YES We show the termination of the TRS R: app(app(app(f(),|0|()),|1|()),x) -> app(app(app(f(),app(s(),x)),x),x) app(app(app(f(),x),y),app(s(),z)) -> app(s(),app(app(app(f(),|0|()),|1|()),z)) app(app(map(),|fun|),nil()) -> nil() app(app(map(),|fun|),app(app(cons(),x),xs)) -> app(app(cons(),app(|fun|,x)),app(app(map(),|fun|),xs)) app(app(filter(),|fun|),nil()) -> nil() app(app(filter(),|fun|),app(app(cons(),x),xs)) -> app(app(app(app(filter2(),app(|fun|,x)),|fun|),x),xs) app(app(app(app(filter2(),true()),|fun|),x),xs) -> app(app(cons(),x),app(app(filter(),|fun|),xs)) app(app(app(app(filter2(),false()),|fun|),x),xs) -> app(app(filter(),|fun|),xs) Instead we prove termination of the uncurried system: app(cons_0(),y) -> cons_1(y) app(cons_1(x1),y) -> cons_2(x1,y) app(f_0(),y) -> f_1(y) app(f_1(x1),y) -> f_2(x1,y) app(f_2(x1,x2),y) -> f_3(x1,x2,y) app(filter_0(),y) -> filter_1(y) app(filter_1(x1),y) -> filter_2(x1,y) app(filter2_0(),y) -> filter2_1(y) app(filter2_1(x1),y) -> filter2_2(x1,y) app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) app(map_0(),y) -> map_1(y) app(map_1(x1),y) -> map_2(x1,y) app(s_0(),y) -> s_1(y) f_3(|0|_0(),|1|_0(),x) -> f_3(s_1(x),x,x) f_3(x,y,s_1(z)) -> s_1(f_3(|0|_0(),|1|_0(),z)) map_2(|fun|,nil_0()) -> nil_0() map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) filter_2(|fun|,nil_0()) -> nil_0() filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: app#(f_2(x1,x2),y) -> f_3#(x1,x2,y) p2: app#(filter_1(x1),y) -> filter_2#(x1,y) p3: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p4: app#(map_1(x1),y) -> map_2#(x1,y) p5: f_3#(|0|_0(),|1|_0(),x) -> f_3#(s_1(x),x,x) p6: f_3#(x,y,s_1(z)) -> f_3#(|0|_0(),|1|_0(),z) p7: map_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p8: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) p9: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p10: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p11: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p12: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y) r6: app(filter_0(),y) -> filter_1(y) r7: app(filter_1(x1),y) -> filter_2(x1,y) r8: app(filter2_0(),y) -> filter2_1(y) r9: app(filter2_1(x1),y) -> filter2_2(x1,y) r10: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r11: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r12: app(map_0(),y) -> map_1(y) r13: app(map_1(x1),y) -> map_2(x1,y) r14: app(s_0(),y) -> s_1(y) r15: f_3(|0|_0(),|1|_0(),x) -> f_3(s_1(x),x,x) r16: f_3(x,y,s_1(z)) -> s_1(f_3(|0|_0(),|1|_0(),z)) r17: map_2(|fun|,nil_0()) -> nil_0() r18: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r19: filter_2(|fun|,nil_0()) -> nil_0() r20: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r21: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r22: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The estimated dependency graph contains the following SCCs: {p2, p3, p4, p7, p8, p9, p10, p11, p12} {p5, p6} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p2: app#(map_1(x1),y) -> map_2#(x1,y) p3: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) p4: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p5: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p6: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p7: app#(filter_1(x1),y) -> filter_2#(x1,y) p8: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p9: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y) r6: app(filter_0(),y) -> filter_1(y) r7: app(filter_1(x1),y) -> filter_2(x1,y) r8: app(filter2_0(),y) -> filter2_1(y) r9: app(filter2_1(x1),y) -> filter2_2(x1,y) r10: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r11: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r12: app(map_0(),y) -> map_1(y) r13: app(map_1(x1),y) -> map_2(x1,y) r14: