YES We show the termination of the TRS R: app(app(plus(),|0|()),y) -> y app(app(plus(),app(s(),x)),y) -> app(s(),app(app(plus(),x),y)) app(app(map(),f),nil()) -> nil() app(app(map(),f),app(app(cons(),x),xs)) -> app(app(cons(),app(f,x)),app(app(map(),f),xs)) app(app(app(curry(),g),x),y) -> app(app(g,x),y) inc() -> app(map(),app(app(curry(),plus()),app(s(),|0|()))) Instead we prove termination of the uncurried system: app(cons_0(),y) -> cons_1(y) app(cons_1(x1),y) -> cons_2(x1,y) app(curry_0(),y) -> curry_1(y) app(curry_1(x1),y) -> curry_2(x1,y) app(curry_2(x1,x2),y) -> curry_3(x1,x2,y) app(map_0(),y) -> map_1(y) app(map_1(x1),y) -> map_2(x1,y) app(plus_0(),y) -> plus_1(y) app(plus_1(x1),y) -> plus_2(x1,y) app(s_0(),y) -> s_1(y) plus_2(|0|_0(),y) -> y plus_2(s_1(x),y) -> s_1(plus_2(x,y)) map_2(f,nil_0()) -> nil_0() map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) curry_3(g,x,y) -> app(app(g,x),y) inc_0() -> map_1(curry_2(plus_0(),s_1(|0|_0()))) -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: app#(curry_2(x1,x2),y) -> curry_3#(x1,x2,y) p2: app#(map_1(x1),y) -> map_2#(x1,y) p3: app#(plus_1(x1),y) -> plus_2#(x1,y) p4: plus_2#(s_1(x),y) -> plus_2#(x,y) p5: map_2#(f,cons_2(x,xs)) -> app#(f,x) p6: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) p7: curry_3#(g,x,y) -> app#(app(g,x),y) p8: curry_3#(g,x,y) -> app#(g,x) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(curry_0(),y) -> curry_1(y) r4: app(curry_1(x1),y) -> curry_2(x1,y) r5: app(curry_2(x1,x2),y) -> curry_3(x1,x2,y) r6: app(map_0(),y) -> map_1(y) r7: app(map_1(x1),y) -> map_2(x1,y) r8: app(plus_0(),y) -> plus_1(y) r9: app(plus_1(x1),y) -> plus_2(x1,y) r10: app(s_0(),y) -> s_1(y) r11: plus_2(|0|_0(),y) -> y r12: plus_2(s_1(x),y) -> s_1(plus_2(x,y)) r13: map_2(f,nil_0()) -> nil_0() r14: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r15: curry_3(g,x,y) -> app(app(g,x),y) r16: inc_0() -> map_1(curry_2(plus_0(),s_1(|0|_0()))) The estimated dependency graph contains the following SCCs: {p1, p2, p5, p6, p7, p8} {p4} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: app#(curry_2(x1,x2),y) -> curry_3#(x1,x2,y) p2: curry_3#(g,x,y) -> app#(g,x) p3: app#(map_1(x1),y) -> map_2#(x1,y) p4: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) p5: map_2#(f,cons_2(x,xs)) -> app#(f,x) p6: curry_3#(g,x,y) -> app#(app(g,x),y) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(curry_0(),y) -> curry_1(y) r4: app(curry_1(x1),y) -> curry_2(x1,y) r5: app(curry_2(x1,x2),y) -> curry_3(x1,x2,y) r6: app(map_0(),y) -> map_1(y) r7: app(map_1(x1),y) -> map_2(x1,y) r8: app(plus_0(),y) -> plus_1(y) r9: app(plus_1(x1),y) -> plus_2(x1,y) r10: app(s_0(),y) -> s_1(y) r11: plus_2(|0|_0(),y) -> y r12: plus_2(s_1(x),y) -> s_1(plus_2(x,y)) r13: map_2(f,nil_0()) -> nil_0() r14: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r15: curry_3(g,x,y) -> app(app(g,x),y) r16: inc_0() -> map_1(curry_2(plus_0(),s_1(|0|_0()))) The set of usable rules consists of r1, r2, r3, r4, r5, r6, r7, r8, r9, r10, r11, r12, r13, r14, r15, r16 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: app#_A(x1,x2) = x1 + 2 curry_2_A(x1,x2) = x1 + x2 + 6 curry_3#_A(x1,x2,x3) = x1 + x2 + 5 map_1_A(x1) = x1 + 4 map_2#_A(x1,x2) = x1 + 3 cons_2_A(x1,x2) = x1 + 1 app_A(x1,x2) = x1 + x2 + 2 cons_0_A() = 1 cons_1_A(x1) = x1 + 2 curry_0_A() = 4 curry_1_A(x1) = x1 + 5 curry_3_A(x1,x2,x3) = x1 + x2 + x3 + 7 map_0_A() = 3 map_2_A(x1,x2) = x1 + x2 + 5 plus_0_A() = 1 plus_1_A(x1) = x1 + 2 plus_2_A(x1,x2) = x2 + 3 s_0_A() = 2 s_1_A(x1) = 1 |0|_0_A() = 1 nil_0_A() = 1 inc_0_A() = 13 base order 2: precedence: curry_3# > app# = curry_3 = map_2 = plus_2 > map_2# = app = s_0 = nil_0 = inc_0 > curry_2 = map_1 = cons_2 = plus_1 = s_1 = |0|_0 > cons_1 = curry_1 = map_0 = plus_0 > cons_0 = curry_0 partial status: pi(app#) = [] pi(curry_2) = [2] pi(curry_3#) = [2] pi(map_1) = [1] pi(map_2#) = [1] pi(cons_2) = [1] pi(app) = [] pi(cons_0) = [] pi(cons_1) = [1] pi(curry_0) = [] pi(curry_1) = [1] pi(curry_3) = [3] pi(map_0) = [] pi(map_2) = [] pi(plus_0) = [] pi(plus_1) = [] pi(plus_2) = [2] pi(s_0) = [] pi(s_1) = [] pi(|0|_0) = [] pi(nil_0) = [] pi(inc_0) = [] The following rules are removed: p1 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: curry_3#(g,x,y) -> app#(g,x) p2: app#(map_1(x1),y) -> map_2#(x1,y) p3: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) p4: map_2#(f,cons_2(x,xs)) -> app#(f,x) p5: curry_3#(g,x,y) -> app#(app(g,x),y) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(curry_0(),y) -> curry_1(y) r4: app(curry_1(x1),y) -> curry_2(x1,y) r5: app(curry_2(x1,x2),y) -> curry_3(x1,x2,y) r6: app(map_0(),y) -> map_1(y) r7: app(map_1(x1),y) -> map_2(x1,y) r8: app(plus_0(),y) -> plus_1(y) r9: app(plus_1(x1),y) -> plus_2(x1,y) r10: app(s_0(),y) -> s_1(y) r11: plus_2(|0|_0(),y) -> y r12: plus_2(s_1(x),y) -> s_1(plus_2(x,y)) r13: map_2(f,nil_0()) -> nil_0() r14: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r15: curry_3(g,x,y) -> app(app(g,x),y) r16: inc_0() -> map_1(curry_2(plus_0(),s_1(|0|_0()))) The estimated dependency graph contains the following SCCs: {p2, p3, p4} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: app#(map_1(x1),y) -> map_2#(x1,y) p2: map_2#(f,cons_2(x,xs)) -> app#(f,x) p3: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(curry_0(),y) -> curry_1(y) r4: app(curry_1(x1),y) -> curry_2(x1,y) r5: app(curry_2(x1,x2),y) -> curry_3(x1,x2,y) r6: app(map_0(),y) -> map_1(y) r7: app(map_1(x1),y) -> map_2(x1,y) r8: app(plus_0(),y) -> plus_1(y) r9: app(plus_1(x1),y) -> plus_2(x1,y) r10: app(s_0(),y) -> s_1(y) r11: plus_2(|0|_0(),y) -> y r12: plus_2(s_1(x),y) -> s_1(plus_2(x,y)) r13: map_2(f,nil_0()) -> nil_0() r14: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r15: curry_3(g,x,y) -> app(app(g,x),y) r16: inc_0() -> map_1(curry_2(plus_0(),s_1(|0|_0()))) The set of usable rules consists of r3, r12, r16 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: app#_A(x1,x2) = x2 + 3 map_1_A(x1) = 3 map_2#_A(x1,x2) = x2 + 2 cons_2_A(x1,x2) = x1 + x2 + 2 app_A(x1,x2) = 0 curry_0_A() = 1 curry_1_A(x1) = 0 plus_2_A(x1,x2) = 2 s_1_A(x1) = 1 inc_0_A() = 5 curry_2_A(x1,x2) = 2 plus_0_A() = 4 |0|_0_A() = 1 base order 2: precedence: curry_0 = inc_0 > curry_2 = plus_0 = |0|_0 > app# = plus_2 > cons_2 = s_1 > map_2# = app > map_1 = curry_1 partial status: pi(app#) = [2] pi(map_1) = [] pi(map_2#) = [] pi(cons_2) = [] pi(app) = [] pi(curry_0) = [] pi(curry_1) = [] pi(plus_2) = [] pi(s_1) = [] pi(inc_0) = [] pi(curry_2) = [] pi(plus_0) = [] pi(|0|_0) = [] The following rules are removed: p3 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: app#(map_1(x1),y) -> map_2#(x1,y) p2: map_2#(f,cons_2(x,xs)) -> app#(f,x) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(curry_0(),y) -> curry_1(y) r4: app(curry_1(x1),y) -> curry_2(x1,y) r5: app(curry_2(x1,x2),y) -> curry_3(x1,x2,y) r6: app(map_0(),y) -> map_1(y) r7: app(map_1(x1),y) -> map_2(x1,y) r8: app(plus_0(),y) -> plus_1(y) r9: app(plus_1(x1),y) -> plus_2(x1,y) r10: app(s_0(),y) -> s_1(y) r11: plus_2(|0|_0(),y) -> y r12: plus_2(s_1(x),y) -> s_1(plus_2(x,y)) r13: map_2(f,nil_0()) -> nil_0() r14: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r15: curry_3(g,x,y) -> app(app(g,x),y) r16: inc_0() -> map_1(curry_2(plus_0(),s_1(|0|_0()))) The estimated dependency graph contains the following SCCs: {p1, p2} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: app#(map_1(x1),y) -> map_2#(x1,y) p2: map_2#(f,cons_2(x,xs)) -> app#(f,x) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(curry_0(),y) -> curry_1(y) r4: app(curry_1(x1),y) -> curry_2(x1,y) r5: app(curry_2(x1,x2),y) -> curry_3(x1,x2,y) r6: app(map_0(),y) -> map_1(y) r7: app(map_1(x1),y) -> map_2(x1,y) r8: app(plus_0(),y) -> plus_1(y) r9: app(plus_1(x1),y) -> plus_2(x1,y) r10: app(s_0(),y) -> s_1(y) r11: plus_2(|0|_0(),y) -> y r12: plus_2(s_1(x),y) -> s_1(plus_2(x,y)) r13: map_2(f,nil_0()) -> nil_0() r14: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r15: curry_3(g,x,y) -> app(app(g,x),y) r16: inc_0() -> map_1(curry_2(plus_0(),s_1(|0|_0()))) The set of usable rules consists of r1, r2, r3, r4, r6, r8, r10, r12, r16 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: app#_A(x1,x2) = x2 + 3 map_1_A(x1) = 1 map_2#_A(x1,x2) = x2 + 2 cons_2_A(x1,x2) = x1 + x2 + 4 app_A(x1,x2) = x1 + x2 + 5 cons_0_A() = 1 cons_1_A(x1) = x1 + 2 curry_0_A() = 4 curry_1_A(x1) = x1 + 3 curry_2_A(x1,x2) = 2 map_0_A() = 