YES We show the termination of the TRS R: app(D(),t()) -> |1|() app(D(),constant()) -> |0|() app(D(),app(app(+(),x),y)) -> app(app(+(),app(D(),x)),app(D(),y)) app(D(),app(app(*(),x),y)) -> app(app(+(),app(app(*(),y),app(D(),x))),app(app(*(),x),app(D(),y))) app(D(),app(app(-(),x),y)) -> app(app(-(),app(D(),x)),app(D(),y)) app(app(map(),f),nil()) -> nil() app(app(map(),f),app(app(cons(),x),xs)) -> app(app(cons(),app(f,x)),app(app(map(),f),xs)) app(app(filter(),f),nil()) -> nil() app(app(filter(),f),app(app(cons(),x),xs)) -> app(app(app(app(filter2(),app(f,x)),f),x),xs) app(app(app(app(filter2(),true()),f),x),xs) -> app(app(cons(),x),app(app(filter(),f),xs)) app(app(app(app(filter2(),false()),f),x),xs) -> app(app(filter(),f),xs) Instead we prove termination of the uncurried system: app(*_0(),y) -> *_1(y) app(*_1(x1),y) -> *_2(x1,y) app(+_0(),y) -> +_1(y) app(+_1(x1),y) -> +_2(x1,y) app(-_0(),y) -> -_1(y) app(-_1(x1),y) -> -_2(x1,y) app(D_0(),y) -> D_1(y) app(cons_0(),y) -> cons_1(y) app(cons_1(x1),y) -> cons_2(x1,y) app(filter_0(),y) -> filter_1(y) app(filter_1(x1),y) -> filter_2(x1,y) app(filter2_0(),y) -> filter2_1(y) app(filter2_1(x1),y) -> filter2_2(x1,y) app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) app(map_0(),y) -> map_1(y) app(map_1(x1),y) -> map_2(x1,y) D_1(t_0()) -> |1|_0() D_1(constant_0()) -> |0|_0() D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) map_2(f,nil_0()) -> nil_0() map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) filter_2(f,nil_0()) -> nil_0() filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: app#(D_0(),y) -> D_1#(y) p2: app#(filter_1(x1),y) -> filter_2#(x1,y) p3: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p4: app#(map_1(x1),y) -> map_2#(x1,y) p5: D_1#(+_2(x,y)) -> D_1#(x) p6: D_1#(+_2(x,y)) -> D_1#(y) p7: D_1#(*_2(x,y)) -> D_1#(x) p8: D_1#(*_2(x,y)) -> D_1#(y) p9: D_1#(-_2(x,y)) -> D_1#(x) p10: D_1#(-_2(x,y)) -> D_1#(y) p11: map_2#(f,cons_2(x,xs)) -> app#(f,x) p12: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) p13: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs) p14: filter_2#(f,cons_2(x,xs)) -> app#(f,x) p15: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs) p16: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(filter_0(),y) -> filter_1(y) r11: app(filter_1(x1),y) -> filter_2(x1,y) r12: app(filter2_0(),y) -> filter2_1(y) r13: app(filter2_1(x1),y) -> filter2_2(x1,y) r14: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r15: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: D_1(t_0()) -> |1|_0() r19: D_1(constant_0()) -> |0|_0() r20: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r21: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r22: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r23: map_2(f,nil_0()) -> nil_0() r24: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r25: filter_2(f,nil_0()) -> nil_0() r26: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r27: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r28: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The estimated dependency graph contains the following SCCs: {p2, p3, p4, p11, p12, p13, p14, p15, p16} {p5, p6, p7, p8, p9, p10} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(f,cons_2(x,xs)) -> app#(f,x) p2: app#(map_1(x1),y) -> map_2#(x1,y) p3: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) p4: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p5: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs) p6: filter_2#(f,cons_2(x,xs)) -> app#(f,x) p7: app#(filter_1(x1),y) -> filter_2#(x1,y) p8: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs) p9: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(filter_0(),y) -> filter_1(y) r11: app(filter_1(x1),y) -> filter_2(x1,y) r12: app(filter2_0(),y) -> filter2_1(y) r13: app(filter2_1(x1),y) -> filter2_2(x1,y) r14: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r15: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: D_1(t_0()) -> |1|_0() r19: D_1(constant_0()) -> |0|_0() r20: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r21: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r22: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r23: map_2(f,nil_0()) -> nil_0() r24: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r25: filter_2(f,nil_0()) -> nil_0() r26: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r27: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r28: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of r18, r19, r25 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: map_2#_A(x1,x2) = max{5, x2 - 7} cons_2_A(x1,x2) = max{x1 + 13, x2 + 29} app#_A(x1,x2) = x2 + 5 map_1_A(x1) = max{13, x1 - 31} filter2_3_A(x1,x2,x3) = max{18, x1 - 31, x2 - 31, x3 - 31} filter2_4#_A(x1,x2,x3,x4) = x4 + 4 false_0_A = 32 filter_2#_A(x1,x2) = x2 + 3 filter_1_A(x1) = max{15, x1 - 31} app_A(x1,x2) = 15 true_0_A = 32 D_1_A(x1) = max{13, x1 - 65} t_0_A = 1 |1|_0_A = 0 constant_0_A = 1 |0|_0_A = 0 filter_2_A(x1,x2) = max{33, x1 - 30, x2 - 76} nil_0_A = 0 base order 2: precedence: cons_2 > filter_2 > false_0 = app = nil_0 > map_1 = filter2_3 = filter_1 = true_0 > filter_2# = D_1 = t_0 = constant_0 > filter2_4# = |1|_0 = |0|_0 > app# > map_2# partial status: pi(map_2#) = [] pi(cons_2) = [2] pi(app#) = [2] pi(map_1) = [] pi(filter2_3) = [] pi(filter2_4#) = [] pi(false_0) = [] pi(filter_2#) = [2] pi(filter_1) = [] pi(app) = [] pi(true_0) = [] pi(D_1) = [] pi(t_0) = [] pi(|1|_0) = [] pi(constant_0) = [] pi(|0|_0) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p2 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(f,cons_2(x,xs)) -> app#(f,x) p2: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) p3: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p4: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs) p5: filter_2#(f,cons_2(x,xs)) -> app#(f,x) p6: app#(filter_1(x1),y) -> filter_2#(x1,y) p7: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs) p8: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(filter_0(),y) -> filter_1(y) r11: app(filter_1(x1),y) -> filter_2(x1,y) r12: app(filter2_0(),y) -> filter2_1(y) r13: app(filter2_1(x1),y) -> filter2_2(x1,y) r14: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r15: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: D_1(t_0()) -> |1|_0() r19: D_1(constant_0()) -> |0|_0() r20: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r21: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r22: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r23: map_2(f,nil_0()) -> nil_0() r24: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r25: filter_2(f,nil_0()) -> nil_0() r26: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r27: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r28: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The estimated dependency graph contains the following SCCs: {p2} {p3, p4, p5, p6, p7, p8} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(filter_0(),y) -> filter_1(y) r11: app(filter_1(x1),y) -> filter_2(x1,y) r12: app(filter2_0(),y) -> filter2_1(y) r13: app(filter2_1(x1),y) -> filter2_2(x1,y) r14: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r15: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: D_1(t_0()) -> |1|_0() r19: D_1(constant_0()) -> |0|_0() r20: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r21: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r22: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r23: map_2(f,nil_0()) -> nil_0() r24: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r25: filter_2(f,nil_0()) -> nil_0() r26: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r27: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r28: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of r1, r2, r3, r4, r5, r6, r8, r10, r12, r13, r14, r18, r19, r25 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: map_2#_A(x1,x2) = max{x1 + 21, x2 + 42} cons_2_A(x1,x2) = max{19, x1 - 21, x2} app_A(x1,x2) = max{20, x1 - 22, x2 - 43} *_0_A = 17 *_1_A(x1) = max{18, x1 - 44} *_2_A(x1,x2) = max{19, x1 - 67, x2 - 75} +_0_A = 1 +_1_A(x1) = max{2, x1 - 44} +_2_A(x1,x2) = max{3, x1 - 85, x2 - 79} -_0_A = 6 -_1_A(x1) = max{7, x1 - 44} -_2_A(x1,x2) = max{8, x1 - 76, x2 - 68} cons_0_A = 41 cons_1_A(x1) = max{18, x1 - 44} filter_0_A = 1 filter_1_A(x1) = max{19, x1 - 43} filter2_0_A = 16 filter2_1_A(x1) = max{17, x1 - 44} filter2_2_A(x1,x2) = max{18, x1 - 67, x2 - 44} filter2_3_A(x1,x2,x3) = max{19, x1 - 90, x2 - 67, x3 - 44} D_1_A(x1) = max{7, x1 - 76} t_0_A = 1 |1|_0_A = 0 constant_0_A = 1 |0|_0_A = 0 filter_2_A(x1,x2) = max{21, x1 - 2, x2 - 21} nil_0_A = 0 base order 2: precedence: filter2_3 = filter_2 = nil_0 > map_2# = cons_2 = app = +_0 = cons_0 > *_2 = -_2 = cons_1 = filter_1 = filter2_2 > *_1 = -_1 = filter_0 = filter2_1 = D_1 = t_0 = constant_0 > *_0 = +_2 = -_0 = filter2_0 = |1|_0 = |0|_0 > +_1 partial status: pi(map_2#) = [2] pi(cons_2) = [2] pi(app) = [] pi(*_0) = [] pi(*_1) = [] pi(*_2) = [] pi(+_0) = [] pi(+_1) = [] pi(+_2) = [] pi(-_0) = [] pi(-_1) = [] pi(-_2) = [] pi(cons_0) = [] pi(cons_1) = [] pi(filter_0) = [] pi(filter_1) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(filter2_3) = [] pi(D_1) = [] pi(t_0) = [] pi(|1|_0) = [] pi(constant_0) = [] pi(|0|_0) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p1 Then no dependency pair