YES We show the termination of the TRS R: app(app(map(),f),nil()) -> nil() app(app(map(),f),app(app(cons(),x),xs)) -> app(app(cons(),app(f,x)),app(app(map(),f),xs)) app(sum(),app(app(cons(),x),xs)) -> app(app(plus(),x),app(sum(),xs)) app(size(),app(app(node(),x),xs)) -> app(s(),app(sum(),app(app(map(),size()),xs))) app(app(plus(),|0|()),x) -> |0|() app(app(plus(),app(s(),x)),y) -> app(s(),app(app(plus(),x),y)) Instead we prove termination of the uncurried system: app(cons_0(),y) -> cons_1(y) app(cons_1(x1),y) -> cons_2(x1,y) app(map_0(),y) -> map_1(y) app(map_1(x1),y) -> map_2(x1,y) app(node_0(),y) -> node_1(y) app(node_1(x1),y) -> node_2(x1,y) app(plus_0(),y) -> plus_1(y) app(plus_1(x1),y) -> plus_2(x1,y) app(s_0(),y) -> s_1(y) app(size_0(),y) -> size_1(y) app(sum_0(),y) -> sum_1(y) map_2(f,nil_0()) -> nil_0() map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) sum_1(cons_2(x,xs)) -> plus_2(x,sum_1(xs)) size_1(node_2(x,xs)) -> s_1(sum_1(map_2(size_0(),xs))) plus_2(|0|_0(),x) -> |0|_0() plus_2(s_1(x),y) -> s_1(plus_2(x,y)) -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: app#(map_1(x1),y) -> map_2#(x1,y) p2: app#(plus_1(x1),y) -> plus_2#(x1,y) p3: app#(size_0(),y) -> size_1#(y) p4: app#(sum_0(),y) -> sum_1#(y) p5: map_2#(f,cons_2(x,xs)) -> app#(f,x) p6: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) p7: sum_1#(cons_2(x,xs)) -> plus_2#(x,sum_1(xs)) p8: sum_1#(cons_2(x,xs)) -> sum_1#(xs) p9: size_1#(node_2(x,xs)) -> sum_1#(map_2(size_0(),xs)) p10: size_1#(node_2(x,xs)) -> map_2#(size_0(),xs) p11: plus_2#(s_1(x),y) -> plus_2#(x,y) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(map_0(),y) -> map_1(y) r4: app(map_1(x1),y) -> map_2(x1,y) r5: app(node_0(),y) -> node_1(y) r6: app(node_1(x1),y) -> node_2(x1,y) r7: app(plus_0(),y) -> plus_1(y) r8: app(plus_1(x1),y) -> plus_2(x1,y) r9: app(s_0(),y) -> s_1(y) r10: app(size_0(),y) -> size_1(y) r11: app(sum_0(),y) -> sum_1(y) r12: map_2(f,nil_0()) -> nil_0() r13: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r14: sum_1(cons_2(x,xs)) -> plus_2(x,sum_1(xs)) r15: size_1(node_2(x,xs)) -> s_1(sum_1(map_2(size_0(),xs))) r16: plus_2(|0|_0(),x) -> |0|_0() r17: plus_2(s_1(x),y) -> s_1(plus_2(x,y)) The estimated dependency graph contains the following SCCs: {p1, p3, p5, p6, p10} {p8} {p11} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: app#(map_1(x1),y) -> map_2#(x1,y) p2: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) p3: map_2#(f,cons_2(x,xs)) -> app#(f,x) p4: app#(size_0(),y) -> size_1#(y) p5: size_1#(node_2(x,xs)) -> map_2#(size_0(),xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(map_0(),y) -> map_1(y) r4: app(map_1(x1),y) -> map_2(x1,y) r5: app(node_0(),y) -> node_1(y) r6: app(node_1(x1),y) -> node_2(x1,y) r7: app(plus_0(),y) -> plus_1(y) r8: app(plus_1(x1),y) -> plus_2(x1,y) r9: app(s_0(),y) -> s_1(y) r10: app(size_0(),y) -> size_1(y) r11: app(sum_0(),y) -> sum_1(y) r12: map_2(f,nil_0()) -> nil_0() r13: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r14: sum_1(cons_2(x,xs)) -> plus_2(x,sum_1(xs)) r15: size_1(node_2(x,xs)) -> s_1(sum_1(map_2(size_0(),xs))) r16: plus_2(|0|_0(),x) -> |0|_0() r17: plus_2(s_1(x),y) -> s_1(plus_2(x,y)) The set of usable rules consists of r16, r17 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: app#_A(x1,x2) = x2 + 4 map_1_A(x1) = 1 map_2#_A(x1,x2) = x2 + 2 cons_2_A(x1,x2) = x1 + x2 + 6 size_0_A() = 2 size_1#_A(x1) = x1 + 3 node_2_A(x1,x2) = x2 + 12 plus_2_A(x1,x2) = x1 + x2 + 3 |0|_0_A() = 1 s_1_A(x1) = x1 + 2 base order 2: precedence: plus_2 > s_1 > app# > cons_2 = size_1# = |0|_0 > map_1 = node_2 > map_2# = size_0 partial status: pi(app#) = [2] pi(map_1) = [] pi(map_2#) = [] pi(cons_2) = [1] pi(size_0) = [] pi(size_1#) = [1] pi(node_2) = [] pi(plus_2) = [] pi(|0|_0) = [] pi(s_1) = [1] The following rules are removed: p1 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) p2: map_2#(f,cons_2(x,xs)) -> app#(f,x) p3: app#(size_0(),y) -> size_1#(y) p4: size_1#(node_2(x,xs)) -> map_2#(size_0(),xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(map_0(),y) -> map_1(y) r4: app(map_1(x1),y) -> map_2(x1,y) r5: app(node_0(),y) -> node_1(y) r6: app(node_1(x1),y) -> node_2(x1,y) r7: app(plus_0(),y) -> plus_1(y) r8: app(plus_1(x1),y) -> plus_2(x1,y) r9: app(s_0(),y) -> s_1(y) r10: app(size_0(),y) -> size_1(y) r11: app(sum_0(),y) -> sum_1(y) r12: map_2(f,nil_0()) -> nil_0() r13: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r14: sum_1(cons_2(x,xs)) -> plus_2(x,sum_1(xs)) r15: size_1(node_2(x,xs)) -> s_1(sum_1(map_2(size_0(),xs))) r16: plus_2(|0|_0(),x) -> |0|_0() r17: plus_2(s_1(x),y) -> s_1(plus_2(x,y)) The estimated dependency graph contains the following SCCs: {p1, p2, p3, p4} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) p2: map_2#(f,cons_2(x,xs)) -> app#(f,x) p3: app#(size_0(),y) -> size_1#(y) p4: size_1#(node_2(x,xs)) -> map_2#(size_0(),xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(map_0(),y) -> map_1(y) r4: app(map_1(x1),y) -> map_2(x1,y) r5: app(node_0(),y) -> node_1(y) r6: app(node_1(x1),y) -> node_2(x1,y) r7: app(plus_0(),y) -> plus_1(y) r8: app(plus_1(x1),y) -> plus_2(x1,y) r9: app(s_0(),y) -> s_1(y) r10: app(size_0(),y) -> size_1(y) r11: app(sum_0(),y) -> sum_1(y) r12: map_2(f,nil_0()) -> nil_0() r13: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r14: sum_1(cons_2(x,xs)) -> plus_2(x,sum_1(xs)) r15: size_1(node_2(x,xs)) -> s_1(sum_1(map_2(size_0(),xs))) r16: plus_2(|0|_0(),x) -> |0|_0() r17: plus_2(s_1(x),y) -> s_1(plus_2(x,y)) The set of usable rules consists of r1, r3, r5, r6, r7, r9, r16, r17 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: map_2#_A(x1,x2) = x1 + x2 + 5 cons_2_A(x1,x2) = x1 + x2 + 12 app#_A(x1,x2) = x2 + 11 size_0_A() = 1 size_1#_A(x1) = x1 + 2 node_2_A(x1,x2) = x2 + 7 app_A(x1,x2) = x2 + 8 cons_0_A() = 2 cons_1_A(x1) = 1 map_0_A() = 2 map_1_A(x1) = 1 node_0_A() = 1 node_1_A(x1) = x1 + 2 plus_0_A() = 2 plus_1_A(x1) = 1 s_0_A() = 1 s_1_A(x1) = x1 + 2 plus_2_A(x1,x2) = x1 + x2 + 9 |0|_0_A() = 1 base order 2: precedence: size_1# = plus_2 > map_2# = s_1 > node_2 > size_0 = app = cons_0 = map_0 = plus_0 = s_0 = |0|_0 > cons_2 = app# = map_1 = node_1 = plus_1 > cons_1 = node_0 partial status: pi(map_2#) = [2] pi(cons_2) = [2] pi(app#) = [] pi(size_0) = [] pi(size_1#) = [] pi(node_2) = [] pi(app) = [2] pi(cons_0) = [] pi(cons_1) = [] pi(map_0) = [] pi(map_1) = [] pi(node_0) = [] pi(node_1) = [1] pi(plus_0) = [] pi(plus_1) = [] pi(s_0) = [] pi(s_1) = [1] pi(plus_2) = [1, 2] pi(|0|_0) = [] The following rules are removed: p1 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(f,cons_2(x,xs)) -> app#(f,x) p2: app#(size_0(),y) -> size_1#(y) p3: size_1#(node_2(x,xs)) -> map_2#(size_0(),xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(map_0(),y) -> map_1(y) r4: app(map_1(x1),y) -> map_2(x1,y) r5: app(node_0(),y) -> node_1(y) r6: app(node_1(x1),y) -> node_2(x1,y) r7: app(plus_0(),y) -> plus_1(y) r8: app(plus_1(x1),y) -> plus_2(x1,y) r9: app(s_0(),y) -> s_1(y) r10: app(size_0(),y) -> size_1(y) r11: app(sum_0(),y) -> sum_1(y) r12: map_2(f,nil_0()) -> nil_0() r13: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r14: sum_1(cons_2(x,xs)) -> plus_2(x,sum_1(xs)) r15: size_1(node_2(x,xs)) -> s_1(sum_1(map_2(size_0(),xs))) r16: plus_2(|0|_0(),x) -> |0|_0() r17: plus_2(s_1(x),y) -> s_1(plus_2(x,y)) The estimated dependency graph contains the following SCCs: {p1, p2, p3} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(f,cons_2(x,xs)) -> app#(f,x) p2: app#(size_0(),y) -> size_1#(y) p3: size_1#(node_2(x,xs)) -> map_2#(size_0(),xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(map_0(),y) -> map_1(y) r4: app(map_1(x1),y) -> map_2(x1,y) r5: app(node_0(),y) -> node_1(y) r6: app(node_1(x1),y) -> node_2(x1,y) r7: app(plus_0(),y) -> plus_1(y) r8: app(plus_1(x1),y) -> plus_2(x1,y) r9: app(s_0(),y) -> s_1(y) r10: app(size_0(),y) -> size_1(y) r11: app(sum_0(),y) -> sum_1(y) r12: map_2(f,nil_0()) -> nil_0() r13: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r14: sum_1(cons_2(x,xs)) -> plus_2(x,sum_1(xs)) r15: size_1(node_2(x,xs)) -> s_1(sum_1(map_2(size_0(),xs))) r16: plus_2(|0|_0(),x) -> |0|_0() r17: plus_2(s_1(x),y) -> s_1(plus_2(x,y)) The set of usable rules consists of r1, r3, r5, r6, r7, r9, r16, r17 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: map_2#_A(x1,x2) = x1 + x2 cons_2_A(x1,x2) = x1 + x2 app#_A(x1,x2) = x2 size_0_A() = 0 size_1#_A(x1) = x1 node_2_A(x1,x2) = x2 app_A(x1,x2) = x2 + 4 cons_0_A() = 2 cons_1_A(x1) = x1 + 1 map_0_A() = 1 map_1_A(x1) = x1 + 3 node_0_A() = 1 node_1_A(x1) = x1 + 2 plus_0_A() = 2 plus_1_A(x1) = 1 s_0_A() = 2 s_1_A(x1) = x1 + 1 plus_2_A(x1,x2) = x1 + x2 + 5 |0|_0_A() = 1 base order 2: precedence: plus_2 > cons_1 = plus_0 = s_1 > cons_2 = node_2 = app = cons_0 = node_1 = plus_1 = s_0 = |0|_0 > map_2# = map_1 = node_0 > app# = size_0 = map_0 > size_1# partial status: pi(map_2#) = [2] pi(cons_2) = [1, 2] pi(app#) = [2] pi(size_0) = [] pi(size_1#) = [1] pi(node_2) = [2] pi(app) = [2] pi(cons_0) = [] pi(cons_1) = [1] pi(map_0) = [] pi(map_1) = [1] pi(node_0) = [] pi(node_1) = [1] pi(plus_0) = [] pi(plus_1) = [] pi(s_0) = [] pi(s_1) = [1] pi(plus_2) = [] pi(|0|_0) = [] The following rules are removed: p2 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(f,cons_2(x,xs)) -> app#(f,x) p2: size_1#(node_2(x,xs)) -> map_2#(size_0(),xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(map_0(),y) -> map_1(y) r4: app(map_1(x1),y) -> map_2(x1,y) r5: app(node_0(),y) -> node_1(y) r6: app(node_1(x1),y) -> node_2(x1,y) r7: app(plus_0(),y) -> plus_1(y) r8: app(plus_1(x1),y) -> plus_2(x1,y) r9: app(s_0(),y) -> s_1(y) r10: app(size_0(),y) -> size_1(y) r11: app(sum_0(),y) -> sum_1(y) r12: map_2(f,nil_0()) -> nil_0() r13: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r14: sum_1(cons_2(x,xs)) -> plus_2(x,sum_1(xs)) r15: size_1(node_2(x,xs)) -> s_1(sum_1(map_2(size_0(),xs))) r16: