YES We show the termination of the TRS R: app(pred(),app(s(),x)) -> x app(app(minus(),x),|0|()) -> x app(app(minus(),x),app(s(),y)) -> app(pred(),app(app(minus(),x),y)) app(app(quot(),|0|()),app(s(),y)) -> |0|() app(app(quot(),app(s(),x)),app(s(),y)) -> app(s(),app(app(quot(),app(app(minus(),x),y)),app(s(),y))) app(app(map(),f),nil()) -> nil() app(app(map(),f),app(app(cons(),x),xs)) -> app(app(cons(),app(f,x)),app(app(map(),f),xs)) app(app(filter(),f),nil()) -> nil() app(app(filter(),f),app(app(cons(),x),xs)) -> app(app(app(app(filter2(),app(f,x)),f),x),xs) app(app(app(app(filter2(),true()),f),x),xs) -> app(app(cons(),x),app(app(filter(),f),xs)) app(app(app(app(filter2(),false()),f),x),xs) -> app(app(filter(),f),xs) Instead we prove termination of the uncurried system: app(cons_0(),y) -> cons_1(y) app(cons_1(x1),y) -> cons_2(x1,y) app(filter_0(),y) -> filter_1(y) app(filter_1(x1),y) -> filter_2(x1,y) app(filter2_0(),y) -> filter2_1(y) app(filter2_1(x1),y) -> filter2_2(x1,y) app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) app(map_0(),y) -> map_1(y) app(map_1(x1),y) -> map_2(x1,y) app(minus_0(),y) -> minus_1(y) app(minus_1(x1),y) -> minus_2(x1,y) app(pred_0(),y) -> pred_1(y) app(quot_0(),y) -> quot_1(y) app(quot_1(x1),y) -> quot_2(x1,y) app(s_0(),y) -> s_1(y) pred_1(s_1(x)) -> x minus_2(x,|0|_0()) -> x minus_2(x,s_1(y)) -> pred_1(minus_2(x,y)) quot_2(|0|_0(),s_1(y)) -> |0|_0() quot_2(s_1(x),s_1(y)) -> s_1(quot_2(minus_2(x,y),s_1(y))) map_2(f,nil_0()) -> nil_0() map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) filter_2(f,nil_0()) -> nil_0() filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: app#(filter_1(x1),y) -> filter_2#(x1,y) p2: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p3: app#(map_1(x1),y) -> map_2#(x1,y) p4: app#(minus_1(x1),y) -> minus_2#(x1,y) p5: app#(pred_0(),y) -> pred_1#(y) p6: app#(quot_1(x1),y) -> quot_2#(x1,y) p7: minus_2#(x,s_1(y)) -> pred_1#(minus_2(x,y)) p8: minus_2#(x,s_1(y)) -> minus_2#(x,y) p9: quot_2#(s_1(x),s_1(y)) -> quot_2#(minus_2(x,y),s_1(y)) p10: quot_2#(s_1(x),s_1(y)) -> minus_2#(x,y) p11: map_2#(f,cons_2(x,xs)) -> app#(f,x) p12: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) p13: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs) p14: filter_2#(f,cons_2(x,xs)) -> app#(f,x) p15: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs) p16: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(filter_0(),y) -> filter_1(y) r4: app(filter_1(x1),y) -> filter_2(x1,y) r5: app(filter2_0(),y) -> filter2_1(y) r6: app(filter2_1(x1),y) -> filter2_2(x1,y) r7: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r8: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r9: app(map_0(),y) -> map_1(y) r10: app(map_1(x1),y) -> map_2(x1,y) r11: app(minus_0(),y) -> minus_1(y) r12: app(minus_1(x1),y) -> minus_2(x1,y) r13: app(pred_0(),y) -> pred_1(y) r14: app(quot_0(),y) -> quot_1(y) r15: app(quot_1(x1),y) -> quot_2(x1,y) r16: app(s_0(),y) -> s_1(y) r17: pred_1(s_1(x)) -> x r18: minus_2(x,|0|_0()) -> x r19: minus_2(x,s_1(y)) -> pred_1(minus_2(x,y)) r20: quot_2(|0|_0(),s_1(y)) -> |0|_0() r21: quot_2(s_1(x),s_1(y)) -> s_1(quot_2(minus_2(x,y),s_1(y))) r22: map_2(f,nil_0()) -> nil_0() r23: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r24: filter_2(f,nil_0()) -> nil_0() r25: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r26: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r27: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The estimated dependency graph contains the following SCCs: {p1, p2, p3, p11, p12, p13, p14, p15, p16} {p9} {p8} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: app#(filter_1(x1),y) -> filter_2#(x1,y) p2: filter_2#(f,cons_2(x,xs)) -> app#(f,x) p3: app#(map_1(x1),y) -> map_2#(x1,y) p4: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) p5: map_2#(f,cons_2(x,xs)) -> app#(f,x) p6: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p7: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs) p8: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs) p9: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(filter_0(),y) -> filter_1(y) r4: app(filter_1(x1),y) -> filter_2(x1,y) r5: app(filter2_0(),y) -> filter2_1(y) r6: app(filter2_1(x1),y) -> filter2_2(x1,y) r7: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r8: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r9: app(map_0(),y) -> map_1(y) r10: app(map_1(x1),y) -> map_2(x1,y) r11: app(minus_0(),y) -> minus_1(y) r12: app(minus_1(x1),y) -> minus_2(x1,y) r13: app(pred_0(),y) -> pred_1(y) r14: app(quot_0(),y) -> quot_1(y) r15: app(quot_1(x1),y) -> quot_2(x1,y) r16: app(s_0(),y) -> s_1(y) r17: pred_1(s_1(x)) -> x r18: minus_2(x,|0|_0()) -> x r19: minus_2(x,s_1(y)) -> pred_1(minus_2(x,y)) r20: quot_2(|0|_0(),s_1(y)) -> |0|_0() r21: quot_2(s_1(x),s_1(y)) -> s_1(quot_2(minus_2(x,y),s_1(y))) r22: map_2(f,nil_0()) -> nil_0() r23: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r24: filter_2(f,nil_0()) -> nil_0() r25: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r26: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r27: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of r1, r2, r3, r5, r6, r7, r9, r11, r14, r15, r16, r20, r21, r24 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: app#_A(x1,x2) = x1 + x2 + 3 filter_1_A(x1) = x1 + 5 filter_2#_A(x1,x2) = x1 + x2 + 4 cons_2_A(x1,x2) = x1 + x2 + 2 map_1_A(x1) = x1 + 2 map_2#_A(x1,x2) = x1 + x2 + 3 filter2_3_A(x1,x2,x3) = x1 + x2 + x3 + 4 filter2_4#_A(x1,x2,x3,x4) = x2 + x4 + 5 false_0_A() = 1 app_A(x1,x2) = x1 + x2 + 3 true_0_A() = 3 cons_0_A() = 1 cons_1_A(x1) = x1 + 3 filter_0_A() = 3 filter2_0_A() = 1 filter2_1_A(x1) = x1 + 2 filter2_2_A(x1,x2) = x1 + x2 + 3 map_0_A() = 1 minus_0_A() = 1 minus_1_A(x1) = x1 + 2 quot_0_A() = 1 quot_1_A(x1) = x1 + 2 quot_2_A(x1,x2) = x1 + 1 s_0_A() = 3 s_1_A(x1) = 2 |0|_0_A() = 1 minus_2_A(x1,x2) = x1 + x2 + 4 filter_2_A(x1,x2) = x1 + x2 + 6 nil_0_A() = 1 base order 2: precedence: map_2# > app# > filter2_4# > filter_2# = cons_2 = filter2_3 > s_0 = minus_2 > s_1 = filter_2 > false_0 = app = true_0 = nil_0 > filter_1 = map_1 = cons_1 = filter2_2 = minus_1 = quot_2 > cons_0 = filter_0 = filter2_1 = map_0 = minus_0 = quot_1 = |0|_0 > filter2_0 = quot_0 partial status: pi(app#) = [] pi(filter_1) = [] pi(filter_2#) = [] pi(cons_2) = [] pi(map_1) = [1] pi(map_2#) = [] pi(filter2_3) = [3] pi(filter2_4#) = [4] pi(false_0) = [] pi(app) = [1, 2] pi(true_0) = [] pi(cons_0) = [] pi(cons_1) = [1] pi(filter_0) = [] pi(filter2_0) = [] pi(filter2_1) = [1] pi(filter2_2) = [1, 2] pi(map_0) = [] pi(minus_0) = [] pi(minus_1) = [1] pi(quot_0) = [] pi(quot_1) = [1] pi(quot_2) = [1] pi(s_0) = [] pi(s_1) = [] pi(|0|_0) = [] pi(minus_2) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p6 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: app#(filter_1(x1),y) -> filter_2#(x1,y) p2: filter_2#(f,cons_2(x,xs)) -> app#(f,x) p3: app#(map_1(x1),y) -> map_2#(x1,y) p4: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) p5: map_2#(f,cons_2(x,xs)) -> app#(f,x) p6: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs) p7: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs) p8: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(filter_0(),y) -> filter_1(y) r4: app(filter_1(x1),y) -> filter_2(x1,y) r5: app(filter2_0(),y) -> filter2_1(y) r6: app(filter2_1(x1),y) -> filter2_2(x1,y) r7: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r8: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r9: app(map_0(),y) -> map_1(y) r10: app(map_1(x1),y) -> map_2(x1,y) r11: app(minus_0(),y) -> minus_1(y) r12: app(minus_1(x1),y) -> minus_2(x1,y) r13: app(pred_0(),y) -> pred_1(y) r14: app(quot_0(),y) -> quot_1(y) r15: app(quot_1(x1),y) -> quot_2(x1,y) r16: app(s_0(),y) -> s_1(y) r17: pred_1(s_1(x)) -> x r18: minus_2(x,|0|_0()) -> x r19: minus_2(x,s_1(y)) -> pred_1(minus_2(x,y)) r20: quot_2(|0|_0(),s_1(y)) -> |0|_0() r21: quot_2(s_1(x),s_1(y)) -> s_1(quot_2(minus_2(x,y),s_1(y))) r22: map_2(f,nil_0()) -> nil_0() r23: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r24: filter_2(f,nil_0()) -> nil_0() r25: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r26: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r27: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The estimated dependency graph contains the following SCCs: {p1, p2, p3, p4, p5, p6, p7, p8} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: app#(filter_1(x1),y) -> filter_2#(x1,y) p2: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs) p3: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs) p4: filter_2#(f,cons_2(x,xs)) -> app#(f,x) p5: app#(map_1(x1),y) -> map_2#(x1,y) p6: map_2#(f,cons_2(x,xs)) -> app#(f,x) p7: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) p8: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(filter_0(),y) -> filter_1(y) r4: app(filter_1(x1),y) -> filter_2(x1,y) r5: app(filter2_0(),y) -> filter2_1(y) r6: app(filter2_1(x1),y) -> filter2_2(x1,y) r7: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r8: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r9: app(map_0(),y) -> map_1(y) r10: app(map_1(x1),y) -> map_2(x1,y) r11: app(minus_0(),y) -> minus_1(y) r12: app(minus_1(x1),y) -> minus_2(x1,y) r13: app(pred_0(),y) -> pred_1(y) r14: app(quot_0(),y) -> quot_1(y) r15: app(quot_1(x1),y) -> quot_2(x1,y) r16: app(s_0(),y) -> s_1(y) r17: pred_1(s_1(x)) -> x r18: minus_2(x,|0|_0()) -> x r19: minus_2(x,s_1(y)) -> pred_1(minus_2(x,y)) r20: quot_2(|0|_0(),s_1(y)) -> |0|_0() r21: quot_2(s_1(x),s_1(y)) -> s_1(quot_2(minus_2(x,y),s_1(y))) r22: map_2(f,nil_0()) -> nil_0() r23: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r24: filter_2(f,nil_0()) -> nil_0() r25: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r26: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r27: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of r1, r2, r3, r5, r6, r7, r9, r11, r14, r15, r16, r20, r21, r24 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: app#_A(x1,x2) = x1 + x2 + 5 filter_1_A(x1) = x1 + 5 filter_2#_A(x1,x2) = x1 + x2 + 4 cons_2_A(x1,x2) = x1 + x2 + 4 filter2_4#_A(x1,x2,x3,x4) = x2 + x4 + 5 app_A(x1,x2) = x1 + x2 + 7 true_0_A() = 1 map_1_A(x1) = x1 + 2 map_2#_A(x1,x2) = x1 + x2 + 5 false_0_A() = 1 cons_0_A() = 1 cons_1_A(x1) = x1 + 2 filter_0_A() = 1 filter2_0_A() = 1 filter2_1_A(x1) = x1 + 2 filter2_2_A(x1,x2) = x1 + x2 + 3 filter2_3_A(x1,x2,x3) = x1 + x2 + x3 + 4 map_0_A() = 1 minus_0_A() = 1 minus_1_A(x1) = x1 + 2 quot_0_A() = 1 quot_1_A(x1) = x1 + 2 quot_2_A(x1,x2) = x1 + 1 s_0_A() = 3 s_1_A(x1) = 2 |0|_0_A() = 1 minus_2_A(x1,x2) = x1 + x2 + 4 filter_2_A(x1,x2) = x1 + x2 + 2 nil_0_A() = 1 base