remains. -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p2: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs) p3: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs) p4: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs) p5: filter_2#(f,cons_2(x,xs)) -> app#(f,x) p6: app#(filter_1(x1),y) -> filter_2#(x1,y) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(filter_0(),y) -> filter_1(y) r11: app(filter_1(x1),y) -> filter_2(x1,y) r12: app(filter2_0(),y) -> filter2_1(y) r13: app(filter2_1(x1),y) -> filter2_2(x1,y) r14: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r15: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: D_1(t_0()) -> |1|_0() r19: D_1(constant_0()) -> |0|_0() r20: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r21: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r22: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r23: map_2(f,nil_0()) -> nil_0() r24: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r25: filter_2(f,nil_0()) -> nil_0() r26: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r27: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r28: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of r1, r2, r3, r4, r5, r6, r8, r10, r13, r16, r18, r19, r25 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: app#_A(x1,x2) = x1 + 5 filter2_3_A(x1,x2,x3) = max{8, x1 - 1, x2 + 7, x3 - 1} filter2_4#_A(x1,x2,x3,x4) = x2 + 6 true_0_A = 1 filter_2#_A(x1,x2) = x1 + 6 cons_2_A(x1,x2) = max{4, x1 - 15, x2 - 15} app_A(x1,x2) = max{x1 - 12, x2 + 10} false_0_A = 15 filter_1_A(x1) = max{27, x1 + 7} *_0_A = 5 *_1_A(x1) = max{6, x1 - 2} *_2_A(x1,x2) = max{10, x1 - 14, x2 - 14} +_0_A = 1 +_1_A(x1) = max{6, x1 - 2} +_2_A(x1,x2) = max{10, x1 - 14, x2 - 15} -_0_A = 11 -_1_A(x1) = max{9, x1 - 1} -_2_A(x1,x2) = max{10, x1 - 14, x2 - 14} cons_0_A = 1 cons_1_A(x1) = max{3, x1 - 4} filter_0_A = 40 filter2_1_A(x1) = max{11, x1 - 1} filter2_2_A(x1,x2) = max{9, x1 - 14, x2 - 1} map_0_A = 4 map_1_A(x1) = max{5, x1 - 15} D_1_A(x1) = max{10, x1 - 14} t_0_A = 1 |1|_0_A = 0 constant_0_A = 13 |0|_0_A = 0 filter_2_A(x1,x2) = max{14, x1 - 43, x2 - 5} nil_0_A = 0 base order 2: precedence: app = *_0 = filter_2 > filter2_3 = false_0 = filter_1 = *_1 = *_2 = -_2 > filter2_4# = filter_2# = cons_2 = -_1 = filter_0 = filter2_2 = map_1 = D_1 = t_0 = constant_0 = nil_0 > app# = true_0 = +_2 = -_0 = cons_1 = filter2_1 = map_0 = |1|_0 = |0|_0 > +_1 = cons_0 > +_0 partial status: pi(app#) = [1] pi(filter2_3) = [] pi(filter2_4#) = [] pi(true_0) = [] pi(filter_2#) = [] pi(cons_2) = [] pi(app) = [] pi(false_0) = [] pi(filter_1) = [] pi(*_0) = [] pi(*_1) = [] pi(*_2) = [] pi(+_0) = [] pi(+_1) = [] pi(+_2) = [] pi(-_0) = [] pi(-_1) = [] pi(-_2) = [] pi(cons_0) = [] pi(cons_1) = [] pi(filter_0) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(map_0) = [] pi(map_1) = [] pi(D_1) = [] pi(t_0) = [] pi(|1|_0) = [] pi(constant_0) = [] pi(|0|_0) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p5 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p2: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs) p3: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs) p4: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs) p5: app#(filter_1(x1),y) -> filter_2#(x1,y) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(filter_0(),y) -> filter_1(y) r11: app(filter_1(x1),y) -> filter_2(x1,y) r12: app(filter2_0(),y) -> filter2_1(y) r13: app(filter2_1(x1),y) -> filter2_2(x1,y) r14: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r15: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: D_1(t_0()) -> |1|_0() r19: D_1(constant_0()) -> |0|_0() r20: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r21: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r22: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r23: map_2(f,nil_0()) -> nil_0() r24: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r25: filter_2(f,nil_0()) -> nil_0() r26: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r27: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r28: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The estimated dependency graph contains the following SCCs: {p2, p3, p4} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs) p2: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs) p3: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(filter_0(),y) -> filter_1(y) r11: app(filter_1(x1),y) -> filter_2(x1,y) r12: app(filter2_0(),y) -> filter2_1(y) r13: app(filter2_1(x1),y) -> filter2_2(x1,y) r14: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r15: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: D_1(t_0()) -> |1|_0() r19: D_1(constant_0()) -> |0|_0() r20: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r21: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r22: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r23: map_2(f,nil_0()) -> nil_0() r24: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r25: filter_2(f,nil_0()) -> nil_0() r26: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r27: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r28: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of r1, r2, r3, r4, r5, r6, r7, r8, r9, r10, r11, r12, r13, r14, r15, r16, r17, r18, r19, r20, r21, r22, r23, r24, r25, r26, r27, r28 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: filter2_4#_A(x1,x2,x3,x4) = x1 + 2 true_0_A = 12 filter_2#_A(x1,x2) = 10 cons_2_A(x1,x2) = 2 app_A(x1,x2) = 7 false_0_A = 11 *_0_A = 2 *_1_A(x1) = 2 *_2_A(x1,x2) = 0 +_0_A = 2 +_1_A(x1) = 2 +_2_A(x1,x2) = 7 -_0_A = 2 -_1_A(x1) = 2 -_2_A(x1,x2) = 0 D_0_A = 2 D_1_A(x1) = 7 cons_0_A = 2 cons_1_A(x1) = 1 filter_0_A = 2 filter_1_A(x1) = 2 filter_2_A(x1,x2) = 6 filter2_0_A = 2 filter2_1_A(x1) = 2 filter2_2_A(x1,x2) = 0 filter2_3_A(x1,x2,x3) = 2 filter2_4_A(x1,x2,x3,x4) = 6 map_0_A = 5 map_1_A(x1) = 4 map_2_A(x1,x2) = 3 t_0_A = 2 |1|_0_A = 1 constant_0_A = 2 |0|_0_A = 1 nil_0_A = 2 base order 2: precedence: D_0 = filter_2 = filter2_4 = map_0 = nil_0 > filter2_4# = true_0 = false_0 > filter_2# > cons_2 = app = *_2 = -_2 = D_1 = map_2 = t_0 = constant_0 > *_1 = +_1 = +_2 = -_0 = -_1 = cons_1 = filter_1 = filter2_3 = map_1 = |1|_0 = |0|_0 > *_0 = +_0 = cons_0 = filter_0 = filter2_2 > filter2_1 > filter2_0 partial status: pi(filter2_4#) = [1] pi(true_0) = [] pi(filter_2#) = [] pi(cons_2) = [] pi(app) = [] pi(false_0) = [] pi(*_0) = [] pi(*_1) = [] pi(*_2) = [] pi(+_0) = [] pi(+_1) = [] pi(+_2) = [] pi(-_0) = [] pi(-_1) = [] pi(-_2) = [] pi(D_0) = [] pi(D_1) = [] pi(cons_0) = [] pi(cons_1) = [] pi(filter_0) = [] pi(filter_1) = [] pi(filter_2) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(filter2_3) = [] pi(filter2_4) = [] pi(map_0) = [] pi(map_1) = [] pi(map_2) = [] pi(t_0) = [] pi(|1|_0) = [] pi(constant_0) = [] pi(|0|_0) = [] pi(nil_0) = [] The following rules are removed: p1 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs) p2: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(filter_0(),y) -> filter_1(y) r11: app(filter_1(x1),y) -> filter_2(x1,y) r12: app(filter2_0(),y) -> filter2_1(y) r13: app(filter2_1(x1),y) -> filter2_2(x1,y) r14: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r15: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: D_1(t_0()) -> |1|_0() r19: D_1(constant_0()) -> |0|_0() r20: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r21: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r22: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r23: map_2(f,nil_0()) -> nil_0() r24: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r25: filter_2(f,nil_0()) -> nil_0() r26: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r27: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r28: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The estimated dependency graph contains the following SCCs: {p1, p2} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs) p2: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(filter_0(),y) -> filter_1(y) r11: app(filter_1(x1),y) -> filter_2(x1,y) r12: app(filter2_0(),y) -> filter2_1(y) r13: app(filter2_1(x1),y) -> filter2_2(x1,y) r14: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r15: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: D_1(t_0()) -> |1|_0() r19: D_1(constant_0()) -> |0|_0() r20: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r21: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r22: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r23: map_2(f,nil_0()) -> nil_0() r24: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r25: filter_2(f,nil_0()) -> nil_0() r26: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r27: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r28: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of r1, r2, r3, r4, r5, r6, r9, r10, r12, r13, r14, r18, r19, r25 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: filter_2#_A(x1,x2) = max{2, x2 + 1} cons_2_A(x1,x2) = max{15, x1 + 13, x2 + 4} filter2_4#_A(x1,x2,x3,x4) = max{x3 + 12, x4 + 3} app_A(x1,x2) = max{29, x1 - 31, x2 + 9} false_0_A = 10 *_0_A = 1 *_1_A(x1) = max{8, x1 - 1} *_2_A(x1,x2) = max{25, x1 - 36, x2 - 9} +_0_A = 1 +_1_A(x1) = max{0, x1 - 1} +_2_A(x1,x2) = max{28, x1 - 33} -_0_A = 9 -_1_A(x1) = max{10, x1 - 1} -_2_A(x1,x2) = max{11, x1 - 59, x2 - 23} cons_1_A(x1) = x1 + 45 filter_0_A = 27 filter_1_A(x1) = max{28, x1 - 12} filter2_0_A = 25 filter2_1_A(x1) = max{26, x1 - 1} filter2_2_A(x1,x2) = max{27, x1 - 33, x2 - 1} filter2_3_A(x1,x2,x3) = max{28, x1 - 65, x2 - 33, x3 - 