plus_2(|0|_0(),x) -> |0|_0() r17: plus_2(s_1(x),y) -> s_1(plus_2(x,y)) The estimated dependency graph contains the following SCCs: (no SCCs) -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: sum_1#(cons_2(x,xs)) -> sum_1#(xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(map_0(),y) -> map_1(y) r4: app(map_1(x1),y) -> map_2(x1,y) r5: app(node_0(),y) -> node_1(y) r6: app(node_1(x1),y) -> node_2(x1,y) r7: app(plus_0(),y) -> plus_1(y) r8: app(plus_1(x1),y) -> plus_2(x1,y) r9: app(s_0(),y) -> s_1(y) r10: app(size_0(),y) -> size_1(y) r11: app(sum_0(),y) -> sum_1(y) r12: map_2(f,nil_0()) -> nil_0() r13: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r14: sum_1(cons_2(x,xs)) -> plus_2(x,sum_1(xs)) r15: size_1(node_2(x,xs)) -> s_1(sum_1(map_2(size_0(),xs))) r16: plus_2(|0|_0(),x) -> |0|_0() r17: plus_2(s_1(x),y) -> s_1(plus_2(x,y)) The set of usable rules consists of r1, r2, r3, r5, r6, r7, r8, r9, r16, r17 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: sum_1#_A(x1) = x1 cons_2_A(x1,x2) = x1 + x2 + 5 app_A(x1,x2) = x1 + x2 + 6 cons_0_A() = 1 cons_1_A(x1) = x1 + 2 map_0_A() = 1 map_1_A(x1) = x1 + 2 node_0_A() = 1 node_1_A(x1) = x1 + 2 node_2_A(x1,x2) = x2 + 7 plus_0_A() = 1 plus_1_A(x1) = x1 + 2 plus_2_A(x1,x2) = x1 + x2 + 3 s_0_A() = 1 s_1_A(x1) = x1 + 2 |0|_0_A() = 1 base order 2: precedence: app > node_2 > node_1 > cons_2 = map_1 = node_0 > sum_1# = cons_1 = map_0 > cons_0 = plus_2 > plus_1 = s_1 = |0|_0 > plus_0 = s_0 partial status: pi(sum_1#) = [] pi(cons_2) = [2] pi(app) = [2] pi(cons_0) = [] pi(cons_1) = [1] pi(map_0) = [] pi(map_1) = [1] pi(node_0) = [] pi(node_1) = [1] pi(node_2) = [] pi(plus_0) = [] pi(plus_1) = [1] pi(plus_2) = [1] pi(s_0) = [] pi(s_1) = [] pi(|0|_0) = [] The following rules are removed: p1 Then no dependency pair remains. -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: plus_2#(s_1(x),y) -> plus_2#(x,y) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(map_0(),y) -> map_1(y) r4: app(map_1(x1),y) -> map_2(x1,y) r5: app(node_0(),y) -> node_1(y) r6: app(node_1(x1),y) -> node_2(x1,y) r7: app(plus_0(),y) -> plus_1(y) r8: app(plus_1(x1),y) -> plus_2(x1,y) r9: app(s_0(),y) -> s_1(y) r10: app(size_0(),y) -> size_1(y) r11: app(sum_0(),y) -> sum_1(y) r12: map_2(f,nil_0()) -> nil_0() r13: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r14: sum_1(cons_2(x,xs)) -> plus_2(x,sum_1(xs)) r15: size_1(node_2(x,xs)) -> s_1(sum_1(map_2(size_0(),xs))) r16: plus_2(|0|_0(),x) -> |0|_0() r17: plus_2(s_1(x),y) -> s_1(plus_2(x,y)) The set of usable rules consists of r1, r5, r6, r7, r9, r16, r17 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: plus_2#_A(x1,x2) = x1 + x2 + 3 s_1_A(x1) = x1 + 2 app_A(x1,x2) = x2 + 11 cons_0_A() = 2 cons_1_A(x1) = 1 node_0_A() = 2 node_1_A(x1) = 1 node_2_A(x1,x2) = x2 + 10 plus_0_A() = 11 plus_1_A(x1) = 10 s_0_A() = 1 plus_2_A(x1,x2) = x1 + x2 + 9 |0|_0_A() = 1 base order 2: precedence: plus_2 > app = plus_0 > plus_1 > plus_2# = node_0 = node_2 > s_1 = node_1 = |0|_0 > s_0 > cons_1 > cons_0 partial status: pi(plus_2#) = [1, 2] pi(s_1) = [] pi(app) = [2] pi(cons_0) = [] pi(cons_1) = [] pi(node_0) = [] pi(node_1) = [] pi(node_2) = [2] pi(plus_0) = [] pi(plus_1) = [] pi(s_0) = [] pi(plus_2) = [] pi(|0|_0) = [] The following rules are removed: p1 Then no dependency pair remains.