YES
We show the termination of the TRS R:

  app(app(minus(),x),|0|()) -> x
  app(app(minus(),app(s(),x)),app(s(),y)) -> app(app(minus(),x),y)
  app(double(),|0|()) -> |0|()
  app(double(),app(s(),x)) -> app(s(),app(s(),app(double(),x)))
  app(app(plus(),|0|()),y) -> y
  app(app(plus(),app(s(),x)),y) -> app(s(),app(app(plus(),x),y))
  app(app(plus(),app(s(),x)),y) -> app(app(plus(),x),app(s(),y))
  app(app(plus(),app(s(),x)),y) -> app(s(),app(app(plus(),app(app(minus(),x),y)),app(double(),y)))
  app(app(map(),f),nil()) -> nil()
  app(app(map(),f),app(app(cons(),x),xs)) -> app(app(cons(),app(f,x)),app(app(map(),f),xs))
  app(app(filter(),f),nil()) -> nil()
  app(app(filter(),f),app(app(cons(),x),xs)) -> app(app(app(app(filter2(),app(f,x)),f),x),xs)
  app(app(app(app(filter2(),true()),f),x),xs) -> app(app(cons(),x),app(app(filter(),f),xs))
  app(app(app(app(filter2(),false()),f),x),xs) -> app(app(filter(),f),xs)

Instead we prove termination of the uncurried system:

  app(cons_0(),y) -> cons_1(y)
  app(cons_1(x1),y) -> cons_2(x1,y)
  app(double_0(),y) -> double_1(y)
  app(filter_0(),y) -> filter_1(y)
  app(filter_1(x1),y) -> filter_2(x1,y)
  app(filter2_0(),y) -> filter2_1(y)
  app(filter2_1(x1),y) -> filter2_2(x1,y)
  app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
  app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
  app(map_0(),y) -> map_1(y)
  app(map_1(x1),y) -> map_2(x1,y)
  app(minus_0(),y) -> minus_1(y)
  app(minus_1(x1),y) -> minus_2(x1,y)
  app(plus_0(),y) -> plus_1(y)
  app(plus_1(x1),y) -> plus_2(x1,y)
  app(s_0(),y) -> s_1(y)
  minus_2(x,|0|_0()) -> x
  minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
  double_1(|0|_0()) -> |0|_0()
  double_1(s_1(x)) -> s_1(s_1(double_1(x)))
  plus_2(|0|_0(),y) -> y
  plus_2(s_1(x),y) -> s_1(plus_2(x,y))
  plus_2(s_1(x),y) -> plus_2(x,s_1(y))
  plus_2(s_1(x),y) -> s_1(plus_2(minus_2(x,y),double_1(y)))
  map_2(f,nil_0()) -> nil_0()
  map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs))
  filter_2(f,nil_0()) -> nil_0()
  filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs)
  filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs))
  filter2_4(false_0(),f,x,xs) -> filter_2(f,xs)


-- SCC decomposition.

Consider the dependency pair problem (P, R), where P consists of

p1: app#(double_0(),y) -> double_1#(y)
p2: app#(filter_1(x1),y) -> filter_2#(x1,y)
p3: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y)
p4: app#(map_1(x1),y) -> map_2#(x1,y)
p5: app#(minus_1(x1),y) -> minus_2#(x1,y)
p6: app#(plus_1(x1),y) -> plus_2#(x1,y)
p7: minus_2#(s_1(x),s_1(y)) -> minus_2#(x,y)
p8: double_1#(s_1(x)) -> double_1#(x)
p9: plus_2#(s_1(x),y) -> plus_2#(x,y)
p10: plus_2#(s_1(x),y) -> plus_2#(x,s_1(y))
p11: plus_2#(s_1(x),y) -> plus_2#(minus_2(x,y),double_1(y))
p12: plus_2#(s_1(x),y) -> minus_2#(x,y)
p13: plus_2#(s_1(x),y) -> double_1#(y)
p14: map_2#(f,cons_2(x,xs)) -> app#(f,x)
p15: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs)
p16: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs)
p17: filter_2#(f,cons_2(x,xs)) -> app#(f,x)
p18: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs)
p19: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(double_0(),y) -> double_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(map_0(),y) -> map_1(y)
r11: app(map_1(x1),y) -> map_2(x1,y)
r12: app(minus_0(),y) -> minus_1(y)
r13: app(minus_1(x1),y) -> minus_2(x1,y)
r14: app(plus_0(),y) -> plus_1(y)
r15: app(plus_1(x1),y) -> plus_2(x1,y)
r16: app(s_0(),y) -> s_1(y)
r17: minus_2(x,|0|_0()) -> x
r18: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r19: double_1(|0|_0()) -> |0|_0()
r20: double_1(s_1(x)) -> s_1(s_1(double_1(x)))
r21: plus_2(|0|_0(),y) -> y
r22: plus_2(s_1(x),y) -> s_1(plus_2(x,y))
r23: plus_2(s_1(x),y) -> plus_2(x,s_1(y))
r24: plus_2(s_1(x),y) -> s_1(plus_2(minus_2(x,y),double_1(y)))
r25: map_2(f,nil_0()) -> nil_0()
r26: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs))
r27: filter_2(f,nil_0()) -> nil_0()
r28: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs)
r29: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs))
r30: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs)

The estimated dependency graph contains the following SCCs:

  {p2, p3, p4, p14, p15, p16, p17, p18, p19}
  {p9, p10, p11}
  {p8}
  {p7}


-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: map_2#(f,cons_2(x,xs)) -> app#(f,x)
p2: app#(map_1(x1),y) -> map_2#(x1,y)
p3: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs)
p4: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y)
p5: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs)
p6: filter_2#(f,cons_2(x,xs)) -> app#(f,x)
p7: app#(filter_1(x1),y) -> filter_2#(x1,y)
p8: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs)
p9: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(double_0(),y) -> double_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(map_0(),y) -> map_1(y)
r11: app(map_1(x1),y) -> map_2(x1,y)
r12: app(minus_0(),y) -> minus_1(y)
r13: app(minus_1(x1),y) -> minus_2(x1,y)
r14: app(plus_0(),y) -> plus_1(y)
r15: app(plus_1(x1),y) -> plus_2(x1,y)
r16: app(s_0(),y) -> s_1(y)
r17: minus_2(x,|0|_0()) -> x
r18: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r19: double_1(|0|_0()) -> |0|_0()
r20: double_1(s_1(x)) -> s_1(s_1(double_1(x)))
r21: plus_2(|0|_0(),y) -> y
r22: plus_2(s_1(x),y) -> s_1(plus_2(x,y))
r23: plus_2(s_1(x),y) -> plus_2(x,s_1(y))
r24: plus_2(s_1(x),y) -> s_1(plus_2(minus_2(x,y),double_1(y)))
r25: map_2(f,nil_0()) -> nil_0()
r26: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs))
r27: filter_2(f,nil_0()) -> nil_0()
r28: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs)
r29: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs))
r30: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs)