app(s_0(),y) -> s_1(y) r15: f_3(|0|_0(),|1|_0(),x) -> f_3(s_1(x),x,x) r16: f_3(x,y,s_1(z)) -> s_1(f_3(|0|_0(),|1|_0(),z)) r17: map_2(|fun|,nil_0()) -> nil_0() r18: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r19: filter_2(|fun|,nil_0()) -> nil_0() r20: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r21: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r22: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r1, r2, r3, r4, r6, r8, r9, r10, r12, r14, r19 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: map_2#_A(x1,x2) = x1 + x2 + 6 cons_2_A(x1,x2) = x1 + x2 + 5 app#_A(x1,x2) = x1 + x2 + 4 map_1_A(x1) = x1 + 3 filter2_3_A(x1,x2,x3) = x1 + x2 + x3 + 4 filter2_4#_A(x1,x2,x3,x4) = x2 + x4 + 6 false_0_A() = 1 filter_2#_A(x1,x2) = x1 + x2 + 5 filter_1_A(x1) = x1 + 2 app_A(x1,x2) = x1 + x2 + 9 true_0_A() = 1 cons_0_A() = 1 cons_1_A(x1) = x1 + 2 f_0_A() = 1 f_1_A(x1) = x1 + 2 f_2_A(x1,x2) = x1 + x2 + 3 filter_0_A() = 1 filter2_0_A() = 1 filter2_1_A(x1) = x1 + 2 filter2_2_A(x1,x2) = x1 + x2 + 3 map_0_A() = 1 s_0_A() = 1 s_1_A(x1) = x1 + 5 filter_2_A(x1,x2) = x1 + x2 + 3 nil_0_A() = 1 base order 2: precedence: app# > filter2_4# > map_2# = filter_2# > cons_2 = app > map_1 = filter2_3 = cons_1 = s_1 = filter_2 > false_0 = filter_1 = true_0 = cons_0 = filter2_2 = map_0 = s_0 = nil_0 > f_2 = filter_0 = filter2_1 > f_1 = filter2_0 > f_0 partial status: pi(map_2#) = [] pi(cons_2) = [] pi(app#) = [2] pi(map_1) = [1] pi(filter2_3) = [2] pi(filter2_4#) = [] pi(false_0) = [] pi(filter_2#) = [2] pi(filter_1) = [1] pi(app) = [2] pi(true_0) = [] pi(cons_0) = [] pi(cons_1) = [1] pi(f_0) = [] pi(f_1) = [1] pi(f_2) = [2] pi(filter_0) = [] pi(filter2_0) = [] pi(filter2_1) = [1] pi(filter2_2) = [2] pi(map_0) = [] pi(s_0) = [] pi(s_1) = [1] pi(filter_2) = [2] pi(nil_0) = [] The following rules are removed: p1 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: app#(map_1(x1),y) -> map_2#(x1,y) p2: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) p3: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p4: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p5: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p6: app#(filter_1(x1),y) -> filter_2#(x1,y) p7: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p8: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y) r6: app(filter_0(),y) -> filter_1(y) r7: app(filter_1(x1),y) -> filter_2(x1,y) r8: app(filter2_0(),y) -> filter2_1(y) r9: app(filter2_1(x1),y) -> filter2_2(x1,y) r10: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r11: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r12: app(map_0(),y) -> map_1(y) r13: app(map_1(x1),y) -> map_2(x1,y) r14: app(s_0(),y) -> s_1(y) r15: f_3(|0|_0(),|1|_0(),x) -> f_3(s_1(x),x,x) r16: f_3(x,y,s_1(z)) -> s_1(f_3(|0|_0(),|1|_0(),z)) r17: map_2(|fun|,nil_0()) -> nil_0() r18: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r19: filter_2(|fun|,nil_0()) -> nil_0() r20: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r21: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r22: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The estimated dependency graph contains the following SCCs: {p3, p4, p5, p6, p7, p8} {p2} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p2: app#(filter_1(x1),y) -> filter_2#(x1,y) p3: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p4: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p5: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p6: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y) r6: app(filter_0(),y) -> filter_1(y) r7: app(filter_1(x1),y) -> filter_2(x1,y) r8: app(filter2_0(),y) -> filter2_1(y) r9: app(filter2_1(x1),y) -> filter2_2(x1,y) r10: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r11: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r12: app(map_0(),y) -> map_1(y) r13: app(map_1(x1),y) -> map_2(x1,y) r14: app(s_0(),y) -> s_1(y) r15: f_3(|0|_0(),|1|_0(),x) -> f_3(s_1(x),x,x) r16: f_3(x,y,s_1(z)) -> s_1(f_3(|0|_0(),|1|_0(),z)) r17: map_2(|fun|,nil_0()) -> nil_0() r18: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r19: filter_2(|fun|,nil_0()) -> nil_0() r20: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r21: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r22: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r1, r2, r3, r4, r6, r8, r9, r10, r12, r14, r19 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: filter_2#_A(x1,x2) = x1 + x2 + 6 cons_2_A(x1,x2) = x1 + x2 + 3 app#_A(x1,x2) = x1 + x2 + 5 filter_1_A(x1) = x1 + 2 filter2_4#_A(x1,x2,x3,x4) = x2 + x4 + 7 app_A(x1,x2) = x1 + x2 + 8 true_0_A() = 1 false_0_A() = 1 filter2_3_A(x1,x2,x3) = x1 + x2 + x3 + 4 cons_0_A() = 1 cons_1_A(x1) = x1 + 2 f_0_A() = 2 f_1_A(x1) = x1 + 1 f_2_A(x1,x2) = x1 + x2 + 2 filter_0_A() = 1 filter2_0_A() = 1 filter2_1_A(x1) = x1 + 2 filter2_2_A(x1,x2) = x1 + x2 + 3 map_0_A() = 1 map_1_A(x1) = x1 + 2 s_0_A() = 3 s_1_A(x1) = x1 + 2 filter_2_A(x1,x2) = x1 + x2 + 6 nil_0_A() = 1 base order 2: precedence: app# > cons_2 = filter2_4# > filter_2# = filter_2 > app = true_0 = false_0 = filter_0 > filter_1 = filter2_3 = cons_1 = s_1 > cons_0 = filter2_2 = map_1 = s_0 = nil_0 > f_2 = filter2_1 = map_0 > f_1 = filter2_0 > f_0 partial status: pi(filter_2#) = [] pi(cons_2) = [] pi(app#) = [2] pi(filter_1) = [1] pi(filter2_4#) = [] pi(app) = [] pi(true_0) = [] pi(false_0) = [] pi(filter2_3) = [3] pi(cons_0) = [] pi(cons_1) = [1] pi(f_0) = [] pi(f_1) = [1] pi(f_2) = [1, 2] pi(filter_0) = [] pi(filter2_0) = [] pi(filter2_1) = [1] pi(filter2_2) = [1, 2] pi(map_0) = [] pi(map_1) = [1] pi(s_0) = [] pi(s_1) = [] pi(filter_2) = [2] pi(nil_0) = [] The following rules are removed: p1 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: app#(filter_1(x1),y) -> filter_2#(x1,y) p2: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p3: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p4: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p5: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y) r6: app(filter_0(),y) -> filter_1(y) r7: app(filter_1(x1),y) -> filter_2(x1,y) r8: app(filter2_0(),y) -> filter2_1(y) r9: app(filter2_1(x1),y) -> filter2_2(x1,y) r10: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r11: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r12: app(map_0(),y) -> map_1(y) r13: app(map_1(x1),y) -> map_2(x1,y) r14: app(s_0(),y) -> s_1(y) r15: f_3(|0|_0(),|1|_0(),x) -> f_3(s_1(x),x,x) r16: f_3(x,y,s_1(z)) -> s_1(f_3(|0|_0(),|1|_0(),z)) r17: map_2(|fun|,nil_0()) -> nil_0() r18: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r19: filter_2(|fun|,nil_0()) -> nil_0() r20: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r21: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r22: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The estimated dependency graph contains the following SCCs: {p2, p3, p4} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p2: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p3: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y) r6: app(filter_0(),y) -> filter_1(y) r7: app(filter_1(x1),y) -> filter_2(x1,y) r8: app(filter2_0(),y) -> filter2_1(y) r9: app(filter2_1(x1),y) -> filter2_2(x1,y) r10: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r11: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r12: app(map_0(),y) -> map_1(y) r13: app(map_1(x1),y) -> map_2(x1,y) r14: app(s_0(),y) -> s_1(y) r15: f_3(|0|_0(),|1|_0(),x) -> f_3(s_1(x),x,x) r16: f_3(x,y,s_1(z)) -> s_1(f_3(|0|_0(),|1|_0(),z)) r17: map_2(|fun|,nil_0()) -> nil_0() r18: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r19: filter_2(|fun|,nil_0()) -> nil_0() r20: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r21: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r22: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r1, r2, r3, r4, r6, r8, r9, r12, r14, r19 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: filter_2#_A(x1,x2) = x2 + 2 cons_2_A(x1,x2) = x1 + x2 + 6 filter2_4#_A(x1,x2,x3,x4) = x4 + 3 app_A(x1,x2) = x1 + x2 + 2 false_0_A() = 1 true_0_A() = 3 cons_0_A() = 4 cons_1_A(x1) = x1 + 5 f_0_A() = 1 f_1_A(x1) = x1 + 2 f_2_A(x1,x2) = x1 + x2 + 3 filter_0_A() = 2 filter_1_A(x1) = x1 + 3 filter2_0_A() = 1 filter2_1_A(x1) = x1 + 2 filter2_2_A(x1,x2) = x1 + 1 map_0_A() = 5 map_1_A(x1) = x1 + 6 s_0_A() = 1 s_1_A(x1) = x1 + 2 filter_2_A(x1,x2) = x1 + 4 nil_0_A() = 0 base order 2: precedence: cons_2 = filter_2 > app = true_0 = s_0 > filter_2# = cons_1 = filter_1 = filter2_2 = map_1 = s_1 = nil_0 > filter2_4# = false_0 = cons_0 = filter_0 = filter2_1 = map_0 > f_2 = filter2_0 > f_1 > f_0 partial status: pi(filter_2#) = [] pi(cons_2) = [2] pi(filter2_4#) = [] pi(app) = [] pi(false_0) = [] pi(true_0) = [] pi(cons_0) = [] pi(cons_1) = [1] pi(f_0) = [] pi(f_1) = [1] pi(f_2) = [2] pi(filter_0) = [] pi(filter_1) = [1] pi(filter2_0) = [] pi(filter2_1) = [1] pi(filter2_2) = [1] pi(map_0) = [] pi(map_1) = [1] pi(s_0) = [] pi(s_1) = [1] pi(filter_2) = [1] pi(nil_0) = [] The following rules are removed: p1 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p2: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y) r6: app(filter_0(),y) -> filter_1(y) r7: app(filter_1(x1),y) -> filter_2(x1,y) r8: app(filter2_0(),y) -> filter2_1(y) r9: app(filter2_1(x1),y) -> filter2_2(x1,y) r10: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r11: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r12: app(map_0(),y) -> map_1(y) r13: app(map_1(x1),y) -> map_2(x1,y) r14: app(s_0(),y) -> s_1(y) r15: f_3(|0|_0(),|1|_0(),x) -> f_3(s_1(x),x,x) r16: f_3(x,y,s_1(z)) -> s_1(f_3(|0|_0(),|1|_0(),z)) r17: map_2(|fun|,nil_0()) -> nil_0() r18: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r19: filter_2(|fun|,nil_0()) -> nil_0() r20: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r21: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r22: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The estimated dependency graph contains the following SCCs: (no SCCs) -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y) r6: app(filter_0(),y) -> filter_1(y) r7: app(filter_1(x1),y) -> filter_2(x1,y) r8: app(filter2_0(),y) -> filter2_1(y) r9: app(filter2_1(x1),y) -> filter2_2(x1,y) r10: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r11: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r12: app(map_0(),y) -> map_1(y) r13: app(map_1(x1),y) -> map_2(x1,y) r14: app(s_0(),y) -> s_1(y) r15: f_3(|0|_0(),|1|_0(),x) -> f_3(s_1(x),x,x) r16: f_3(x,y,s_1(z)) -> s_1(f_3(|0|_0(),|1|_0(),z)) r17: map_2(|fun|,nil_0()) -> nil_0() r18: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r19: filter_2(|fun|,nil_0()) -> nil_0() r20: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r21: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r22: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r1, r3, r4, r6, r8, r9, r10, r12, r14, r19, r20, r21, r22 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: map_2#_A(x1,x2) = x2 cons_2_A(x1,x2) = x1 + x2 + 6 app_A(x1,x2) = x2 + 5 cons_0_A() = 1 cons_1_A(x1) = x1 + 2 f_0_A() = 3 f_1_A(x1) = 2 f_2_A(x1,x2) = 1 filter_0_A() = 2 filter_1_A(x1) = 1 filter2_0_A() = 4 filter2_1_A(x1) = 3 filter2_2_A(x1,x2) = 2 filter2_3_A(x1,x2,x3) = 1 map_0_A() = 2 map_1_A(x1) = 1 s_0_A() = 1 s_1_A(x1) = x1 + 2 filter_2_A(x1,x2) = x1 + x2 + 6 nil_0_A() = 1 filter2_4_A(x1,x2,x3,x4) = x2 + x3 + x4 + 12 true_0_A() = 1 false_0_A() = 1 base order 2: precedence: filter_2 > cons_1 = filter2_4 > app = filter_0 = filter2_0 = s_0 > cons_2 = cons_0 = f_0 = filter_1 = filter2_1 = filter2_3 = map_0 = s_1 = false_0 > map_2# = f_1 = filter2_2 = map_1 = nil_0 = true_0 > f_2 partial status: pi(map_2#) = [] pi(cons_2) = [1] pi(app) = [2] pi(cons_0) = [] pi(cons_1) = [1] pi(f_0) = [] pi(f_1) = [] pi(f_2) = [] pi(filter_0) = [] pi(filter_1) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(filter2_3) = [] pi(map_0) = [] pi(map_1) = [] pi(s_0) = [] pi(s_1) = [] pi(filter_2) = [] pi(nil_0) = [] pi(filter2_4) = [3, 4] pi(true_0) = [] pi(false_0) = [] The following rules are removed: p1 Then no dependency pair remains. -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: f_3#(|0|_0(),|1|_0(),x) -> f_3#(s_1(x),x,x) p2: f_3#(x,y,s_1(z)) -> f_3#(|0|_0(),|1|_0(),z) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y) r6: app(filter_0(),y) -> filter_1(y) r7: app(filter_1(x1),y) -> filter_2(x1,y) r8: app(filter2_0(),y) -> filter2_1(y) r9: app(filter2_1(x1),y) -> filter2_2(x1,y) r10: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r11: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r12: app(map_0(),y) -> map_1(y) r13: app(map_1(x1),y) -> map_2(x1,y) r14: app(s_0(),y) -> s_1(y) r15: f_3(|0|_0(),|1|_0(),x) -> f_3(s_1(x),x,x) r16: f_3(x,y,s_1(z)) -> s_1(f_3(|0|_0(),|1|_0(),z)) r17: map_2(|fun|,nil_0()) -> nil_0() r18: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r19: filter_2(|fun|,nil_0()) -> nil_0() r20: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r21: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r22: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r1, r3, r4, r6, r8, r9, r10, r12, r14, r19 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: f_3#_A(x1,x2,x3) = x3 + 2 |0|_0_A() = 1 |1|_0_A() = 3 s_1_A(x1) = x1 + 4 app_A(x1,x2) = x2 + 5 cons_0_A() = 1 cons_1_A(x1) = 2 f_0_A() = 3 f_1_A(x1) = 2 f_2_A(x1,x2) = 1 filter_0_A() = 2 filter_1_A(x1) = 1 filter2_0_A() = 5 filter2_1_A(x1) = 4 filter2_2_A(x1,x2) = 3 filter2_3_A(x1,x2,x3) = 2 map_0_A() = 2 map_1_A(x1) = 1 s_0_A() = 1 filter_2_A(x1,x2) = x1 + x2 + 6 nil_0_A() = 1 base order 2: precedence: filter_2 > app = f_0 = filter_0 = filter2_0 = map_0 > |1|_0 = s_1 = cons_1 = f_1 = filter_1 = filter2_1 = map_1 = nil_0 > f_3# = cons_0 = f_2 = filter2_2 = filter2_3 = s_0 > |0|_0 partial status: pi(f_3#) = [] pi(|0|_0) = [] pi(|1|_0) = [] pi(s_1) = [] pi(app) = [2] pi(cons_0) = [] pi(cons_1) = [] pi(f_0) = [] pi(f_1) = [] pi(f_2) = [] pi(filter_0) = [] pi(filter_1) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(filter2_3) = [] pi(map_0) = [] pi(map_1) = [] pi(s_0) = [] pi(filter_2) = [2] pi(nil_0) = [] The following rules are removed: p2 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: f_3#(|0|_0(),|1|_0(),x) -> f_3#(s_1(x),x,x) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y) r6: app(filter_0(),y) -> filter_1(y) r7: app(filter_1(x1),y) -> filter_2(x1,y) r8: app(filter2_0(),y) -> filter2_1(y) r9: app(filter2_1(x1),y) -> filter2_2(x1,y) r10: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r11: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r12: app(map_0(),y) -> map_1(y) r13: app(map_1(x1),y) -> map_2(x1,y) r14: app(s_0(),y) -> s_1(y) r15: f_3(|0|_0(),|1|_0(),x) -> f_3(s_1(x),x,x) r16: f_3(x,y,s_1(z)) -> s_1(f_3(|0|_0(),|1|_0(),z)) r17: map_2(|fun|,nil_0()) -> nil_0() r18: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r19: filter_2(|fun|,nil_0()) -> nil_0() r20: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r21: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r22: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The estimated dependency graph contains the following SCCs: (no SCCs)