YES We show the termination of the TRS R: app(f(),app(f(),x)) -> app(g(),app(f(),x)) app(g(),app(g(),x)) -> app(f(),x) app(app(map(),|fun|),nil()) -> nil() app(app(map(),|fun|),app(app(cons(),x),xs)) -> app(app(cons(),app(|fun|,x)),app(app(map(),|fun|),xs)) app(app(filter(),|fun|),nil()) -> nil() app(app(filter(),|fun|),app(app(cons(),x),xs)) -> app(app(app(app(filter2(),app(|fun|,x)),|fun|),x),xs) app(app(app(app(filter2(),true()),|fun|),x),xs) -> app(app(cons(),x),app(app(filter(),|fun|),xs)) app(app(app(app(filter2(),false()),|fun|),x),xs) -> app(app(filter(),|fun|),xs) Instead we prove termination of the uncurried system: app(cons_0(),y) -> cons_1(y) app(cons_1(x1),y) -> cons_2(x1,y) app(f_0(),y) -> f_1(y) app(filter_0(),y) -> filter_1(y) app(filter_1(x1),y) -> filter_2(x1,y) app(filter2_0(),y) -> filter2_1(y) app(filter2_1(x1),y) -> filter2_2(x1,y) app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) app(g_0(),y) -> g_1(y) app(map_0(),y) -> map_1(y) app(map_1(x1),y) -> map_2(x1,y) f_1(f_1(x)) -> g_1(f_1(x)) g_1(g_1(x)) -> f_1(x) map_2(|fun|,nil_0()) -> nil_0() map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) filter_2(|fun|,nil_0()) -> nil_0() filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: app#(f_0(),y) -> f_1#(y) p2: app#(filter_1(x1),y) -> filter_2#(x1,y) p3: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p4: app#(g_0(),y) -> g_1#(y) p5: app#(map_1(x1),y) -> map_2#(x1,y) p6: f_1#(f_1(x)) -> g_1#(f_1(x)) p7: g_1#(g_1(x)) -> f_1#(x) p8: map_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p9: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) p10: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p11: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p12: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p13: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(filter_0(),y) -> filter_1(y) r5: app(filter_1(x1),y) -> filter_2(x1,y) r6: app(filter2_0(),y) -> filter2_1(y) r7: app(filter2_1(x1),y) -> filter2_2(x1,y) r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r10: app(g_0(),y) -> g_1(y) r11: app(map_0(),y) -> map_1(y) r12: app(map_1(x1),y) -> map_2(x1,y) r13: f_1(f_1(x)) -> g_1(f_1(x)) r14: g_1(g_1(x)) -> f_1(x) r15: map_2(|fun|,nil_0()) -> nil_0() r16: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r17: filter_2(|fun|,nil_0()) -> nil_0() r18: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r19: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r20: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The estimated dependency graph contains the following SCCs: {p2, p3, p5, p8, p9, p10, p11, p12, p13} {p6, p7} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p2: app#(map_1(x1),y) -> map_2#(x1,y) p3: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) p4: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p5: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p6: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p7: app#(filter_1(x1),y) -> filter_2#(x1,y) p8: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p9: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(filter_0(),y) -> filter_1(y) r5: app(filter_1(x1),y) -> filter_2(x1,y) r6: app(filter2_0(),y) -> filter2_1(y) r7: app(filter2_1(x1),y) -> filter2_2(x1,y) r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r10: app(g_0(),y) -> g_1(y) r11: app(map_0(),y) -> map_1(y) r12: app(map_1(x1),y) -> map_2(x1,y) r13: f_1(f_1(x)) -> g_1(f_1(x)) r14: g_1(g_1(x)) -> f_1(x) r15: map_2(|fun|,nil_0()) -> nil_0() r16: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r17: filter_2(|fun|,nil_0()) -> nil_0() r18: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r19: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r20: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r1, r2, r4, r6, r7, r11, r17 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: map_2#_A(x1,x2) = x1 + 8 cons_2_A(x1,x2) = max{25, x1 - 26, x2 - 28} app#_A(x1,x2) = x1 + 6 map_1_A(x1) = x1 + 9 filter2_3_A(x1,x2,x3) = max{x1 - 3, x2 + 29, x3} filter2_4#_A(x1,x2,x3,x4) = x2 + 