The set of usable rules consists of

  r1, r2, r6, r7, r12, r14, r16, r27

Take the reduction pair:

  generalized weighted path order (>=MG, >MG)
  
    base order 1:
  
      max/plus interpretation on natural numbers:
      
        map_2#_A(x1,x2) = max{7, x1 - 9}
        cons_2_A(x1,x2) = max{6, x1 - 38, x2 - 38}
        app#_A(x1,x2) = max{7, x1 - 9}
        map_1_A(x1) = max{7, x1 + 6}
        filter2_3_A(x1,x2,x3) = max{x1 + 17, x2 + 4, x3 + 10}
        filter2_4#_A(x1,x2,x3,x4) = max{7, x2 - 6}
        false_0_A = 1
        filter_2#_A(x1,x2) = max{7, x1 - 6}
        filter_1_A(x1) = x1 + 8
        app_A(x1,x2) = max{28, x1 - 18, x2 - 18}
        true_0_A = 5
        cons_0_A = 1
        cons_1_A(x1) = max{2, x1 - 19}
        filter2_0_A = 1
        filter2_1_A(x1) = max{2, x1 - 19}
        filter2_2_A(x1,x2) = max{3, x1 - 38, x2 - 19}
        minus_0_A = 19
        minus_1_A(x1) = max{20, x1 - 19}
        plus_0_A = 16
        plus_1_A(x1) = max{17, x1 - 19}
        s_0_A = 17
        s_1_A(x1) = max{22, x1 - 25}
        filter_2_A(x1,x2) = max{9, x1 - 40, x2 - 46}
        nil_0_A = 8
  
    base order 2:
  
      precedence:
      
        app = cons_0 = filter2_1 > filter2_0 = filter_2 > map_1 = false_0 = filter_1 = nil_0 > map_2# = cons_2 = app# = filter2_4# = filter_2# = cons_1 = plus_1 > filter2_3 = true_0 = minus_1 = plus_0 = s_1 > filter2_2 = minus_0 = s_0
      
  
    partial status:
  
      pi(map_2#) = []
      pi(cons_2) = []
      pi(app#) = []
      pi(map_1) = [1]
      pi(filter2_3) = [1, 3]
      pi(filter2_4#) = []
      pi(false_0) = []
      pi(filter_2#) = []
      pi(filter_1) = [1]
      pi(app) = []
      pi(true_0) = []
      pi(cons_0) = []
      pi(cons_1) = []
      pi(filter2_0) = []
      pi(filter2_1) = []
      pi(filter2_2) = []
      pi(minus_0) = []
      pi(minus_1) = []
      pi(plus_0) = []
      pi(plus_1) = []
      pi(s_0) = []
      pi(s_1) = []
      pi(filter_2) = []
      pi(nil_0) = []

The following rules are removed:

  p4



-- SCC decomposition.

Consider the dependency pair problem (P, R), where P consists of

p1: map_2#(f,cons_2(x,xs)) -> app#(f,x)
p2: app#(map_1(x1),y) -> map_2#(x1,y)
p3: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs)
p4: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs)
p5: filter_2#(f,cons_2(x,xs)) -> app#(f,x)
p6: app#(filter_1(x1),y) -> filter_2#(x1,y)
p7: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs)
p8: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(double_0(),y) -> double_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(map_0(),y) -> map_1(y)
r11: app(map_1(x1),y) -> map_2(x1,y)
r12: app(minus_0(),y) -> minus_1(y)
r13: app(minus_1(x1),y) -> minus_2(x1,y)
r14: app(plus_0(),y) -> plus_1(y)
r15: app(plus_1(x1),y) -> plus_2(x1,y)
r16: app(s_0(),y) -> s_1(y)
r17: minus_2(x,|0|_0()) -> x
r18: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r19: double_1(|0|_0()) -> |0|_0()
r20: double_1(s_1(x)) -> s_1(s_1(double_1(x)))
r21: plus_2(|0|_0(),y) -> y
r22: plus_2(s_1(x),y) -> s_1(plus_2(x,y))
r23: plus_2(s_1(x),y) -> plus_2(x,s_1(y))
r24: plus_2(s_1(x),y) -> s_1(plus_2(minus_2(x,y),double_1(y)))
r25: map_2(f,nil_0()) -> nil_0()
r26: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs))
r27: filter_2(f,nil_0()) -> nil_0()
r28: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs)
r29: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs))
r30: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs)

The estimated dependency graph contains the following SCCs:

  {p1, p2, p3, p4, p5, p6, p7, p8}


-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: map_2#(f,cons_2(x,xs)) -> app#(f,x)
p2: app#(filter_1(x1),y) -> filter_2#(x1,y)
p3: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs)
p4: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs)
p5: filter_2#(f,cons_2(x,xs)) -> app#(f,x)
p6: app#(map_1(x1),y) -> map_2#(x1,y)
p7: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs)
p8: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(double_0(),y) -> double_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(map_0(),y) -> map_1(y)
r11: app(map_1(x1),y) -> map_2(x1,y)
r12: app(minus_0(),y) -> minus_1(y)
r13: app(minus_1(x1),y) -> minus_2(x1,y)
r14: app(plus_0(),y) -> plus_1(y)
r15: app(plus_1(x1),y) -> plus_2(x1,y)
r16: app(s_0(),y) -> s_1(y)
r17: minus_2(x,|0|_0()) -> x
r18: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r19: double_1(|0|_0()) -> |0|_0()
r20: double_1(s_1(x)) -> s_1(s_1(double_1(x)))
r21: plus_2(|0|_0(),y) -> y
r22: plus_2(s_1(x),y) -> s_1(plus_2(x,y))
r23: plus_2(s_1(x),y) -> plus_2(x,s_1(y))
r24: plus_2(s_1(x),y) -> s_1(plus_2(minus_2(x,y),double_1(y)))
r25: map_2(f,nil_0()) -> nil_0()
r26: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs))
r27: filter_2(f,nil_0()) -> nil_0()
r28: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs)
r29: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs))
r30: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs)

The set of usable rules consists of

  r1, r4, r6, r8, r10, r12, r14, r16, r27

Take the reduction pair:

  generalized weighted path order (>=MG, >MG)
  
    base order 1:
  
      max/plus interpretation on natural numbers:
      
        map_2#_A(x1,x2) = max{4, x1 + 3}
        cons_2_A(x1,x2) = max{6, x1 - 16, x2 - 16}
        app#_A(x1,x2) = x1 + 2
        filter_1_A(x1) = x1 + 5
        filter_2#_A(x1,x2) = x1 + 4
        filter2_4#_A(x1,x2,x3,x4) = x2 + 4
        app_A(x1,x2) = max{12, x1 - 14, x2 + 5}
        true_0_A = 1
        map_1_A(x1) = max{6, x1 + 3}
        false_0_A = 4
        cons_0_A = 13
        cons_1_A(x1) = 4
        filter_0_A = 1
        filter2_0_A = 10
        filter2_1_A(x1) = max{11, x1 - 1}
        filter2_2_A(x1,x2) = max{13, x1 + 1, x2 + 6}
        filter2_3_A(x1,x2,x3) = max{0, x1 - 36, x2 - 9}
        map_0_A = 13
        minus_0_A = 9
        minus_1_A(x1) = max{10, x1 - 15}
        plus_0_A = 7
        plus_1_A(x1) = max{8, x1 - 1}
        s_0_A = 1
        s_1_A(x1) = max{6, x1 - 11}
        filter_2_A(x1,x2) = max{15, x1 + 13, x2 - 7}
        nil_0_A = 0
  