order 2: precedence: filter2_4# > filter_2# = map_2# = s_0 = minus_2 > app# = s_1 > cons_2 = app > cons_1 = quot_2 > map_1 = cons_0 = filter2_3 = minus_1 = quot_1 = |0|_0 = filter_2 > filter_1 = true_0 = false_0 = filter2_2 = map_0 = minus_0 = quot_0 = nil_0 > filter_0 = filter2_1 > filter2_0 partial status: pi(app#) = [] pi(filter_1) = [1] pi(filter_2#) = [] pi(cons_2) = [] pi(filter2_4#) = [] pi(app) = [] pi(true_0) = [] pi(map_1) = [1] pi(map_2#) = [2] pi(false_0) = [] pi(cons_0) = [] pi(cons_1) = [1] pi(filter_0) = [] pi(filter2_0) = [] pi(filter2_1) = [1] pi(filter2_2) = [1, 2] pi(filter2_3) = [1, 2, 3] pi(map_0) = [] pi(minus_0) = [] pi(minus_1) = [1] pi(quot_0) = [] pi(quot_1) = [] pi(quot_2) = [1] pi(s_0) = [] pi(s_1) = [] pi(|0|_0) = [] pi(minus_2) = [] pi(filter_2) = [1] pi(nil_0) = [] The following rules are removed: p1 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs) p2: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs) p3: filter_2#(f,cons_2(x,xs)) -> app#(f,x) p4: app#(map_1(x1),y) -> map_2#(x1,y) p5: map_2#(f,cons_2(x,xs)) -> app#(f,x) p6: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) p7: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(filter_0(),y) -> filter_1(y) r4: app(filter_1(x1),y) -> filter_2(x1,y) r5: app(filter2_0(),y) -> filter2_1(y) r6: app(filter2_1(x1),y) -> filter2_2(x1,y) r7: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r8: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r9: app(map_0(),y) -> map_1(y) r10: app(map_1(x1),y) -> map_2(x1,y) r11: app(minus_0(),y) -> minus_1(y) r12: app(minus_1(x1),y) -> minus_2(x1,y) r13: app(pred_0(),y) -> pred_1(y) r14: app(quot_0(),y) -> quot_1(y) r15: app(quot_1(x1),y) -> quot_2(x1,y) r16: app(s_0(),y) -> s_1(y) r17: pred_1(s_1(x)) -> x r18: minus_2(x,|0|_0()) -> x r19: minus_2(x,s_1(y)) -> pred_1(minus_2(x,y)) r20: quot_2(|0|_0(),s_1(y)) -> |0|_0() r21: quot_2(s_1(x),s_1(y)) -> s_1(quot_2(minus_2(x,y),s_1(y))) r22: map_2(f,nil_0()) -> nil_0() r23: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r24: filter_2(f,nil_0()) -> nil_0() r25: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r26: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r27: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The estimated dependency graph contains the following SCCs: {p1, p2, p7} {p4, p5, p6} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs) p2: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs) p3: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(filter_0(),y) -> filter_1(y) r4: app(filter_1(x1),y) -> filter_2(x1,y) r5: app(filter2_0(),y) -> filter2_1(y) r6: app(filter2_1(x1),y) -> filter2_2(x1,y) r7: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r8: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r9: app(map_0(),y) -> map_1(y) r10: app(map_1(x1),y) -> map_2(x1,y) r11: app(minus_0(),y) -> minus_1(y) r12: app(minus_1(x1),y) -> minus_2(x1,y) r13: app(pred_0(),y) -> pred_1(y) r14: app(quot_0(),y) -> quot_1(y) r15: app(quot_1(x1),y) -> quot_2(x1,y) r16: app(s_0(),y) -> s_1(y) r17: pred_1(s_1(x)) -> x r18: minus_2(x,|0|_0()) -> x r19: minus_2(x,s_1(y)) -> pred_1(minus_2(x,y)) r20: quot_2(|0|_0(),s_1(y)) -> |0|_0() r21: quot_2(s_1(x),s_1(y)) -> s_1(quot_2(minus_2(x,y),s_1(y))) r22: map_2(f,nil_0()) -> nil_0() r23: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r24: filter_2(f,nil_0()) -> nil_0() r25: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r26: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r27: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of