2 plus_0_A() = 1 plus_1_A(x1) = x1 + 3 s_0_A() = 2 s_1_A(x1) = 1 plus_2_A(x1,x2) = 2 inc_0_A() = 3 |0|_0_A() = 4 base order 2: precedence: map_2# = map_0 = inc_0 > map_1 = |0|_0 > app = s_0 > cons_2 = curry_1 = s_1 > app# = cons_1 = curry_0 = curry_2 = plus_1 = plus_2 > cons_0 = plus_0 partial status: pi(app#) = [2] pi(map_1) = [] pi(map_2#) = [2] pi(cons_2) = [] pi(app) = [2] pi(cons_0) = [] pi(cons_1) = [1] pi(curry_0) = [] pi(curry_1) = [1] pi(curry_2) = [] pi(map_0) = [] pi(plus_0) = [] pi(plus_1) = [1] pi(s_0) = [] pi(s_1) = [] pi(plus_2) = [] pi(inc_0) = [] pi(|0|_0) = [] The following rules are removed: p1 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(f,cons_2(x,xs)) -> app#(f,x) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(curry_0(),y) -> curry_1(y) r4: app(curry_1(x1),y) -> curry_2(x1,y) r5: app(curry_2(x1,x2),y) -> curry_3(x1,x2,y) r6: app(map_0(),y) -> map_1(y) r7: app(map_1(x1),y) -> map_2(x1,y) r8: app(plus_0(),y) -> plus_1(y) r9: app(plus_1(x1),y) -> plus_2(x1,y) r10: app(s_0(),y) -> s_1(y) r11: plus_2(|0|_0(),y) -> y r12: plus_2(s_1(x),y) -> s_1(plus_2(x,y)) r13: map_2(f,nil_0()) -> nil_0() r14: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r15: curry_3(g,x,y) -> app(app(g,x),y) r16: inc_0() -> map_1(curry_2(plus_0(),s_1(|0|_0()))) The estimated dependency graph contains the following SCCs: (no SCCs) -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: plus_2#(s_1(x),y) -> plus_2#(x,y) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(curry_0(),y) -> curry_1(y) r4: app(curry_1(x1),y) -> curry_2(x1,y) r5: app(curry_2(x1,x2),y) -> curry_3(x1,x2,y) r6: app(map_0(),y) -> map_1(y) r7: app(map_1(x1),y) -> map_2(x1,y) r8: app(plus_0(),y) -> plus_1(y) r9: app(plus_1(x1),y) -> plus_2(x1,y) r10: app(s_0(),y) -> s_1(y) r11: plus_2(|0|_0(),y) -> y r12: plus_2(s_1(x),y) -> s_1(plus_2(x,y)) r13: map_2(f,nil_0()) -> nil_0() r14: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r15: curry_3(g,x,y) -> app(app(g,x),y) r16: inc_0() -> map_1(curry_2(plus_0(),s_1(|0|_0()))) The set of usable rules consists of r1, r3, r4, r8, r16 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: plus_2#_A(x1,x2) = x1 s_1_A(x1) = x1 app_A(x1,x2) = 4 cons_0_A() = 2 cons_1_A(x1) = 1 curry_0_A() = 4 curry_1_A(x1) = 3 curry_2_A(x1,x2) = 2 plus_0_A() = 2 plus_1_A(x1) = 1 inc_0_A() = 8 map_1_A(x1) = x1 + 5 |0|_0_A() = 1 base order 2: precedence: inc_0 > plus_0 = |0|_0 > s_1 = plus_1 > plus_2# > app = cons_0 = curry_0 > cons_1 = curry_1 = map_1 > curry_2 partial status: pi(plus_2#) = [1] pi(s_1) = [1] pi(app) = [] pi(cons_0) = [] pi(cons_1) = [] pi(curry_0) = [] pi(curry_1) = [] pi(curry_2) = [] pi(plus_0) = [] pi(plus_1) = [] pi(inc_0) = [] pi(map_1) = [] pi(|0|_0) = [] The following rules are removed: p1 Then no dependency pair remains.