    base order 2:
  
      precedence:
      
        filter2_2 > app > cons_2 = cons_0 = filter_2 > filter_1 = map_1 = false_0 = cons_1 = filter2_1 = filter2_3 = minus_1 = plus_1 = nil_0 > filter_2# = filter2_4# = filter_0 = filter2_0 = map_0 = minus_0 = plus_0 = s_1 > app# = true_0 = s_0 > map_2#
      
  
    partial status:
  
      pi(map_2#) = [1]
      pi(cons_2) = []
      pi(app#) = [1]
      pi(filter_1) = [1]
      pi(filter_2#) = []
      pi(filter2_4#) = []
      pi(app) = []
      pi(true_0) = []
      pi(map_1) = [1]
      pi(false_0) = []
      pi(cons_0) = []
      pi(cons_1) = []
      pi(filter_0) = []
      pi(filter2_0) = []
      pi(filter2_1) = []
      pi(filter2_2) = [2]
      pi(filter2_3) = []
      pi(map_0) = []
      pi(minus_0) = []
      pi(minus_1) = []
      pi(plus_0) = []
      pi(plus_1) = []
      pi(s_0) = []
      pi(s_1) = []
      pi(filter_2) = [1]
      pi(nil_0) = []

The following rules are removed:

  p2



-- SCC decomposition.

Consider the dependency pair problem (P, R), where P consists of

p1: map_2#(f,cons_2(x,xs)) -> app#(f,x)
p2: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs)
p3: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs)
p4: filter_2#(f,cons_2(x,xs)) -> app#(f,x)
p5: app#(map_1(x1),y) -> map_2#(x1,y)
p6: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs)
p7: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(double_0(),y) -> double_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(map_0(),y) -> map_1(y)
r11: app(map_1(x1),y) -> map_2(x1,y)
r12: app(minus_0(),y) -> minus_1(y)
r13: app(minus_1(x1),y) -> minus_2(x1,y)
r14: app(plus_0(),y) -> plus_1(y)
r15: app(plus_1(x1),y) -> plus_2(x1,y)
r16: app(s_0(),y) -> s_1(y)
r17: minus_2(x,|0|_0()) -> x
r18: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r19: double_1(|0|_0()) -> |0|_0()
r20: double_1(s_1(x)) -> s_1(s_1(double_1(x)))
r21: plus_2(|0|_0(),y) -> y
r22: plus_2(s_1(x),y) -> s_1(plus_2(x,y))
r23: plus_2(s_1(x),y) -> plus_2(x,s_1(y))
r24: plus_2(s_1(x),y) -> s_1(plus_2(minus_2(x,y),double_1(y)))
r25: map_2(f,nil_0()) -> nil_0()
r26: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs))
r27: filter_2(f,nil_0()) -> nil_0()
r28: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs)
r29: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs))
r30: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs)

The estimated dependency graph contains the following SCCs:

  {p2, p3, p7}
  {p1, p5, p6}


-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs)
p2: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs)
p3: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(double_0(),y) -> double_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(map_0(),y) -> map_1(y)
r11: app(map_1(x1),y) -> map_2(x1,y)
r12: app(minus_0(),y) -> minus_1(y)
r13: app(minus_1(x1),y) -> minus_2(x1,y)
r14: app(plus_0(),y) -> plus_1(y)
r15: app(plus_1(x1),y) -> plus_2(x1,y)
r16: app(s_0(),y) -> s_1(y)
r17: minus_2(x,|0|_0()) -> x
r18: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r19: double_1(|0|_0()) -> |0|_0()
r20: double_1(s_1(x)) -> s_1(s_1(double_1(x)))
r21: plus_2(|0|_0(),y) -> y
r22: plus_2(s_1(x),y) -> s_1(plus_2(x,y))
r23: plus_2(s_1(x),y) -> plus_2(x,s_1(y))
r24: plus_2(s_1(x),y) -> s_1(plus_2(minus_2(x,y),double_1(y)))
r25: map_2(f,nil_0()) -> nil_0()
r26: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs))
r27: filter_2(f,nil_0()) -> nil_0()
r28: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs)
r29: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs))
r30: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs)

The set of usable rules consists of

  r1, r3, r4, r6, r12, r14, r16, r19, r20, r21, r27

Take the reduction pair:

  generalized weighted path order (>=MG, >MG)
  
    base order 1:
  
      max/plus interpretation on natural numbers:
      
        filter2_4#_A(x1,x2,x3,x4) = max{x3 + 11, x4 + 3}
        false_0_A = 1
        filter_2#_A(x1,x2) = max{2, x2 - 1}
        cons_2_A(x1,x2) = max{15, x1 + 13, x2 + 11}
        app_A(x1,x2) = x2 + 11
        true_0_A = 12
        cons_0_A = 1
        cons_1_A(x1) = max{10, x1}
        double_0_A = 1
        double_1_A(x1) = max{2, x1 - 15}
        filter_0_A = 11
        filter_1_A(x1) = max{10, x1}
        filter2_0_A = 1
        filter2_1_A(x1) = max{6, x1 - 11}
        minus_0_A = 1
        minus_1_A(x1) = max{6, x1}
        plus_0_A = 11
        plus_1_A(x1) = max{10, x1}
        s_0_A = 1
        s_1_A(x1) = max{0, x1 - 16}
        |0|_0_A = 0
        plus_2_A(x1,x2) = max{x1 - 30, x2 + 13}
        filter_2_A(x1,x2) = max{13, x1 - 12, x2 - 16}
        nil_0_A = 0
  
    base order 2:
  
      precedence:
      
        plus_2 = filter_2 > app > cons_2 = double_1 = filter_1 = plus_1 = nil_0 > filter2_4# = cons_1 = double_0 = filter_0 = minus_1 = plus_0 = s_1 = |0|_0 > filter_2# = cons_0 = filter2_1 = minus_0 = s_0 > false_0 = true_0 = filter2_0
      
  
    partial status:
  
      pi(filter2_4#) = []
      pi(false_0) = []
      pi(filter_2#) = []
      pi(cons_2) = [2]
      pi(app) = [2]
      pi(true_0) = []
      pi(cons_0) = []
      pi(cons_1) = [1]
      pi(double_0) = []
      pi(double_1) = []
      pi(filter_0) = []
      pi(filter_1) = [1]
      pi(filter2_0) = []
      pi(filter2_1) = []
      pi(minus_0) = []
      pi(minus_1) = [1]
      pi(plus_0) = []
      pi(plus_1) = [1]
      pi(s_0) = []
      pi(s_1) = []
      pi(|0|_0) = []
      pi(plus_2) = [2]
      pi(filter_2) = []
      pi(nil_0) = []

The following rules are removed:

  p3



-- SCC decomposition.