6 false_0_A = 26 filter_2#_A(x1,x2) = x1 + 6 filter_1_A(x1) = max{25, x1 + 6} app_A(x1,x2) = max{x1, x2 + 25} true_0_A = 26 cons_0_A = 0 cons_1_A(x1) = max{0, x1 - 26} filter_0_A = 0 filter2_0_A = 0 filter2_1_A(x1) = max{0, x1 - 1} filter2_2_A(x1,x2) = max{0, x1 - 2, x2 - 1} map_0_A = 0 filter_2_A(x1,x2) = max{27, x1 - 1, x2 - 12} nil_0_A = 11 base order 2: precedence: app = filter_0 = filter_2 > cons_2 = map_1 = filter2_3 = false_0 = filter_1 = nil_0 > true_0 = cons_1 = filter2_2 = map_0 > map_2# = filter2_4# = filter_2# = cons_0 = filter2_1 > app# = filter2_0 partial status: pi(map_2#) = [1] pi(cons_2) = [] pi(app#) = [1] pi(map_1) = [1] pi(filter2_3) = [2, 3] pi(filter2_4#) = [2] pi(false_0) = [] pi(filter_2#) = [1] pi(filter_1) = [] pi(app) = [1] pi(true_0) = [] pi(cons_0) = [] pi(cons_1) = [] pi(filter_0) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(map_0) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p7 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p2: app#(map_1(x1),y) -> map_2#(x1,y) p3: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) p4: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p5: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p6: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p7: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p8: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(filter_0(),y) -> filter_1(y) r5: app(filter_1(x1),y) -> filter_2(x1,y) r6: app(filter2_0(),y) -> filter2_1(y) r7: app(filter2_1(x1),y) -> filter2_2(x1,y) r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r10: app(g_0(),y) -> g_1(y) r11: app(map_0(),y) -> map_1(y) r12: app(map_1(x1),y) -> map_2(x1,y) r13: f_1(f_1(x)) -> g_1(f_1(x)) r14: g_1(g_1(x)) -> f_1(x) r15: map_2(|fun|,nil_0()) -> nil_0() r16: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r17: filter_2(|fun|,nil_0()) -> nil_0() r18: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r19: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r20: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The estimated dependency graph contains the following SCCs: {p1, p2, p3, p4, p5, p6, p7, p8} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p2: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p3: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p4: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p5: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p6: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p7: app#(map_1(x1),y) -> map_2#(x1,y) p8: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(filter_0(),y) -> filter_1(y) r5: app(filter_1(x1),y) -> filter_2(x1,y) r6: app(filter2_0(),y) -> filter2_1(y) r7: app(filter2_1(x1),y) -> filter2_2(x1,y) r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r10: app(g_0(),y) -> g_1(y) r11: app(map_0(),y) -> map_1(y) r12: app(map_1(x1),y) -> map_2(x1,y) r13: f_1(f_1(x)) -> g_1(f_1(x)) r14: g_1(g_1(x)) -> f_1(x) r15: map_2(|fun|,nil_0()) -> nil_0() r16: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r17: filter_2(|fun|,nil_0()) -> nil_0() r18: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r19: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r20: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r1, r2, r4, r6, r7, r11, r17 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: map_2#_A(x1,x2) = max{12, x1 + 4} cons_2_A(x1,x2) = max{11, x1 - 17, x2 - 17} app#_A(x1,x2) = x1 + 3 filter2_3_A(x1,x2,x3) = max{9, x1 - 1, x2 + 7, x3 - 1} filter2_4#_A(x1,x2,x3,x4) = x2 + 4 true_0_A = 7 filter_2#_A(x1,x2) = x1 + 4 app_A(x1,x2) = max{15, x1 - 14, x2 + 6} false_0_A = 7 map_1_A(x1) = max{13, x1 + 5} cons_0_A = 9 cons_1_A(x1) = max{10, x1 - 1} filter_0_A = 6 filter_1_A(x1) = max{7, x1 - 27} filter2_0_A = 6 filter2_1_A(x1) = max{7, x1 - 1} filter2_2_A(x1,x2) = max{8, x1 - 16, x2 - 1} map_0_A = 12 filter_2_A(x1,x2) = max{8, x1 - 26, x2 - 19} nil_0_A = 7 base order 2: precedence: cons_2 > filter2_3 = app = filter2_0 = filter_2 > false_0 = map_1 = cons_1 = filter_1 = filter2_2 = nil_0 > filter2_4# = filter_2# = cons_0 = filter_0 = filter2_1 = map_0 > app# = true_0 > map_2# partial status: pi(map_2#) = [] pi(cons_2) = [] pi(app#) = [1] pi(filter2_3) = [] pi(filter2_4#) = [] pi(true_0) = [] pi(filter_2#) = [] pi(app) = [2] pi(false_0) = [] pi(map_1) = [] pi(cons_0) = [] pi(cons_1) = [] pi(filter_0) = [] pi(filter_1) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(map_0) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p1 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p2: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p3: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p4: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p5: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p6: app#(map_1(x1),y) -> map_2#(x1,y) p7: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(filter_0(),y) -> filter_1(y) r5: app(filter_1(x1),y) -> filter_2(x1,y) r6: app(filter2_0(),y) -> filter2_1(y) r7: app(filter2_1(x1),y) -> filter2_2(x1,y) r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r10: app(g_0(),y) -> g_1(y) r11: app(map_0(),y) -> map_1(y) r12: app(map_1(x1),y) -> map_2(x1,y) r13: f_1(f_1(x)) -> g_1(f_1(x)) r14: g_1(g_1(x)) -> f_1(x) r15: map_2(|fun|,nil_0()) -> nil_0() r16: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r17: filter_2(|fun|,nil_0()) -> nil_0() r18: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r19: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r20: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The estimated dependency graph contains the following SCCs: {p1, p2, p3, p4, p5} {p7} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p2: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p3: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p4: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p5: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(filter_0(),y) -> filter_1(y) r5: app(filter_1(x1),y) -> filter_2(x1,y) r6: app(filter2_0(),y) -> filter2_1(y) r7: app(filter2_1(x1),y) -> filter2_2(x1,y) r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r10: app(g_0(),y) -> g_1(y) r11: app(map_0(),y) -> map_1(y) r12: app(map_1(x1),y) -> map_2(x1,y) r13: f_1(f_1(x)) -> g_1(f_1(x)) r14: g_1(g_1(x)) -> f_1(x) r15: map_2(|fun|,nil_0()) -> nil_0() r16: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r17: filter_2(|fun|,nil_0()) -> nil_0() r18: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r19: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r20: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r2, r4, r6, r7, r11, r17 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: app#_A(x1,x2) = max{0, x1 - 5} filter2_3_A(x1,x2,x3) = max{x1 + 6, x2 + 4, x3 - 1} filter2_4#_A(x1,x2,x3,x4) = max{0, x2 - 4} false_0_A = 1 filter_2#_A(x1,x2) = max{0, x1 - 4} cons_2_A(x1,x2) = max{2, x1 - 41, x2 - 11} app_A(x1,x2) = max{8, x1 - 9, x2 - 9} true_0_A = 23 cons_1_A(x1) = max{12, x1 - 10} filter_0_A = 7 filter_1_A(x1) = max{8, x1 - 10} filter2_0_A = 1 filter2_1_A(x1) = max{2, x1 - 10} filter2_2_A(x1,x2) = max{3, x1 - 20, x2 - 10} map_0_A = 1 map_1_A(x1) = max{0, x1 - 10} filter_2_A(x1,x2) = max{2, x1 - 7, x2 - 11} nil_0_A = 1 base order 2: precedence: app > map_1 > filter2_3 = filter2_4# = filter_2# = map_0 = filter_2 > app# = false_0 = filter_1 = filter2_2 = nil_0 > cons_2 = filter_0 = filter2_1 > true_0 = cons_1 = filter2_0 partial status: pi(app#) = [] pi(filter2_3) = [2] pi(filter2_4#) = [] pi(false_0) = [] pi(filter_2#) = [] pi(cons_2) = [] pi(app) = [] pi(true_0) = [] pi(cons_1) = [] pi(filter_0) = [] pi(filter_1) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(map_0) = [] pi(map_1) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p3 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p2: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p3: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p4: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(filter_0(),y) -> filter_1(y) r5: app(filter_1(x1),y) -> filter_2(x1,y) r6: app(filter2_0(),y) -> filter2_1(y) r7: app(filter2_1(x1),y) -> filter2_2(x1,y) r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r10: app(g_0(),y) -> g_1(y) r11: app(map_0(),y) -> map_1(y) r12: app(map_1(x1),y) -> map_2(x1,y) r13: f_1(f_1(x)) -> g_1(f_1(x)) r14: g_1(g_1(x)) -> f_1(x) r15: map_2(|fun|,nil_0()) -> nil_0() r16: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r17: filter_2(|fun|,nil_0()) -> nil_0() r18: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r19: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r20: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The estimated dependency graph contains the following SCCs: {p2, p3, p4} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p2: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p3: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(filter_0(),y) -> filter_1(y) r5: app(filter_1(x1),y) -> filter_2(x1,y) r6: app(filter2_0(),y) -> filter2_1(y) r7: app(filter2_1(x1),y) -> filter2_2(x1,y) r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r10: app(g_0(),y) -> g_1(y) r11: app(map_0(),y) -> map_1(y) r12: app(map_1(x1),y) -> map_2(x1,y) r13: f_1(f_1(x)) -> g_1(f_1(x)) r14: g_1(g_1(x)) -> f_1(x) r15: map_2(|fun|,nil_0()) -> nil_0() r16: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r17: filter_2(|fun|,nil_0()) -> nil_0() r18: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r19: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r20: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r1, r2, r4, r6, r8, r11, r17 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: filter2_4#_A(x1,x2,x3,x4) = max{x3 + 7, x4 + 5} false_0_A = 1 filter_2#_A(x1,x2) = x2 + 4 cons_2_A(x1,x2) = max{x1 + 7, x2 + 5} app_A(x1,x2) = max{x1 + 11, x2 + 11} true_0_A = 12 cons_0_A = 2 cons_1_A(x1) = max{12, x1 + 8} filter_0_A = 17 filter_1_A(x1) = max{27, x1 - 12} filter2_0_A = 1 filter2_1_A(x1) = max{12, x1 - 12} filter2_2_A(x1,x2) = max{24, x1 + 1, x2 - 23} filter2_3_A(x1,x2,x3) = max{35, x1 - 12, x2 - 12, x3 - 12} map_0_A = 1 map_1_A(x1) = max{7, x1 - 12} filter_2_A(x1,x2) = max{37, x1 - 13, x2 - 8} nil_0_A = 0 base order 2: precedence: app > filter_2# = cons_0 = filter_2 > false_0 = filter_1 = map_1 = nil_0 > cons_2 = filter_0 = filter2_3 = map_0 > filter2_4# = true_0 = cons_1 = filter2_2 > filter2_1 > filter2_0 partial status: pi(filter2_4#) = [] pi(false_0) = [] pi(filter_2#) = [2] pi(cons_2) = [1, 2] pi(app) = [1, 2] pi(true_0) = [] pi(cons_0) = [] pi(cons_1) = [1] pi(filter_0) = [] pi(filter_1) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [1] pi(filter2_3) = [] pi(map_0) = [] pi(map_1) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p2 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p2: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(filter_0(),y) -> filter_1(y) r5: app(filter_1(x1),y) -> filter_2(x1,y) r6: app(filter2_0(),y) -> filter2_1(y) r7: app(filter2_1(x1),y) -> filter2_2(x1,y) r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r10: app(g_0(),y) -> g_1(y) r11: app(map_0(),y) -> map_1(y) r12: app(map_1(x1),y) -> map_2(x1,y) r13: f_1(f_1(x)) -> g_1(f_1(x)) r14: g_1(g_1(x)) -> f_1(x) r15: map_2(|fun|,nil_0()) -> nil_0() r16: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r17: filter_2(|fun|,nil_0()) -> nil_0() r18: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r19: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r20: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The estimated dependency graph contains the following SCCs: (no SCCs) -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(filter_0(),y) -> filter_1(y) r5: app(filter_1(x1),y) -> filter_2(x1,y) r6: app(filter2_0(),y) -> filter2_1(y) r7: app(filter2_1(x1),y) -> filter2_2(x1,y) r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r10: app(g_0(),y) -> g_1(y) r11: app(map_0(),y) -> map_1(y) r12: app(map_1(x1),y) -> map_2(x1,y) r13: f_1(f_1(x)) -> g_1(f_1(x)) r14: g_1(g_1(x)) -> f_1(x) r15: map_2(|fun|,nil_0()) -> nil_0() r16: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r17: filter_2(|fun|,nil_0()) -> nil_0() r18: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r19: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r20: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r1, r4, r6, r7, r8, r11, r17 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: map_2#_A(x1,x2) = max{4, x1 + 1, x2 + 2} cons_2_A(x1,x2) = max{2, x1 - 1, x2} app_A(x1,x2) = max{0, x1 - 2, x2 - 5} cons_0_A = 1 cons_1_A(x1) = max{0, x1 - 5} filter_0_A = 1 filter_1_A(x1) = 0 filter2_0_A = 1 filter2_1_A(x1) = max{0, x1 - 6} filter2_2_A(x1,x2) = max{0, x1 - 8, x2 - 5} filter2_3_A(x1,x2,x3) = max{0, x1 - 10, x2 - 7, x3 - 5} map_0_A = 1 map_1_A(x1) = max{0, x1 - 5} filter_2_A(x1,x2) = max{x1 + 3, x2 - 3} nil_0_A = 0 base order 2: precedence: filter_2 > map_2# = app = filter_0 = nil_0 > cons_2 = filter_1 = filter2_3 = map_1 > cons_1 = filter2_2 = map_0 > cons_0 = filter2_1 > filter2_0 partial status: pi(map_2#) = [2] pi(cons_2) = [2] pi(app) = [] pi(cons_0) = [] pi(cons_1) = [] pi(filter_0) = [] pi(filter_1) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(filter2_3) = [] pi(map_0) = [] pi(map_1) = [] pi(filter_2) = [1] pi(nil_0) = [] The following rules are removed: p1 Then no dependency pair remains. -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: f_1#(f_1(x)) -> g_1#(f_1(x)) p2: g_1#(g_1(x)) -> f_1#(x) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(filter_0(),y) -> filter_1(y) r5: app(filter_1(x1),y) -> filter_2(x1,y) r6: app(filter2_0(),y) -> filter2_1(y) r7: app(filter2_1(x1),y) -> filter2_2(x1,y) r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r10: app(g_0(),y) -> g_1(y) r11: app(map_0(),y) -> map_1(y) r12: app(map_1(x1),y) -> map_2(x1,y) r13: f_1(f_1(x)) -> g_1(f_1(x)) r14: g_1(g_1(x)) -> f_1(x) r15: map_2(|fun|,nil_0()) -> nil_0() r16: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r17: filter_2(|fun|,nil_0()) -> nil_0() r18: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r19: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r20: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r1, r2, r3, r4, r6, r7, r8, r10, r11, r13, r14, r17 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: f_1#_A(x1) = max{10, x1 + 4} f_1_A(x1) = max{10, x1 + 8} g_1#_A(x1) = max{11, x1 + 3} g_1_A(x1) = max{10, x1 + 8} app_A(x1,x2) = max{x1 - 11, x2 + 10} cons_0_A = 10 cons_1_A(x1) = max{1, x1 - 1} cons_2_A(x1,x2) = max{5, x1 - 28, x2 - 30} f_0_A = 9 filter_0_A = 9 filter_1_A(x1) = max{10, x1 - 36} filter2_0_A = 1 filter2_1_A(x1) = max{6, x1 - 1} filter2_2_A(x1,x2) = max{8, x1 - 12, x2 - 1} filter2_3_A(x1,x2,x3) = max{9, x1 - 24, x2 - 13, x3 - 1} g_0_A = 9 map_0_A = 9 map_1_A(x1) = max{10, x1 - 1} filter_2_A(x1,x2) = max{4, x1 - 48, x2 - 30} nil_0_A = 0 base order 2: precedence: g_1# = filter_2 = nil_0 > f_1 = app = filter_0 > g_1 = f_0 = filter_1 = filter2_3 > f_1# = cons_2 = filter2_2 = g_0 = map_1 > cons_1 = filter2_1 = map_0 > cons_0 = filter2_0 partial status: pi(f_1#) = [] pi(f_1) = [] pi(g_1#) = [1] pi(g_1) = [] pi(app) = [] pi(cons_0) = [] pi(cons_1) = [] pi(cons_2) = [] pi(f_0) = [] pi(filter_0) = [] pi(filter_1) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(filter2_3) = [] pi(g_0) = [] pi(map_0) = [] pi(map_1) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p1 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: g_1#(g_1(x)) -> f_1#(x) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(filter_0(),y) -> filter_1(y) r5: app(filter_1(x1),y) -> filter_2(x1,y) r6: app(filter2_0(),y) -> filter2_1(y) r7: app(filter2_1(x1),y) -> filter2_2(x1,y) r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r10: app(g_0(),y) -> g_1(y) r11: app(map_0(),y) -> map_1(y) r12: app(map_1(x1),y) -> map_2(x1,y) r13: f_1(f_1(x)) -> g_1(f_1(x)) r14: g_1(g_1(x)) -> f_1(x) r15: map_2(|fun|,nil_0()) -> nil_0() r16: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r17: filter_2(|fun|,nil_0()) -> nil_0() r18: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r19: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r20: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The estimated dependency graph contains the following SCCs: (no SCCs)