0()) -> s_1(x)
r26: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r27: le_2(|0|_0(),y) -> true_0()
r28: le_2(s_1(x),|0|_0()) -> false_0()
r29: le_2(s_1(x),s_1(y)) -> le_2(x,y)
r30: if_3(true_0(),x,y) -> x
r31: if_3(false_0(),x,y) -> y
r32: perfectp_1(|0|_0()) -> false_0()
r33: perfectp_1(s_1(x)) -> f_4(x,s_1(|0|_0()),s_1(x),s_1(x))
r34: f_4(|0|_0(),y,|0|_0(),u) -> true_0()
r35: f_4(|0|_0(),y,s_1(z),u) -> false_0()
r36: f_4(s_1(x),|0|_0(),z,u) -> f_4(x,u,minus_2(z,s_1(x)),u)
r37: f_4(s_1(x),s_1(y),z,u) -> if_3(le_2(x,y),f_4(s_1(x),minus_2(y,x),z,u),f_4(x,u,z,u))
r38: map_2(|fun|,nil_0()) -> nil_0()
r39: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs))
r40: filter_2(|fun|,nil_0()) -> nil_0()
r41: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs)
r42: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs))
r43: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs)

The set of usable rules consists of

  r24

Take the reduction pair:

  generalized weighted path order (>=MG, >G)
  
    base order 1:
  
      trivial reduction triple (T x T, T x T, Φ)
  
    base order 2:
  
      lexicographic combination of reduction triples:
      
        1. marked-algebra reduction triple (>=A, >=A!, >A!):
        
          max/plus interpretation on natural numbers:
          
            le_2#_A(x1,x2) = max{0, x1 - 11, x2 - 11}
            s_1_A(x1) = x1 + 10
            minus_2_A(x1,x2) = max{23, x1 - 11, x2 - 21}
            |0|_0_A = 1
            le_2#!_A(x1,x2) = max{9, x1 - 11, x2 - 11}
            s_1!_A(x1) = max{8, x1 - 85}
            minus_2!_A(x1,x2) = max{8, x1 - 11, x2 - 71}
            |0|_0!_A = 7
        
        2. marked-algebra reduction triple (>=A, >=A!, >A!):
        
          max/plus interpretation on natural numbers:
          
            le_2#_A(x1,x2) = max{0, x1 - 9, x2 - 9}
            s_1_A(x1) = max{16, x1 + 8}
            minus_2_A(x1,x2) = max{26, x1 - 17, x2 - 10}
            |0|_0_A = 9
            le_2#!_A(x1,x2) = max{11, x1 - 17, x2 - 131}
            s_1!_A(x1) = max{10, x1 - 130}
            minus_2!_A(x1,x2) = max{10, x1 - 95, x2 - 117}
            |0|_0!_A = 9
        
  
    partial status:
  
      pi(le_2#) = [2]
      pi(s_1) = [1]
      pi(minus_2) = [1]
      pi(|0|_0) = []

The following rules are removed:

  p1

Then no dependency pair remains.

-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: minus_2#(s_1(x),s_1(y)) -> minus_2#(x,y)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(f_0(),y) -> f_1(y)
r4: app(f_1(x1),y) -> f_2(x1,y)
r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y)
r6: app(f_3(x1,x2,x3),y) -> f_4(x1,x2,x3,y)
r7: app(filter_0(),y) -> filter_1(y)
r8: app(filter_1(x1),y) -> filter_2(x1,y)
r9: app(filter2_0(),y) -> filter2_1(y)
r10: app(filter2_1(x1),y) -> filter2_2(x1,y)
r11: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r12: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r13: app(if_0(),y) -> if_1(y)
r14: app(if_1(x1),y) -> if_2(x1,y)
r15: app(if_2(x1,x2),y) -> if_3(x1,x2,y)
r16: app(le_0(),y) -> le_1(y)
r17: app(le_1(x1),y) -> le_2(x1,y)
r18: app(map_0(),y) -> map_1(y)
r19: app(map_1(x1),y) -> map_2(x1,y)
r20: app(minus_0(),y) -> minus_1(y)
r21: app(minus_1(x1),y) -> minus_2(x1,y)
r22: app(perfectp_0(),y) -> perfectp_1(y)
r23: app(s_0(),y) -> s_1(y)
r24: minus_2(|0|_0(),y) -> |0|_0()
r25: minus_2(s_1(x),|0|_0()) -> s_1(x)
r26: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r27: le_2(|0|_0(),y) -> true_0()
r28: le_2(s_1(x),|0|_0()) -> false_0()
r29: le_2(s_1(x),s_1(y)) -> le_2(x,y)
r30: if_3(true_0(),x,y) -> x
r31: if_3(false_0(),x,y) -> y
r32: perfectp_1(|0|_0()) -> false_0()
r33: perfectp_1(s_1(x)) -> f_4(x,s_1(|0|_0()),s_1(x),s_1(x))
r34: f_4(|0|_0(),y,|0|_0(),u) -> true_0()
r35: f_4(|0|_0(),y,s_1(z),u) -> false_0()
r36: f_4(s_1(x),|0|_0(),z,u) -> f_4(x,u,minus_2(z,s_1(x)),u)
r37: f_4(s_1(x),s_1(y),z,u) -> if_3(le_2(x,y),f_4(s_1(x),minus_2(y,x),z,u),f_4(x,u,z,u))
r38: map_2(|fun|,nil_0()) -> nil_0()
r39: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs))
r40: filter_2(|fun|,nil_0()) -> nil_0()
r41: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs)
r42: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs))
r43: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs)

The set of usable rules consists of

  r24

Take the reduction pair:

  generalized weighted path order (>=MG, >G)
  
    base order 1:
  
      trivial reduction triple (T x T, T x T, Φ)
  
    base order 2:
  
      lexicographic combination of reduction triples:
      
        1. marked-algebra reduction triple (>=A, >=A!, >A!):
        
          max/plus interpretation on natural numbers:
          
            minus_2#_A(x1,x2) = max{0, x1 - 5, x2 - 5}
            s_1_A(x1) = max{11, x1 + 4}
            minus_2_A(x1,x2) = max{21, x1 - 12, x2 - 5}
            |0|_0_A = 4
            minus_2#!_A(x1,x2) = max{13, x1 - 103, x2 - 103}
            s_1!_A(x1) = max{12, x1 - 102}
            minus_2!_A(x1,x2) = max{11, x1 - 12, x2 - 45}
            |0|_0!_A = 5
        
        2. marked-algebra reduction triple (>=A, >=A!, >A!):
        
          max/plus interpretation on natural numbers:
          
            minus_2#_A(x1,x2) = max{0, x1 - 26, x2 - 26}
            s_1_A(x1) = max{52, x1 + 25}
            minus_2_A(x1,x2) = max{62, x1 - 53, x2 - 46}
            |0|_0_A = 45
            minus_2#!_A(x1,x2) = max{11, x2 - 179}
            s_1!_A(x1) = max{10, x1 - 179}
            minus_2!_A(x1,x2) = max{11, x1 - 53, x2 - 113}
            |0|_0!_A = 8
        
  
    partial status:
  
      pi(minus_2#) = [2]
      pi(s_1) = [1]
      pi(minus_2) = [1]
      pi(|0|_0) = []

The following rules are removed:

  p1

Then no dependency pair remains.