Consider the dependency pair problem (P, R), where P consists of

p1: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs)
p2: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(double_0(),y) -> double_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(map_0(),y) -> map_1(y)
r11: app(map_1(x1),y) -> map_2(x1,y)
r12: app(minus_0(),y) -> minus_1(y)
r13: app(minus_1(x1),y) -> minus_2(x1,y)
r14: app(plus_0(),y) -> plus_1(y)
r15: app(plus_1(x1),y) -> plus_2(x1,y)
r16: app(s_0(),y) -> s_1(y)
r17: minus_2(x,|0|_0()) -> x
r18: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r19: double_1(|0|_0()) -> |0|_0()
r20: double_1(s_1(x)) -> s_1(s_1(double_1(x)))
r21: plus_2(|0|_0(),y) -> y
r22: plus_2(s_1(x),y) -> s_1(plus_2(x,y))
r23: plus_2(s_1(x),y) -> plus_2(x,s_1(y))
r24: plus_2(s_1(x),y) -> s_1(plus_2(minus_2(x,y),double_1(y)))
r25: map_2(f,nil_0()) -> nil_0()
r26: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs))
r27: filter_2(f,nil_0()) -> nil_0()
r28: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs)
r29: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs))
r30: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs)

The estimated dependency graph contains the following SCCs:

  {p1, p2}


-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs)
p2: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(double_0(),y) -> double_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(map_0(),y) -> map_1(y)
r11: app(map_1(x1),y) -> map_2(x1,y)
r12: app(minus_0(),y) -> minus_1(y)
r13: app(minus_1(x1),y) -> minus_2(x1,y)
r14: app(plus_0(),y) -> plus_1(y)
r15: app(plus_1(x1),y) -> plus_2(x1,y)
r16: app(s_0(),y) -> s_1(y)
r17: minus_2(x,|0|_0()) -> x
r18: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r19: double_1(|0|_0()) -> |0|_0()
r20: double_1(s_1(x)) -> s_1(s_1(double_1(x)))
r21: plus_2(|0|_0(),y) -> y
r22: plus_2(s_1(x),y) -> s_1(plus_2(x,y))
r23: plus_2(s_1(x),y) -> plus_2(x,s_1(y))
r24: plus_2(s_1(x),y) -> s_1(plus_2(minus_2(x,y),double_1(y)))
r25: map_2(f,nil_0()) -> nil_0()
r26: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs))
r27: filter_2(f,nil_0()) -> nil_0()
r28: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs)
r29: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs))
r30: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs)

The set of usable rules consists of

  r1, r4, r6, r7, r8, r10, r12, r14

Take the reduction pair:

  generalized weighted path order (>=MG, >MG)
  
    base order 1:
  
      max/plus interpretation on natural numbers:
      
        filter2_4#_A(x1,x2,x3,x4) = max{x3 + 3, x4 + 21}
        false_0_A = 1
        filter_2#_A(x1,x2) = x2 + 20
        cons_2_A(x1,x2) = max{13, x1 - 16, x2 + 5}
        app_A(x1,x2) = max{15, x1 - 7, x2 - 7}
        cons_0_A = 5
        cons_1_A(x1) = max{6, x1 - 9}
        filter_0_A = 1
        filter_1_A(x1) = max{2, x1 - 8}
        filter2_0_A = 6
        filter2_1_A(x1) = max{1, x1 - 8}
        filter2_2_A(x1,x2) = max{2, x1 - 16, x2 - 8}
        filter2_3_A(x1,x2,x3) = max{3, x1 - 24, x2 - 16, x3 - 32}
        map_0_A = 5
        map_1_A(x1) = max{6, x1 - 8}
        minus_0_A = 5
        minus_1_A(x1) = max{6, x1 - 7}
        plus_0_A = 1
        plus_1_A(x1) = max{6, x1 - 8}
  
    base order 2:
  
      precedence:
      
        filter2_4# > filter_2# = app = filter_0 = filter2_0 > false_0 = cons_2 = filter_1 = map_1 = minus_1 = plus_1 > cons_1 = filter2_3 = map_0 = minus_0 = plus_0 > cons_0 = filter2_2 > filter2_1
      
  
    partial status:
  
      pi(filter2_4#) = [4]
      pi(false_0) = []
      pi(filter_2#) = []
      pi(cons_2) = [2]
      pi(app) = []
      pi(cons_0) = []
      pi(cons_1) = []
      pi(filter_0) = []
      pi(filter_1) = []
      pi(filter2_0) = []
      pi(filter2_1) = []
      pi(filter2_2) = []
      pi(filter2_3) = []
      pi(map_0) = []
      pi(map_1) = []
      pi(minus_0) = []
      pi(minus_1) = []
      pi(plus_0) = []
      pi(plus_1) = []

The following rules are removed:

  p2



-- SCC decomposition.

Consider the dependency pair problem (P, R), where P consists of

p1: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(double_0(),y) -> double_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(map_0(),y) -> map_1(y)
r11: app(map_1(x1),y) -> map_2(x1,y)
r12: app(minus_0(),y) -> minus_1(y)
r13: app(minus_1(x1),y) -> minus_2(x1,y)
r14: app(plus_0(),y) -> plus_1(y)
r15: app(plus_1(x1),y) -> plus_2(x1,y)
r16: app(s_0(),y) -> s_1(y)
r17: minus_2(x,|0|_0()) -> x
r18: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r19: double_1(|0|_0()) -> |0|_0()
r20: double_1(s_1(x)) -> s_1(s_1(double_1(x)))
r21: plus_2(|0|_0(),y) -> y
r22: plus_2(s_1(x),y) -> s_1(plus_2(x,y))
r23: plus_2(s_1(x),y) -> plus_2(x,s_1(y))
r24: plus_2(s_1(x),y) -> s_1(plus_2(minus_2(x,y),double_1(y)))
r25: map_2(f,nil_0()) -> nil_0()
r26: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs))
r27: filter_2(f,nil_0()) -> nil_0()
r28: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs)
r29: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs))
r30: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs)

The estimated dependency graph contains the following SCCs:

  (no SCCs)

-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: map_2#(f,cons_2(x,xs)) -> app#(f,x)
p2: app#(map_1(x1),y) -> map_2#(x1,y)
p3: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(double_0(),y) -> double_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(map_0(),y) -> map_1(y)
r11: app(map_1(x1),y) -> map_2(x1,y)
r12: app(minus_0(),y) -> minus_1(y)
r13: app(minus_1(x1),y) -> minus_2(x1,y)
r14: app(plus_0(),y) -> plus_1(y)
r15: app(plus_1(x1),y) -> plus_2(x1,y)
r16: app(s_0(),y) -> s_1(y)
r17: minus_2(x,|0|_0()) -> x
r18: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r19: double_1(|0|_0()) -> |0|_0()
r20: double_1(s_1(x)) -> s_1(s_1(double_1(x)))
r21: plus_2(|0|_0(),y) -> y
r22: plus_2(s_1(x),y) -> s_1(plus_2(x,y))
r23: plus_2(s_1(x),y) -> plus_2(x,s_1(y))
r24: plus_2(s_1(x),y) -> s_1(plus_2(minus_2(x,y),double_1(y)))
r25: map_2(f,nil_0()) -> nil_0()
r26: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs))
r27: filter_2(f,nil_0()) -> nil_0()
r28: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs)
r29: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs))
r30: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs)