r1, r2, r3, r5, r7, r9, r11, r14, r15, r16, r20, r21, r24 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: filter_2#_A(x1,x2) = x2 + 2 cons_2_A(x1,x2) = x1 + x2 + 4 filter2_4#_A(x1,x2,x3,x4) = x4 + 3 app_A(x1,x2) = x1 + x2 + 5 false_0_A() = 3 true_0_A() = 3 cons_0_A() = 1 cons_1_A(x1) = x1 + 2 filter_0_A() = 4 filter_1_A(x1) = x1 + 3 filter2_0_A() = 1 filter2_1_A(x1) = x1 + 2 filter2_2_A(x1,x2) = x1 + x2 + 8 filter2_3_A(x1,x2,x3) = x1 + x2 + x3 + 9 map_0_A() = 1 map_1_A(x1) = x1 + 2 minus_0_A() = 2 minus_1_A(x1) = x1 + 6 quot_0_A() = 1 quot_1_A(x1) = x1 + 2 quot_2_A(x1,x2) = x1 + 1 s_0_A() = 4 s_1_A(x1) = 3 |0|_0_A() = 1 minus_2_A(x1,x2) = x1 + x2 + 5 filter_2_A(x1,x2) = x1 + x2 + 7 nil_0_A() = 1 base order 2: precedence: cons_2 = quot_1 = minus_2 > filter2_1 = filter2_3 = quot_2 = s_0 > filter2_2 = s_1 = filter_2 > app = true_0 = filter2_0 = quot_0 = |0|_0 > filter_2# = cons_1 = filter_1 = minus_1 > filter2_4# = false_0 = cons_0 = filter_0 = map_1 = minus_0 = nil_0 > map_0 partial status: pi(filter_2#) = [2] pi(cons_2) = [2] pi(filter2_4#) = [] pi(app) = [] pi(false_0) = [] pi(true_0) = [] pi(cons_0) = [] pi(cons_1) = [1] pi(filter_0) = [] pi(filter_1) = [1] pi(filter2_0) = [] pi(filter2_1) = [1] pi(filter2_2) = [1, 2] pi(filter2_3) = [3] pi(map_0) = [] pi(map_1) = [1] pi(minus_0) = [] pi(minus_1) = [1] pi(quot_0) = [] pi(quot_1) = [] pi(quot_2) = [] pi(s_0) = [] pi(s_1) = [] pi(|0|_0) = [] pi(minus_2) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p1 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs) p2: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(filter_0(),y) -> filter_1(y) r4: app(filter_1(x1),y) -> filter_2(x1,y) r5: app(filter2_0(),y) -> filter2_1(y) r6: app(filter2_1(x1),y) -> filter2_2(x1,y) r7: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r8: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r9: app(map_0(),y) -> map_1(y) r10: app(map_1(x1),y) -> map_2(x1,y) r11: app(minus_0(),y) -> minus_1(y) r12: app(minus_1(x1),y) -> minus_2(x1,y) r13: app(pred_0(),y) -> pred_1(y) r14: app(quot_0(),y) -> quot_1(y) r15: app(quot_1(x1),y) -> quot_2(x1,y) r16: app(s_0(),y) -> s_1(y) r17: pred_1(s_1(x)) -> x r18: minus_2(x,|0|_0()) -> x r19: minus_2(x,s_1(y)) -> pred_1(minus_2(x,y)) r20: quot_2(|0|_0(),s_1(y)) -> |0|_0() r21: quot_2(s_1(x),s_1(y)) -> s_1(quot_2(minus_2(x,y),s_1(y))) r22: map_2(f,nil_0()) -> nil_0() r23: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r24: filter_2(f,nil_0()) -> nil_0() r25: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r26: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r27: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The estimated dependency graph contains the following SCCs: (no SCCs) -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: app#(map_1(x1),y) -> map_2#(x1,y) p2: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) p3: map_2#(f,cons_2(x,xs)) -> app#(f,x) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(filter_0(),y) -> filter_1(y) r4: app(filter_1(x1),y) -> filter_2(x1,y) r5: app(filter2_0(),y) -> filter2_1(y) r6: app(filter2_1(x1),y) -> filter2_2(x1,y) r7: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r8: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r9: app(map_0(),y) -> map_1(y) r10: app(map_1(x1),y) -> map_2(x1,y) r11: app(minus_0(),y) -> minus_1(y) r12: app(minus_1(x1),y) -> minus_2(x1,y) r13: app(pred_0(),y) -> pred_1(y) r14: app(quot_0(),y) -> quot_1(y) r15: app(quot_1(x1),y) -> quot_2(x1,y) r16: app(s_0(),y) -> s_1(y) r17: pred_1(s_1(x)) -> x