The set of usable rules consists of

  r1, r2, r6, r7, r8, r10, r12, r14, r16, r27

Take the reduction pair:

  generalized weighted path order (>=MG, >MG)
  
    base order 1:
  
      max/plus interpretation on natural numbers:
      
        map_2#_A(x1,x2) = x1 + 9
        cons_2_A(x1,x2) = max{4, x1 - 30, x2 - 30}
        app#_A(x1,x2) = x1 + 8
        map_1_A(x1) = max{11, x1 + 10}
        app_A(x1,x2) = max{x1 - 12, x2 + 11}
        cons_0_A = 10
        cons_1_A(x1) = max{11, x1 - 1}
        filter2_0_A = 13
        filter2_1_A(x1) = max{8, x1 - 1}
        filter2_2_A(x1,x2) = max{9, x1 - 14, x2 - 1}
        filter2_3_A(x1,x2,x3) = max{10, x1 - 27, x2 - 14, x3 - 1}
        map_0_A = 1
        minus_0_A = 11
        minus_1_A(x1) = max{1, x1 - 13}
        plus_0_A = 1
        plus_1_A(x1) = max{10, x1 - 1}
        s_0_A = 7
        s_1_A(x1) = max{8, x1 - 11}
        filter_2_A(x1,x2) = max{5, x1 - 53, x2 - 38}
        nil_0_A = 0
  
    base order 2:
  
      precedence:
      
        filter_2 = nil_0 > app > app# = map_1 = filter2_2 = filter2_3 > cons_2 = filter2_1 = map_0 = plus_1 > map_2# = cons_1 = filter2_0 = minus_1 = plus_0 = s_1 > cons_0 = minus_0 = s_0
      
  
    partial status:
  
      pi(map_2#) = [1]
      pi(cons_2) = []
      pi(app#) = [1]
      pi(map_1) = [1]
      pi(app) = [2]
      pi(cons_0) = []
      pi(cons_1) = []
      pi(filter2_0) = []
      pi(filter2_1) = []
      pi(filter2_2) = []
      pi(filter2_3) = []
      pi(map_0) = []
      pi(minus_0) = []
      pi(minus_1) = []
      pi(plus_0) = []
      pi(plus_1) = []
      pi(s_0) = []
      pi(s_1) = []
      pi(filter_2) = []
      pi(nil_0) = []

The following rules are removed:

  p1



-- SCC decomposition.

Consider the dependency pair problem (P, R), where P consists of

p1: app#(map_1(x1),y) -> map_2#(x1,y)
p2: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(double_0(),y) -> double_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(map_0(),y) -> map_1(y)
r11: app(map_1(x1),y) -> map_2(x1,y)
r12: app(minus_0(),y) -> minus_1(y)
r13: app(minus_1(x1),y) -> minus_2(x1,y)
r14: app(plus_0(),y) -> plus_1(y)
r15: app(plus_1(x1),y) -> plus_2(x1,y)
r16: app(s_0(),y) -> s_1(y)
r17: minus_2(x,|0|_0()) -> x
r18: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r19: double_1(|0|_0()) -> |0|_0()
r20: double_1(s_1(x)) -> s_1(s_1(double_1(x)))
r21: plus_2(|0|_0(),y) -> y
r22: plus_2(s_1(x),y) -> s_1(plus_2(x,y))
r23: plus_2(s_1(x),y) -> plus_2(x,s_1(y))
r24: plus_2(s_1(x),y) -> s_1(plus_2(minus_2(x,y),double_1(y)))
r25: map_2(f,nil_0()) -> nil_0()
r26: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs))
r27: filter_2(f,nil_0()) -> nil_0()
r28: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs)
r29: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs))
r30: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs)

The estimated dependency graph contains the following SCCs:

  {p2}


-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(double_0(),y) -> double_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(map_0(),y) -> map_1(y)
r11: app(map_1(x1),y) -> map_2(x1,y)
r12: app(minus_0(),y) -> minus_1(y)
r13: app(minus_1(x1),y) -> minus_2(x1,y)
r14: app(plus_0(),y) -> plus_1(y)
r15: app(plus_1(x1),y) -> plus_2(x1,y)
r16: app(s_0(),y) -> s_1(y)
r17: minus_2(x,|0|_0()) -> x
r18: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r19: double_1(|0|_0()) -> |0|_0()
r20: double_1(s_1(x)) -> s_1(s_1(double_1(x)))
r21: plus_2(|0|_0(),y) -> y
r22: plus_2(s_1(x),y) -> s_1(plus_2(x,y))
r23: plus_2(s_1(x),y) -> plus_2(x,s_1(y))
r24: plus_2(s_1(x),y) -> s_1(plus_2(minus_2(x,y),double_1(y)))
r25: map_2(f,nil_0()) -> nil_0()
r26: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs))
r27: filter_2(f,nil_0()) -> nil_0()
r28: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs)
r29: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs))
r30: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs)

The set of usable rules consists of

  r1, r4, r6, r10, r12, r14, r16, r27

Take the reduction pair:

  generalized weighted path order (>=MG, >MG)
  
    base order 1:
  
      max/plus interpretation on natural numbers:
      
        map_2#_A(x1,x2) = max{x1 + 14, x2 + 23}
        cons_2_A(x1,x2) = max{12, x1 - 9, x2 + 1}
        app_A(x1,x2) = max{7, x2 - 9}
        cons_0_A = 8
        cons_1_A(x1) = max{7, x1 - 9}
        filter_0_A = 1
        filter_1_A(x1) = max{5, x1 - 9}
        filter2_0_A = 1
        filter2_1_A(x1) = max{7, x1 - 9}
        map_0_A = 1
        map_1_A(x1) = max{7, x1 - 9}
        minus_0_A = 1
        minus_1_A(x1) = max{2, x1 - 9}
        plus_0_A = 1
        plus_1_A(x1) = max{7, x1 - 9}
        s_0_A = 1
        s_1_A(x1) = max{4, x1 - 11}
        filter_2_A(x1,x2) = max{6, x1 - 11, x2 - 11}
        nil_0_A = 0
  
    base order 2:
  
      precedence:
      
        filter_2 > map_2# = cons_0 = map_0 = plus_0 = nil_0 > cons_2 > app > cons_1 = filter_1 = filter2_1 = map_1 = minus_1 = plus_1 = s_1 > filter_0 = filter2_0 = minus_0 = s_0
      
  
    partial status:
  
      pi(map_2#) = [2]
      pi(cons_2) = [2]
      pi(app) = []
      pi(cons_0) = []
      pi(cons_1) = []
      pi(filter_0) = []
      pi(filter_1) = []
      pi(filter2_0) = []
      pi(filter2_1) = []
      pi(map_0) = []
      pi(map_1) = []
      pi(minus_0) = []
      pi(minus_1) = []
      pi(plus_0) = []
      pi(plus_1) = []
      pi(s_0) = []
      pi(s_1) = []
      pi(filter_2) = []
      pi(nil_0) = []

The following rules are removed:

  p1

Then no dependency pair remains.

-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: plus_2#(s_1(x),y) -> plus_2#(minus_2(x,y),double_1(y))
p2: plus_2#(s_1(x),y) -> plus_2#(x,s_1(y))
p3: plus_2#(s_1(x),y) -> plus_2#(x,y)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(double_0(),y) -> double_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(map_0(),y) -> map_1(y)
r11: app(map_1(x1),y) -> map_2(x1,y)
r12: app(minus_0(),y) -> minus_1(y)
r13: app(minus_1(x1),y) -> minus_2(x1,y)
r14: app(plus_0(),y) -> plus_1(y)
r15: app(plus_1(x1),y) -> plus_2(x1,y)
r16: app(s_0(),y) -> s_1(y)
r17: minus_2(x,|0|_0()) -> x
r18: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r19: double_1(|0|_0()) -> |0|_0()
r20: double_1(s_1(x)) -> s_1(s_1(double_1(x)))
r21: plus_2(|0|_0(),y) -> y
r22: plus_2(s_1(x),y) -> s_1(plus_2(x,y))
r23: plus_2(s_1(x),y) -> plus_2(x,s_1(y))
r24: plus_2(s_1(x),y) -> s_1(plus_2(minus_2(x,y),double_1(y)))
r25: map_2(f,nil_0()) -> nil_0()
r26: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs))
r27: filter_2(f,nil_0()) -> nil_0()
r28: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs)
r29: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs))
r30: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs)

The set of usable rules consists of

  r1, r2, r4, r6, r7, r8, r10, r12, r14, r17, r18

Take the reduction pair:

  generalized weighted path order (>=MG, >MG)
  
    base order 1:
  
      max/plus interpretation on natural numbers:
      
        plus_2#_A(x1,x2) = max{1, x1 - 15}
        s_1_A(x1) = max{30, x1 + 17}
        minus_2_A(x1,x2) = max{14, x1}
        double_1_A(x1) = max{5, x1 - 35}
        app_A(x1,x2) = max{8, x1, x2 - 5}
        cons_0_A = 0
        cons_1_A(x1) = max{0, x1 - 6}
        cons_2_A(x1,x2) = max{2, x2 - 8}
        filter_0_A = 1
        filter_1_A(x1) = max{0, x1 - 6}
        filter2_0_A = 0
        filter2_1_A(x1) = max{0, x1 - 6}
        filter2_2_A(x1,x2) = max{0, x1 - 23, x2 - 6}
        filter2_3_A(x1,x2,x3) = max{0, x1 - 23, x2 - 6, x3 - 5}
        map_0_A = 0
        map_1_A(x1) = max{0, x1 - 6}
        minus_0_A = 2
        minus_1_A(x1) = 1
        plus_0_A = 0
        plus_1_A(x1) = max{0, x1 - 35}
        |0|_0_A = 0
  
    base order 2:
  
      precedence:
      
        s_1 = filter2_0 = minus_0 = plus_0 > minus_2 > minus_1 > app > plus_2# = double_1 = plus_1 > map_1 = |0|_0 > map_0 > cons_2 = filter_1 = filter2_3 > cons_1 = filter_0 = filter2_2 > cons_0 = filter2_1
      
  
    partial status:
  
      pi(plus_2#) = []
      pi(s_1) = [1]
      pi(minus_2) = [1]
      pi(double_1) = []
      pi(app) = [1]
      pi(cons_0) = []
      pi(cons_1) = []
      pi(cons_2) = []
      pi(filter_0) = []
      pi(filter_1) = []
      pi(filter2_0) = []
      pi(filter2_1) = []
      pi(filter2_2) = []
      pi(filter2_3) = []
      pi(map_0) = []
      pi(map_1) = []
      pi(minus_0) = []
      pi(minus_1) = []
      pi(plus_0) = []
      pi(plus_1) = []
      pi(|0|_0) = []

The following rules are removed:

  p2



-- SCC decomposition.

Consider the dependency pair problem (P, R), where P consists of

p1: plus_2#(s_1(x),y) -> plus_2#(minus_2(x,y),double_1(y))
p2: plus_2#(s_1(x),y) -> plus_2#(x,y)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(double_0(),y) -> double_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(map_0(),y) -> map_1(y)
r11: app(map_1(x1),y) -> map_2(x1,y)
r12: app(minus_0(),y) -> minus_1(y)
r13: app(minus_1(x1),y) -> minus_2(x1,y)
r14: app(plus_0(),y) -> plus_1(y)
r15: app(plus_1(x1),y) -> plus_2(x1,y)
r16: app(s_0(),y) -> s_1(y)
r17: minus_2(x,|0|_0()) -> x
r18: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r19: double_1(|0|_0()) -> |0|_0()
r20: double_1(s_1(x)) -> s_1(s_1(double_1(x)))
r21: plus_2(|0|_0(),y) -> y
r22: plus_2(s_1(x),y) -> s_1(plus_2(x,y))
r23: plus_2(s_1(x),y) -> plus_2(x,s_1(y))
r24: plus_2(s_1(x),y) -> s_1(plus_2(minus_2(x,y),double_1(y)))
r25: map_2(f,nil_0()) -> nil_0()
r26: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs))
r27: filter_2(f,nil_0()) -> nil_0()
r28: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs)
r29: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs))
r30: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs)

The estimated dependency graph contains the following SCCs:

  {p1, p2}


-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: plus_2#(s_1(x),y) -> plus_2#(minus_2(x,y),double_1(y))
p2: plus_2#(s_1(x),y) -> plus_2#(x,y)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(double_0(),y) -> double_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(map_0(),y) -> map_1(y)
r11: app(map_1(x1),y) -> map_2(x1,y)
r12: app(minus_0(),y) -> minus_1(y)
r13: app(minus_1(x1),y) -> minus_2(x1,y)
r14: app(plus_0(),y) -> plus_1(y)
r15: app(plus_1(x1),y) -> plus_2(x1,y)
r16: app(s_0(),y) -> s_1(y)
r17: minus_2(x,|0|_0()) -> x
r18: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r19: double_1(|0|_0()) -> |0|_0()
r20: double_1(s_1(x)) -> s_1(s_1(double_1(x)))
r21: plus_2(|0|_0(),y) -> y
r22: plus_2(s_1(x),y) -> s_1(plus_2(x,y))
r23: plus_2(s_1(x),y) -> plus_2(x,s_1(y))
r24: plus_2(s_1(x),y) -> s_1(plus_2(minus_2(x,y),double_1(y)))
r25: map_2(f,nil_0()) -> nil_0()
r26: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs))
r27: filter_2(f,nil_0()) -> nil_0()
r28: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs)
r29: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs))
r30: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs)