r18: minus_2(x,|0|_0()) -> x r19: minus_2(x,s_1(y)) -> pred_1(minus_2(x,y)) r20: quot_2(|0|_0(),s_1(y)) -> |0|_0() r21: quot_2(s_1(x),s_1(y)) -> s_1(quot_2(minus_2(x,y),s_1(y))) r22: map_2(f,nil_0()) -> nil_0() r23: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r24: filter_2(f,nil_0()) -> nil_0() r25: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r26: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r27: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of r1, r3, r5, r6, r7, r9, r11, r13, r14, r16, r17, r18, r19, r20, r24 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: app#_A(x1,x2) = x2 + 4 map_1_A(x1) = x1 + 2 map_2#_A(x1,x2) = x2 + 3 cons_2_A(x1,x2) = x1 + x2 + 5 app_A(x1,x2) = x2 + 4 cons_0_A() = 2 cons_1_A(x1) = 1 filter_0_A() = 2 filter_1_A(x1) = 1 filter2_0_A() = 4 filter2_1_A(x1) = 3 filter2_2_A(x1,x2) = 2 filter2_3_A(x1,x2,x3) = 1 map_0_A() = 1 minus_0_A() = 2 minus_1_A(x1) = 1 pred_0_A() = 1 pred_1_A(x1) = x1 + 2 quot_0_A() = 2 quot_1_A(x1) = 1 s_0_A() = 1 s_1_A(x1) = x1 + 3 minus_2_A(x1,x2) = x1 + x2 + 9 |0|_0_A() = 2 quot_2_A(x1,x2) = x1 + 5 filter_2_A(x1,x2) = x1 + x2 + 5 nil_0_A() = 1 base order 2: precedence: pred_1 > cons_2 = cons_0 = filter2_0 = quot_0 = minus_2 = |0|_0 > cons_1 = filter2_1 = quot_1 = s_1 = quot_2 > app = minus_0 = s_0 > map_2# = filter_0 = filter2_2 = minus_1 = pred_0 = filter_2 > app# = map_1 = filter_1 = filter2_3 = nil_0 > map_0 partial status: pi(app#) = [] pi(map_1) = [1] pi(map_2#) = [] pi(cons_2) = [2] pi(app) = [] pi(cons_0) = [] pi(cons_1) = [] pi(filter_0) = [] pi(filter_1) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(filter2_3) = [] pi(map_0) = [] pi(minus_0) = [] pi(minus_1) = [] pi(pred_0) = [] pi(pred_1) = [1] pi(quot_0) = [] pi(quot_1) = [] pi(s_0) = [] pi(s_1) = [1] pi(minus_2) = [2] pi(|0|_0) = [] pi(quot_2) = [] pi(filter_2) = [1] pi(nil_0) = [] The following rules are removed: p1 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) p2: map_2#(f,cons_2(x,xs)) -> app#(f,x) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(filter_0(),y) -> filter_1(y) r4: app(filter_1(x1),y) -> filter_2(x1,y) r5: app(filter2_0(),y) -> filter2_1(y) r6: app(filter2_1(x1),y) -> filter2_2(x1,y) r7: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r8: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r9: app(map_0(),y) -> map_1(y) r10: app(map_1(x1),y) -> map_2(x1,y) r11: app(minus_0(),y) -> minus_1(y) r12: app(minus_1(x1),y) -> minus_2(x1,y) r13: app(pred_0(),y) -> pred_1(y) r14: app(quot_0(),y) -> quot_1(y) r15: app(quot_1(x1),y) -> quot_2(x1,y) r16: app(s_0(),y) -> s_1(y) r17: pred_1(s_1(x)) -> x r18: minus_2(x,|0|_0()) -> x r19: minus_2(x,s_1(y)) -> pred_1(minus_2(x,y)) r20: quot_2(|0|_0(),s_1(y)) -> |0|_0() r21: quot_2(s_1(x),s_1(y)) -> s_1(quot_2(minus_2(x,y),s_1(y))) r22: map_2(f,nil_0()) -> nil_0() r23: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r24: filter_2(f,nil_0()) -> nil_0() r25: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r26: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r27: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The estimated dependency graph contains the following SCCs: {p1} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(filter_0(),y) -> filter_1(y) r4: app(filter_1(x1),y) -> filter_2(x1,y) r5: app(filter2_0(),y) -> filter2_1(y) r6: app(filter2_1(x1),y) -> filter2_2(x1,y) r7: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r8: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r9: app(map_0(),y) -> map_1(y) r10: app(map_1(x1),y) -> map_2(x1,y) r11: app(minus_0(),y) -> minus_1(y) r12: app(minus_1(x1),y) -> minus_2(x1,y) r13: app(pred_0(),y) -> pred_1(y) r14: app(quot_0(),y) -> quot_1(y) r15: app(quot_1(x1),y) -> quot_2(x1,y) r16: app(s_0(),y) -> s_1(y) r17: pred_1(s_1(x)) -> x r18: minus_2(x,|0|_0()) -> x r19: minus_2(x,s_1(y)) -> pred_1(minus_2(x,y)) r20: quot_2(|0|_0(),s_1(y)) -> |0|_0() r21: quot_2(s_1(x),s_1(y)) -> s_1(quot_2(minus_2(x,y),s_1(y))) r22: map_2(f,nil_0()) -> nil_0() r23: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r24: filter_2(f,nil_0()) -> nil_0() r25: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r26: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r27: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of r1, r3, r5, r7, r9, r11, r14, r15, r16, r20, r21, r24 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: map_2#_A(x1,x2) = x2 cons_2_A(x1,x2) = x1 + x2 + 3 app_A(x1,x2) = x2 + 8 cons_0_A() = 1 cons_1_A(x1) = x1 + 2 filter_0_A() = 2 filter_1_A(x1) = 1 filter2_0_A() = 2 filter2_1_A(x1) = 1 filter2_2_A(x1,x2) = x1 + 2 filter2_3_A(x1,x2,x3) = 3 map_0_A() = 2 map_1_A(x1) = 1 minus_0_A() = 3 minus_1_A(x1) = 2 quot_0_A() = 6 quot_1_A(x1) = 5 quot_2_A(x1,x2) = 4 s_0_A() = 4 s_1_A(x1) = 3 |0|_0_A() = 1 minus_2_A(x1,x2) = 1 filter_2_A(x1,x2) = x1 + x2 + 3 nil_0_A() = 1 base order 2: precedence: quot_0 > quot_1 > filter2_2 = quot_2 = filter_2 > cons_2 = app = filter_0 = filter2_0 = filter2_3 = map_0 = minus_0 = s_0 = nil_0 > map_2# = cons_1 = filter_1 = filter2_1 = map_1 = minus_1 = s_1 > cons_0 = |0|_0 > minus_2 partial status: pi(map_2#) = [] pi(cons_2) = [2] pi(app) = [] pi(cons_0) = [] pi(cons_1) = [1] pi(filter_0) = [] pi(filter_1) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [1] pi(filter2_3) = [] pi(map_0) = [] pi(map_1) = [] pi(minus_0) = [] pi(minus_1) = [] pi(quot_0) = [] pi(quot_1) = [] pi(quot_2) = [] pi(s_0) = [] pi(s_1) = [] pi(|0|_0) = [] pi(minus_2) = [] pi(filter_2) = [1] pi(nil_0) = [] The following rules are removed: p1 Then no dependency pair remains. -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: quot_2#(s_1(x),s_1(y)) -> quot_2#(minus_2(x,y),s_1(y)) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(filter_0(),y) -> filter_1(y) r4: app(filter_1(x1),y) -> filter_2(x1,y) r5: app(filter2_0(),y) -> filter2_1(y) r6: app(filter2_1(x1),y) -> filter2_2(x1,y) r7: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r8: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r9: app(map_0(),y) -> map_1(y) r10: app(map_1(x1),y) -> map_2(x1,y) r11: app(minus_0(),y) -> minus_1(y) r12: app(minus_1(x1),y) -> minus_2(x1,y) r13: app(pred_0(),y) -> pred_1(y) r14: app(quot_0(),y) -> quot_1(y) r15: app(quot_1(x1),y) -> quot_2(x1,y) r16: app(s_0(),y) -> s_1(y) r17: pred_1(s_1(x)) -> x r18: minus_2(x,|0|_0()) -> x r19: minus_2(x,s_1(y)) -> pred_1(minus_2(x,y)) r20: quot_2(|0|_0(),s_1(y)) -> |0|_0() r21: quot_2(s_1(x),s_1(y)) -> s_1(quot_2(minus_2(x,y),s_1(y))) r22: map_2(f,nil_0()) -> nil_0() r23: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r24: filter_2(f,nil_0()) -> nil_0() r25: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r26: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r27: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of r1, r2, r3, r5, r6, r7, r9, r11, r12, r13, r14, r16, r17, r18, r19, r24 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: quot_2#_A(x1,x2) = x1 + x2 s_1_A(x1) = x1 + 4 minus_2_A(x1,x2) = x1 + 3 app_A(x1,x2) = x1 + x2 + 4 cons_0_A() = 1 cons_1_A(x1) = x1 + 2 cons_2_A(x1,x2) = x1 + x2 + 3 