The set of usable rules consists of

  r2, r4, r6, r7, r8, r10, r12, r14, r17, r18, r27

Take the reduction pair:

  generalized weighted path order (>=MG, >MG)
  
    base order 1:
  
      max/plus interpretation on natural numbers:
      
        plus_2#_A(x1,x2) = max{1, x1 - 4}
        s_1_A(x1) = max{13, x1 + 7}
        minus_2_A(x1,x2) = x1 + 3
        double_1_A(x1) = max{18, x1 + 12}
        app_A(x1,x2) = max{15, x1 - 17, x2 - 25}
        cons_1_A(x1) = max{3, x1 - 1}
        cons_2_A(x1,x2) = max{4, x1 - 19, x2 - 26}
        filter_0_A = 13
        filter_1_A(x1) = max{14, x1 - 26}
        filter2_0_A = 1
        filter2_1_A(x1) = max{2, x1 - 26}
        filter2_2_A(x1,x2) = max{3, x1 - 44, x2 - 26}
        filter2_3_A(x1,x2,x3) = max{14, x1 - 62, x2 - 44, x3 - 26}
        map_0_A = 13
        map_1_A(x1) = max{14, x1 - 26}
        minus_0_A = 16
        minus_1_A(x1) = max{15, x1 - 26}
        plus_0_A = 16
        plus_1_A(x1) = max{0, x1 - 26}
        |0|_0_A = 19
        filter_2_A(x1,x2) = max{40, x1 - 2, x2 - 5}
        nil_0_A = 4
  
    base order 2:
  
      precedence:
      
        double_1 > s_1 > plus_2# > minus_2 = filter_0 = |0|_0 = filter_2 = nil_0 > app > cons_1 = cons_2 = filter_1 = filter2_2 = filter2_3 = map_1 = minus_1 = plus_1 > filter2_1 = map_0 = minus_0 = plus_0 > filter2_0
      
  
    partial status:
  
      pi(plus_2#) = []
      pi(s_1) = [1]
      pi(minus_2) = []
      pi(double_1) = [1]
      pi(app) = []
      pi(cons_1) = []
      pi(cons_2) = []
      pi(filter_0) = []
      pi(filter_1) = []
      pi(filter2_0) = []
      pi(filter2_1) = []
      pi(filter2_2) = []
      pi(filter2_3) = []
      pi(map_0) = []
      pi(map_1) = []
      pi(minus_0) = []
      pi(minus_1) = []
      pi(plus_0) = []
      pi(plus_1) = []
      pi(|0|_0) = []
      pi(filter_2) = []
      pi(nil_0) = []

The following rules are removed:

  p2



-- SCC decomposition.

Consider the dependency pair problem (P, R), where P consists of

p1: plus_2#(s_1(x),y) -> plus_2#(minus_2(x,y),double_1(y))

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(double_0(),y) -> double_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(map_0(),y) -> map_1(y)
r11: app(map_1(x1),y) -> map_2(x1,y)
r12: app(minus_0(),y) -> minus_1(y)
r13: app(minus_1(x1),y) -> minus_2(x1,y)
r14: app(plus_0(),y) -> plus_1(y)
r15: app(plus_1(x1),y) -> plus_2(x1,y)
r16: app(s_0(),y) -> s_1(y)
r17: minus_2(x,|0|_0()) -> x
r18: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r19: double_1(|0|_0()) -> |0|_0()
r20: double_1(s_1(x)) -> s_1(s_1(double_1(x)))
r21: plus_2(|0|_0(),y) -> y
r22: plus_2(s_1(x),y) -> s_1(plus_2(x,y))
r23: plus_2(s_1(x),y) -> plus_2(x,s_1(y))
r24: plus_2(s_1(x),y) -> s_1(plus_2(minus_2(x,y),double_1(y)))
r25: map_2(f,nil_0()) -> nil_0()
r26: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs))
r27: filter_2(f,nil_0()) -> nil_0()
r28: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs)
r29: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs))
r30: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs)

The estimated dependency graph contains the following SCCs:

  {p1}


-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: plus_2#(s_1(x),y) -> plus_2#(minus_2(x,y),double_1(y))

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(double_0(),y) -> double_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(map_0(),y) -> map_1(y)
r11: app(map_1(x1),y) -> map_2(x1,y)
r12: app(minus_0(),y) -> minus_1(y)
r13: app(minus_1(x1),y) -> minus_2(x1,y)
r14: app(plus_0(),y) -> plus_1(y)
r15: app(plus_1(x1),y) -> plus_2(x1,y)
r16: app(s_0(),y) -> s_1(y)
r17: minus_2(x,|0|_0()) -> x
r18: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r19: double_1(|0|_0()) -> |0|_0()
r20: double_1(s_1(x)) -> s_1(s_1(double_1(x)))
r21: plus_2(|0|_0(),y) -> y
r22: plus_2(s_1(x),y) -> s_1(plus_2(x,y))
r23: plus_2(s_1(x),y) -> plus_2(x,s_1(y))
r24: plus_2(s_1(x),y) -> s_1(plus_2(minus_2(x,y),double_1(y)))
r25: map_2(f,nil_0()) -> nil_0()
r26: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs))
r27: filter_2(f,nil_0()) -> nil_0()
r28: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs)
r29: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs))
r30: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs)

The set of usable rules consists of

  r1, r4, r6, r7, r8, r10, r12, r14, r17, r18, r27

Take the reduction pair:

  generalized weighted path order (>=MG, >MG)
  
    base order 1:
  
      max/plus interpretation on natural numbers:
      
        plus_2#_A(x1,x2) = max{1, x1 - 4}
        s_1_A(x1) = x1 + 21
        minus_2_A(x1,x2) = max{3, x1}
        double_1_A(x1) = max{45, x1 - 43}
        app_A(x1,x2) = max{45, x1 - 12, x2 + 8}
        cons_0_A = 11
        cons_1_A(x1) = max{6, x1 - 1}
        filter_0_A = 10
        filter_1_A(x1) = max{11, x1 - 60}
        filter2_0_A = 8
        filter2_1_A(x1) = max{9, x1 - 1}
        filter2_2_A(x1,x2) = max{10, x1 - 14, x2 - 1}
        filter2_3_A(x1,x2,x3) = max{11, x1 - 47, x2 - 59, x3 - 1}
        map_0_A = 9
        map_1_A(x1) = max{10, x1 - 1}
        minus_0_A = 11
        minus_1_A(x1) = max{10, x1 - 1}
        plus_0_A = 5
        plus_1_A(x1) = max{6, x1 - 1}
        |0|_0_A = 0
        filter_2_A(x1,x2) = max{46, x1 - 59, x2 - 41}
        nil_0_A = 0
  
    base order 2:
  
      precedence:
      
        s_1 = cons_0 = minus_0 > minus_2 = map_1 > app = map_0 = filter_2 > double_1 = cons_1 = filter_1 = filter2_3 = minus_1 = plus_1 = nil_0 > plus_2# = filter_0 = filter2_2 = plus_0 = |0|_0 > filter2_1 > filter2_0
      
  
    partial status:
  
      pi(plus_2#) = []
      pi(s_1) = [1]
      pi(minus_2) = [1]
      pi(double_1) = []
      pi(app) = []
      pi(cons_0) = []
      pi(cons_1) = []
      pi(filter_0) = []
      pi(filter_1) = []
      pi(filter2_0) = []
      pi(filter2_1) = []
      pi(filter2_2) = []
      pi(filter2_3) = []
      pi(map_0) = []
      pi(map_1) = []
      pi(minus_0) = []
      pi(minus_1) = []
      pi(plus_0) = []
      pi(plus_1) = []
      pi(|0|_0) = []
      pi(filter_2) = []
      pi(nil_0) = []

The following rules are removed:

  p1

Then no dependency pair remains.

-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: double_1#(s_1(x)) -> double_1#(x)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(double_0(),y) -> double_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(map_0(),y) -> map_1(y)
r11: app(map_1(x1),y) -> map_2(x1,y)
r12: app(minus_0(),y) -> minus_1(y)
r13: app(minus_1(x1),y) -> minus_2(x1,y)
r14: app(plus_0(),y) -> plus_1(y)
r15: app(plus_1(x1),y) -> plus_2(x1,y)
r16: app(s_0(),y) -> s_1(y)
r17: minus_2(x,|0|_0()) -> x
r18: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r19: double_1(|0|_0()) -> |0|_0()
r20: double_1(s_1(x)) -> s_1(s_1(double_1(x)))
r21: plus_2(|0|_0(),y) -> y
r22: plus_2(s_1(x),y) -> s_1(plus_2(x,y))
r23: plus_2(s_1(x),y) -> plus_2(x,s_1(y))
r24: plus_2(s_1(x),y) -> s_1(plus_2(minus_2(x,y),double_1(y)))
r25: map_2(f,nil_0()) -> nil_0()
r26: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs))
r27: filter_2(f,nil_0()) -> nil_0()
r28: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs)
r29: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs))
r30: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs)

The set of usable rules consists of

  r1, r2, r4, r6, r7, r8, r10, r12, r14

Take the reduction pair:

  generalized weighted path order (>=MG, >MG)
  
    base order 1:
  
      max/plus interpretation on natural numbers:
      
        double_1#_A(x1) = x1 + 4
        s_1_A(x1) = x1 + 4
        app_A(x1,x2) = max{8, x1 - 9, x2 - 10}
        cons_0_A = 2
        cons_1_A(x1) = max{3, x1 - 11}
        cons_2_A(x1,x2) = max{2, x2 - 10}
        filter_0_A = 8
        filter_1_A(x1) = max{4, x1 - 10}
        filter2_0_A = 1
        filter2_1_A(x1) = max{6, x1 - 11}
        filter2_2_A(x1,x2) = max{7, x1 - 21, x2 - 11}
        filter2_3_A(x1,x2,x3) = max{8, x1 - 30, x2 - 20, x3 - 10}
        map_0_A = 5
        map_1_A(x1) = max{6, x1 - 11}
        minus_0_A = 3
        minus_1_A(x1) = max{4, x1 - 11}
        plus_0_A = 5
        plus_1_A(x1) = max{6, x1 - 11}
  
    base order 2:
  
      precedence:
      
        s_1 = cons_0 = map_0 > double_1# = app > map_1 = minus_1 = plus_1 > cons_2 = filter2_3 = minus_0 = plus_0 > cons_1 = filter_1 = filter2_2 > filter_0 = filter2_1 > filter2_0
      
  
    partial status:
  
      pi(double_1#) = [1]
      pi(s_1) = [1]
      pi(app) = []
      pi(cons_0) = []
      pi(cons_1) = []
      pi(cons_2) = []
      pi(filter_0) = []
      pi(filter_1) = []
      pi(filter2_0) = []
      pi(filter2_1) = []
      pi(filter2_2) = []
      pi(filter2_3) = []
      pi(map_0) = []
      pi(map_1) = []
      pi(minus_0) = []
      pi(minus_1) = []
      pi(plus_0) = []
      pi(plus_1) = []

The following rules are removed:

  p1

Then no dependency pair remains.

-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: minus_2#(s_1(x),s_1(y)) -> minus_2#(x,y)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(double_0(),y) -> double_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(map_0(),y) -> map_1(y)
r11: app(map_1(x1),y) -> map_2(x1,y)
r12: app(minus_0(),y) -> minus_1(y)
r13: app(minus_1(x1),y) -> minus_2(x1,y)
r14: app(plus_0(),y) -> plus_1(y)
r15: app(plus_1(x1),y) -> plus_2(x1,y)
r16: app(s_0(),y) -> s_1(y)
r17: minus_2(x,|0|_0()) -> x
r18: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r19: double_1(|0|_0()) -> |0|_0()
r20: double_1(s_1(x)) -> s_1(s_1(double_1(x)))
r21: plus_2(|0|_0(),y) -> y
r22: plus_2(s_1(x),y) -> s_1(plus_2(x,y))
r23: plus_2(s_1(x),y) -> plus_2(x,s_1(y))
r24: plus_2(s_1(x),y) -> s_1(plus_2(minus_2(x,y),double_1(y)))
r25: map_2(f,nil_0()) -> nil_0()
r26: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs))
r27: filter_2(f,nil_0()) -> nil_0()
r28: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs)
r29: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs))
r30: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs)

The set of usable rules consists of

  r1, r2, r4, r6, r8, r10, r12, r27

Take the reduction pair:

  generalized weighted path order (>=MG, >MG)
  
    base order 1:
  
      max/plus interpretation on natural numbers:
      
        minus_2#_A(x1,x2) = max{6, x1 + 1}
        s_1_A(x1) = x1 + 8
        app_A(x1,x2) = max{10, x1 - 12, x2 + 2}
        cons_0_A = 2
        cons_1_A(x1) = max{3, x1 - 8}
        cons_2_A(x1,x2) = max{4, x1 - 20, x2 - 9}
        filter_0_A = 6
        filter_1_A(x1) = max{7, x1 - 11}
        filter2_0_A = 11
        filter2_1_A(x1) = max{9, x1 - 2}
        filter2_2_A(x1,x2) = max{11, x1 - 1, x2 - 1}
        filter2_3_A(x1,x2,x3) = max{1, x1 - 14, x2 - 14, x3 - 1}
        map_0_A = 4
        map_1_A(x1) = max{5, x1 - 1}
        minus_0_A = 2
        minus_1_A(x1) = max{3, x1 - 1}
        filter_2_A(x1,x2) = max{8, x1 - 24, x2 - 8}
        nil_0_A = 7
  
    base order 2:
  
      precedence:
      
        minus_2# = s_1 = cons_1 = filter2_2 = filter2_3 > app = cons_0 > cons_2 = filter2_1 = minus_1 = filter_2 > filter_1 = filter2_0 = map_1 = minus_0 = nil_0 > filter_0 = map_0
      
  
    partial status:
  
      pi(minus_2#) = [1]
      pi(s_1) = [1]
      pi(app) = []
      pi(cons_0) = []
      pi(cons_1) = []
      pi(cons_2) = []
      pi(filter_0) = []
      pi(filter_1) = []
      pi(filter2_0) = []
      pi(filter2_1) = []
      pi(filter2_2) = []
      pi(filter2_3) = []
      pi(map_0) = []
      pi(map_1) = []
      pi(minus_0) = []
      pi(minus_1) = []
      pi(filter_2) = []
      pi(nil_0) = []

The following rules are removed:

  p1

Then no dependency pair remains.