filter_0_A() = 1 filter_1_A(x1) = x1 + 2 filter2_0_A() = 1 filter2_1_A(x1) = x1 + 2 filter2_2_A(x1,x2) = x1 + x2 + 3 filter2_3_A(x1,x2,x3) = x1 + x2 + x3 + 4 map_0_A() = 1 map_1_A(x1) = x1 + 2 minus_0_A() = 1 minus_1_A(x1) = x1 + 2 pred_0_A() = 1 pred_1_A(x1) = x1 quot_0_A() = 1 quot_1_A(x1) = x1 + 3 s_0_A() = 5 |0|_0_A() = 1 filter_2_A(x1,x2) = x1 + x2 + 3 nil_0_A() = 1 base order 2: precedence: cons_2 = filter_2 > minus_2 = app = pred_1 = s_0 = nil_0 > quot_2# = s_1 = cons_1 = filter_1 = filter2_1 = filter2_3 = map_1 = minus_1 = pred_0 > cons_0 = filter_0 = filter2_0 = filter2_2 = map_0 = minus_0 = quot_1 = |0|_0 > quot_0 partial status: pi(quot_2#) = [2] pi(s_1) = [] pi(minus_2) = [] pi(app) = [2] pi(cons_0) = [] pi(cons_1) = [1] pi(cons_2) = [1] pi(filter_0) = [] pi(filter_1) = [1] pi(filter2_0) = [] pi(filter2_1) = [1] pi(filter2_2) = [1, 2] pi(filter2_3) = [3] pi(map_0) = [] pi(map_1) = [1] pi(minus_0) = [] pi(minus_1) = [1] pi(pred_0) = [] pi(pred_1) = [] pi(quot_0) = [] pi(quot_1) = [1] pi(s_0) = [] pi(|0|_0) = [] pi(filter_2) = [2] pi(nil_0) = [] The following rules are removed: p1 Then no dependency pair remains. -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: minus_2#(x,s_1(y)) -> minus_2#(x,y) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(filter_0(),y) -> filter_1(y) r4: app(filter_1(x1),y) -> filter_2(x1,y) r5: app(filter2_0(),y) -> filter2_1(y) r6: app(filter2_1(x1),y) -> filter2_2(x1,y) r7: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r8: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r9: app(map_0(),y) -> map_1(y) r10: app(map_1(x1),y) -> map_2(x1,y) r11: app(minus_0(),y) -> minus_1(y) r12: app(minus_1(x1),y) -> minus_2(x1,y) r13: app(pred_0(),y) -> pred_1(y) r14: app(quot_0(),y) -> quot_1(y) r15: app(quot_1(x1),y) -> quot_2(x1,y) r16: app(s_0(),y) -> s_1(y) r17: pred_1(s_1(x)) -> x r18: minus_2(x,|0|_0()) -> x r19: minus_2(x,s_1(y)) -> pred_1(minus_2(x,y)) r20: quot_2(|0|_0(),s_1(y)) -> |0|_0() r21: quot_2(s_1(x),s_1(y)) -> s_1(quot_2(minus_2(x,y),s_1(y))) r22: map_2(f,nil_0()) -> nil_0() r23: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r24: filter_2(f,nil_0()) -> nil_0() r25: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r26: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r27: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of r1, r3, r5, r7, r9, r11, r14, r16, r20, r24 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: minus_2#_A(x1,x2) = x1 + x2 + 3 s_1_A(x1) = x1 + 2 app_A(x1,x2) = x2 + 5 cons_0_A() = 1 cons_1_A(x1) = x1 + 2 filter_0_A() = 2 filter_1_A(x1) = 1 filter2_0_A() = 2 filter2_1_A(x1) = 1 filter2_2_A(x1,x2) = x1 + 2 filter2_3_A(x1,x2,x3) = 3 map_0_A() = 2 map_1_A(x1) = 1 minus_0_A() = 2 minus_1_A(x1) = 1 quot_0_A() = 2 quot_1_A(x1) = 1 s_0_A() = 1 quot_2_A(x1,x2) = x1 + 6 |0|_0_A() = 1 filter_2_A(x1,x2) = x1 + 6 nil_0_A() = 1 base order 2: precedence: minus_2# = app = cons_0 = filter_0 = filter2_0 = map_0 = minus_0 = quot_0 = s_0 = filter_2 > s_1 = cons_1 = filter_1 = filter2_3 = minus_1 = quot_2 = |0|_0 > filter2_2 = map_1 = quot_1 = nil_0 > filter2_1 partial status: pi(minus_2#) = [1] pi(s_1) = [1] pi(app) = [] pi(cons_0) = [] pi(cons_1) = [1] pi(filter_0) = [] pi(filter_1) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [1] pi(filter2_3) = [] pi(map_0) = [] pi(map_1) = [] pi(minus_0) = [] pi(minus_1) = [] pi(quot_0) = [] pi(quot_1) = [] pi(s_0) = [] pi(quot_2) = [1] pi(|0|_0) = [] pi(filter_2) = [1] pi(nil_0) = [] The following rules are removed: p1 Then no dependency pair remains.