1} D_1_A(x1) = max{8, x1 - 27} t_0_A = 26 |1|_0_A = 0 constant_0_A = 26 |0|_0_A = 0 filter_2_A(x1,x2) = max{30, x1 - 43, x2 - 16} nil_0_A = 1 base order 2: precedence: app = *_1 = *_2 = -_0 > filter_2# = *_0 = -_2 > cons_2 = -_1 = filter2_3 = D_1 = t_0 = constant_0 = filter_2 > filter2_4# = false_0 = +_2 = cons_1 = filter_1 = filter2_1 = filter2_2 = |1|_0 = |0|_0 = nil_0 > +_1 = filter_0 = filter2_0 > +_0 partial status: pi(filter_2#) = [2] pi(cons_2) = [1, 2] pi(filter2_4#) = [] pi(app) = [2] pi(false_0) = [] pi(*_0) = [] pi(*_1) = [] pi(*_2) = [] pi(+_0) = [] pi(+_1) = [] pi(+_2) = [] pi(-_0) = [] pi(-_1) = [] pi(-_2) = [] pi(cons_1) = [1] pi(filter_0) = [] pi(filter_1) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(filter2_3) = [] pi(D_1) = [] pi(t_0) = [] pi(|1|_0) = [] pi(constant_0) = [] pi(|0|_0) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p1 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(filter_0(),y) -> filter_1(y) r11: app(filter_1(x1),y) -> filter_2(x1,y) r12: app(filter2_0(),y) -> filter2_1(y) r13: app(filter2_1(x1),y) -> filter2_2(x1,y) r14: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r15: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: D_1(t_0()) -> |1|_0() r19: D_1(constant_0()) -> |0|_0() r20: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r21: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r22: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r23: map_2(f,nil_0()) -> nil_0() r24: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r25: filter_2(f,nil_0()) -> nil_0() r26: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r27: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r28: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The estimated dependency graph contains the following SCCs: (no SCCs) -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: D_1#(+_2(x,y)) -> D_1#(x) p2: D_1#(-_2(x,y)) -> D_1#(y) p3: D_1#(-_2(x,y)) -> D_1#(x) p4: D_1#(*_2(x,y)) -> D_1#(y) p5: D_1#(*_2(x,y)) -> D_1#(x) p6: D_1#(+_2(x,y)) -> D_1#(y) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(filter_0(),y) -> filter_1(y) r11: app(filter_1(x1),y) -> filter_2(x1,y) r12: app(filter2_0(),y) -> filter2_1(y) r13: app(filter2_1(x1),y) -> filter2_2(x1,y) r14: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r15: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: D_1(t_0()) -> |1|_0() r19: D_1(constant_0()) -> |0|_0() r20: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r21: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r22: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r23: map_2(f,nil_0()) -> nil_0() r24: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r25: filter_2(f,nil_0()) -> nil_0() r26: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r27: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r28: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of r1, r3, r5, r8, r9, r10, r12, r13, r16, r18, r19, r25 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: D_1#_A(x1) = max{8, x1 + 4} +_2_A(x1,x2) = max{18, x1 + 5, x2 + 7} -_2_A(x1,x2) = max{39, x1 + 26, x2 + 13} *_2_A(x1,x2) = max{17, x1 + 10, x2 + 9} app_A(x1,x2) = max{16, x1 - 3, x2 - 9} *_0_A = 1 *_1_A(x1) = max{2, x1 - 9} +_0_A = 2 +_1_A(x1) = max{1, x1 - 10} -_0_A = 2 -_1_A(x1) = max{1, x1 - 10} cons_0_A = 1 cons_1_A(x1) = max{2, x1 - 10} cons_2_A(x1,x2) = max{7, x1 - 17, x2 - 10} filter_0_A = 2 filter_1_A(x1) = max{4, x1 - 10} filter2_0_A = 2 filter2_1_A(x1) = max{0, x1 - 10} filter2_2_A(x1,x2) = max{0, x1 - 14, x2 - 10} map_0_A = 1 map_1_A(x1) = max{2, x1 - 21} D_1_A(x1) = max{12, x1 - 40} t_0_A = 1 |1|_0_A = 0 constant_0_A = 1 |0|_0_A = 0 filter_2_A(x1,x2) = max{5, x1 - 14, x2 - 10} nil_0_A = 0 base order 2: precedence: +_2 > -_2 = *_2 > D_1# = app = -_0 > *_1 = +_1 = -_1 = cons_2 = map_1 = D_1 = t_0 = constant_0 > *_0 = +_0 = cons_1 = map_0 = |1|_0 = |0|_0 = filter_2 > cons_0 = filter_1 = filter2_0 = filter2_2 = nil_0 > filter_0 = filter2_1 partial status: pi(D_1#) = [1] pi(+_2) = [] pi(-_2) = [2] pi(*_2) = [2] pi(app) = [] pi(*_0) = [] pi(*_1) = [] pi(+_0) = [] pi(+_1) = [] pi(-_0) = [] pi(-_1) = [] pi(cons_0) = [] pi(cons_1) = [] pi(cons_2) = [] pi(filter_0) = [] pi(filter_1) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(map_0) = [] pi(map_1) = [] pi(D_1) = [] pi(t_0) = [] pi(|1|_0) = [] pi(constant_0) = [] pi(|0|_0) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p6 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: D_1#(+_2(x,y)) -> D_1#(x) p2: D_1#(-_2(x,y)) -> D_1#(y) p3: D_1#(-_2(x,y)) -> D_1#(x) p4: D_1#(*_2(x,y)) -> D_1#(y) p5: D_1#(*_2(x,y)) -> D_1#(x) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(filter_0(),y) -> filter_1(y) r11: app(filter_1(x1),y) -> filter_2(x1,y) r12: app(filter2_0(),y) -> filter2_1(y) r13: app(filter2_1(x1),y) -> filter2_2(x1,y) r14: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r15: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: D_1(t_0()) -> |1|_0() r19: D_1(constant_0()) -> |0|_0() r20: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r21: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r22: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r23: map_2(f,nil_0()) -> nil_0() r24: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r25: filter_2(f,nil_0()) -> nil_0() r26: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r27: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r28: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The estimated dependency graph contains the following SCCs: {p1, p2, p3, p4, p5} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: D_1#(+_2(x,y)) -> D_1#(x) p2: D_1#(*_2(x,y)) -> D_1#(x) p3: D_1#(*_2(x,y)) -> D_1#(y) p4: D_1#(-_2(x,y)) -> D_1#(x) p5: D_1#(-_2(x,y)) -> D_1#(y) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(filter_0(),y) -> filter_1(y) r11: app(filter_1(x1),y) -> filter_2(x1,y) r12: app(filter2_0(),y) -> filter2_1(y) r13: app(filter2_1(x1),y) -> filter2_2(x1,y) r14: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r15: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: D_1(t_0()) -> |1|_0() r19: D_1(constant_0()) -> |0|_0() r20: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r21: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r22: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r23: map_2(f,nil_0()) -> nil_0() r24: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r25: filter_2(f,nil_0()) -> nil_0() r26: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r27: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r28: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of r1, r3, r5, r8, r9, r10, r12, r14, r16, r18, r19, r25 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: D_1#_A(x1) = x1 + 28 +_2_A(x1,x2) = max{x1 + 34, x2 - 14} *_2_A(x1,x2) = max{x1 + 31, x2 + 65} -_2_A(x1,x2) = max{x1 + 61, x2 + 29} app_A(x1,x2) = max{31, x1 - 5, x2 - 14} *_0_A = 3 *_1_A(x1) = max{4, x1 - 15} +_0_A = 3 +_1_A(x1) = max{4, x1 - 15} -_0_A = 4 -_1_A(x1) = max{3, x1 - 14} cons_0_A = 1 cons_1_A(x1) = max{2, x1 - 15} cons_2_A(x1,x2) = max{14, x1 - 32, x2 - 16} filter_0_A = 3 filter_1_A(x1) = max{4, x1 - 19} filter2_0_A = 1 filter2_1_A(x1) = max{2, x1 - 15} filter2_2_A(x1,x2) = max{3, x1 - 1, x2 + 1} filter2_3_A(x1,x2,x3) = max{4, x1 - 6, x2 - 14, x3 - 14} map_0_A = 1 map_1_A(x1) = max{2, x1 - 15} D_1_A(x1) = max{30, x1 - 67} t_0_A = 1 |1|_0_A = 0 constant_0_A = 66 |0|_0_A = 0 filter_2_A(x1,x2) = max{18, x1 - 18, x2 + 1} nil_0_A = 14 base order 2: precedence: +_2 = *_2 = -_2 > D_1# = app > *_1 = +_1 = -_1 = cons_0 = map_1 = D_1 = t_0 = constant_0 = filter_2 > *_0 = +_0 = -_0 = cons_2 = filter_1 = filter2_3 = map_0 = |1|_0 = |0|_0 = nil_0 > cons_1 = filter_0 = filter2_2 > filter2_1 > filter2_0 partial status: pi(D_1#) = [1] pi(+_2) = [] pi(*_2) = [2] pi(-_2) = [2] pi(app) = [] pi(*_0) = [] pi(*_1) = [] pi(+_0) = [] pi(+_1) = [] pi(-_0) = [] pi(-_1) = [] pi(cons_0) = [] pi(cons_1) = [] pi(cons_2) = [] pi(filter_0) = [] pi(filter_1) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [2] pi(filter2_3) = [] pi(map_0) = [] pi(map_1) = [] pi(D_1) = [] pi(t_0) = [] pi(|1|_0) = [] pi(constant_0) = [] pi(|0|_0) = [] pi(filter_2) = [2] pi(nil_0) = [] The following rules are removed: p5 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: D_1#(+_2(x,y)) -> D_1#(x) p2: D_1#(*_2(x,y)) -> D_1#(x) p3: D_1#(*_2(x,y)) -> D_1#(y) p4: D_1#(-_2(x,y)) -> D_1#(x) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(filter_0(),y) -> filter_1(y) r11: app(filter_1(x1),y) -> filter_2(x1,y) r12: app(filter2_0(),y) -> filter2_1(y) r13: app(filter2_1(x1),y) -> filter2_2(x1,y) r14: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r15: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: D_1(t_0()) -> |1|_0() r19: D_1(constant_0()) -> |0|_0() r20: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r21: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r22: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r23: map_2(f,nil_0()) -> nil_0() r24: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r25: filter_2(f,nil_0()) -> nil_0() r26: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r27: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r28: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The estimated dependency graph contains the following SCCs: {p1, p2, p3, p4} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: D_1#(+_2(x,y)) -> D_1#(x) p2: D_1#(-_2(x,y)) -> D_1#(x) p3: D_1#(*_2(x,y)) -> D_1#(y) p4: D_1#(*_2(x,y)) -> D_1#(x) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(filter_0(),y) -> filter_1(y) r11: app(filter_1(x1),y) -> filter_2(x1,y) r12: app(filter2_0(),y) -> filter2_1(y) r13: app(filter2_1(x1),y) -> filter2_2(x1,y) r14: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r15: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: D_1(t_0()) -> |1|_0() r19: D_1(constant_0()) -> |0|_0() r20: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r21: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r22: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r23: map_2(f,nil_0()) -> nil_0() r24: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r25: filter_2(f,nil_0()) -> nil_0() r26: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r27: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r28: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of r1, r3, r5, r8, r9, r10, r12, r13, r14, r16, r18, r19, r25 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: D_1#_A(x1) = x1 + 20 +_2_A(x1,x2) = max{x1 + 23, x2 - 9} -_2_A(x1,x2) = max{x1 + 21, x2 - 9} *_2_A(x1,x2) = max{x1 + 28, x2 + 21} app_A(x1,x2) = max{57, x1 - 24, x2 + 3} *_0_A = 1 *_1_A(x1) = max{2, x1 - 1} +_0_A = 22 +_1_A(x1) = max{23, x1 - 1} -_0_A = 23 -_1_A(x1) = max{10, x1 - 1} cons_0_A = 4 cons_1_A(x1) = max{5, x1 - 1} cons_2_A(x1,x2) = max{4, x1 - 58, x2 - 64} filter_0_A = 1 filter_1_A(x1) = max{4, x1 - 1} filter2_0_A = 21 filter2_1_A(x1) = max{22, x1 - 1} filter2_2_A(x1,x2) = max{23, x1 - 26, x2 - 27} filter2_3_A(x1,x2,x3) = max{22, x1 - 51, x2 - 52} map_0_A = 3 map_1_A(x1) = max{4, x1 - 3} D_1_A(x1) = max{8, x1 - 45} t_0_A = 1 |1|_0_A = 0 constant_0_A = 1 |0|_0_A = 0 filter_2_A(x1,x2) = max{14, x1 - 77, x2 - 52} nil_0_A = 0 base order 2: precedence: +_2 = -_2 = *_2 > D_1# = app = *_0 = map_0 > *_1 = +_1 = -_1 = cons_2 = filter2_1 = filter2_2 = map_1 = D_1 = t_0 = constant_0 = filter_2 > +_0 = -_0 = cons_1 = filter_1 = filter2_0 = filter2_3 = |1|_0 = |0|_0 = nil_0 > cons_0 = filter_0 partial status: pi(D_1#) = [1] pi(+_2) = [] pi(-_2) = [1] pi(*_2) = [2] pi(app) = [] pi(*_0) = [] pi(*_1) = [] pi(+_0) = [] pi(+_1) = [] pi(-_0) = [] pi(-_1) = [] pi(cons_0) = [] pi(cons_1) = [] pi(cons_2) = [] pi(filter_0) = [] pi(filter_1) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(filter2_3) = [] pi(map_0) = [] pi(map_1) = [] pi(D_1) = [] pi(t_0) = [] pi(|1|_0) = [] pi(constant_0) = [] pi(|0|_0) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p4 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: D_1#(+_2(x,y)) -> D_1#(x) p2: D_1#(-_2(x,y)) -> D_1#(x) p3: D_1#(*_2(x,y)) -> D_1#(y) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(filter_0(),y) -> filter_1(y) r11: app(filter_1(x1),y) -> filter_2(x1,y) r12: app(filter2_0(),y) -> filter2_1(y) r13: app(filter2_1(x1),y) -> filter2_2(x1,y) r14: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r15: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: D_1(t_0()) -> |1|_0() r19: D_1(constant_0()) -> |0|_0() r20: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r21: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r22: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r23: map_2(f,nil_0()) -> nil_0() r24: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r25: filter_2(f,nil_0()) -> nil_0() r26: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r27: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r28: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The estimated dependency graph contains the following SCCs: {p1, p2, p3} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: D_1#(+_2(x,y)) -> D_1#(x) p2: D_1#(*_2(x,y)) -> D_1#(y) p3: D_1#(-_2(x,y)) -> D_1#(x) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(filter_0(),y) -> filter_1(y) r11: app(filter_1(x1),y) -> filter_2(x1,y) r12: app(filter2_0(),y) -> filter2_1(y) r13: app(filter2_1(x1),y) -> filter2_2(x1,y) r14: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r15: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: D_1(t_0()) -> |1|_0() r19: D_1(constant_0()) -> |0|_0() r20: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r21: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r22: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r23: map_2(f,nil_0()) -> nil_0() r24: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r25: filter_2(f,nil_0()) -> nil_0() r26: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r27: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r28: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of r1, r3, r5, r8, r10, r12, r13, r14, r16, r18, r19, r25 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: D_1#_A(x1) = x1 + 11 +_2_A(x1,x2) = max{52, x1 + 26, x2 - 9} *_2_A(x1,x2) = max{x1 - 1, x2 + 51} -_2_A(x1,x2) = max{x1 + 25, x2 - 6} app_A(x1,x2) = max{32, x1 - 5, x2 - 10} *_0_A = 4 *_1_A(x1) = max{3, x1 - 11} +_0_A = 3 +_1_A(x1) = max{4, x1 - 10} -_0_A = 3 -_1_A(x1) = max{4, x1 - 10} cons_0_A = 2 cons_1_A(x1) = max{3, x1 - 32} filter_0_A = 1 filter_1_A(x1) = max{2, x1 - 28} filter2_0_A = 1 filter2_1_A(x1) = max{2, x1 - 11} filter2_2_A(x1,x2) = max{3, x1 - 17, x2 - 11} filter2_3_A(x1,x2,x3) = max{4, x1 - 23, x2 - 16, x3 - 11} map_0_A = 3 map_1_A(x1) = max{4, x1 - 43} D_1_A(x1) = max{5, x1 - 27} t_0_A = 26 |1|_0_A = 0 constant_0_A = 26 |0|_0_A = 0 filter_2_A(x1,x2) = max{3, x1 - 34, x2 - 11} nil_0_A = 0 base order 2: precedence: +_2 > *_2 = -_2 = filter2_2 > D_1# = app = +_0 = -_0 > *_1 = +_1 = -_1 = cons_1 = filter_1 = filter2_1 = map_1 = D_1 = t_0 = constant_0 = filter_2 > *_0 = cons_0 = filter_0 = filter2_0 = filter2_3 = map_0 = |1|_0 = |0|_0 = nil_0 partial status: pi(D_1#) = [1] pi(+_2) = [] pi(*_2) = [2] pi(-_2) = [1] pi(app) = [] pi(*_0) = [] pi(*_1) = [] pi(+_0) = [] pi(+_1) = [] pi(-_0) = [] pi(-_1) = [] pi(cons_0) = [] pi(cons_1) = [] pi(filter_0) = [] pi(filter_1) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(filter2_3) = [] pi(map_0) = [] pi(map_1) = [] pi(D_1) = [] pi(t_0) = [] pi(|1|_0) = [] pi(constant_0) = [] pi(|0|_0) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p3 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: D_1#(+_2(x,y)) -> D_1#(x) p2: D_1#(*_2(x,y)) -> D_1#(y) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(filter_0(),y) -> filter_1(y) r11: app(filter_1(x1),y) -> filter_2(x1,y) r12: app(filter2_0(),y) -> filter2_1(y) r13: app(filter2_1(x1),y) -> filter2_2(x1,y) r14: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r15: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: D_1(t_0()) -> |1|_0() r19: D_1(constant_0()) -> |0|_0() r20: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r21: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r22: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r23: map_2(f,nil_0()) -> nil_0() r24: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r25: filter_2(f,nil_0()) -> nil_0() r26: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r27: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r28: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The estimated dependency graph contains the following SCCs: {p1, p2} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: D_1#(+_2(x,y)) -> D_1#(x) p2: D_1#(*_2(x,y)) -> D_1#(y) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(filter_0(),y) -> filter_1(y) r11: app(filter_1(x1),y) -> filter_2(x1,y) r12: app(filter2_0(),y) -> filter2_1(y) r13: app(filter2_1(x1),y) -> filter2_2(x1,y) r14: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r15: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: D_1(t_0()) -> |1|_0() r19: D_1(constant_0()) -> |0|_0() r20: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r21: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r22: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r23: map_2(f,nil_0()) -> nil_0() r24: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r25: filter_2(f,nil_0()) -> nil_0() r26: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r27: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r28: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of r1, r3, r5, r6, r8, r9, r10, r12, r14, r16, r18, r19, r25 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: D_1#_A(x1) = x1 + 69 +_2_A(x1,x2) = max{x1 + 107, x2 - 34} *_2_A(x1,x2) = max{x1 - 34, x2 + 70} app_A(x1,x2) = max{32, x1 - 5, x2 - 12} *_0_A = 1 *_1_A(x1) = max{2, x1 - 35} +_0_A = 3 +_1_A(x1) = max{4, x1 - 13} -_0_A = 4 -_1_A(x1) = max{3, x1 - 56} -_2_A(x1,x2) = max{31, x1 - 62, x2 - 31} cons_0_A = 1 cons_1_A(x1) = max{2, x1 - 12} cons_2_A(x1,x2) = max{3, x1 - 45, x2 - 12} filter_0_A = 3 filter_1_A(x1) = max{4, x1 - 12} filter2_0_A = 1 filter2_1_A(x1) = max{2, x1 - 13} filter2_2_A(x1,x2) = max{x1 - 1, x2 + 10} filter2_3_A(x1,x2,x3) = max{4, x1 - 7, x2 - 1, x3 - 13} map_0_A = 3 map_1_A(x1) = max{4, x1 - 13} D_1_A(x1) = max{30, x1 - 76} t_0_A = 75 |1|_0_A = 29 constant_0_A = 1 |0|_0_A = 0 filter_2_A(x1,x2) = max{18, x1 - 18, x2 - 14} nil_0_A = 0 base order 2: precedence: +_2 > app = -_0 > +_1 = -_2 = map_1 > +_0 = -_1 = cons_2 = filter2_3 = map_0 = D_1 = t_0 = constant_0 = filter_2 > *_2 = cons_1 = filter_1 = filter2_2 = |1|_0 = |0|_0 = nil_0 > D_1# = *_1 = cons_0 = filter_0 = filter2_1 > *_0 = filter2_0 partial status: pi(D_1#) = [1] pi(+_2) = [] pi(*_2) = [2] pi(app) = [] pi(*_0) = [] pi(*_1) = [] pi(+_0) = [] pi(+_1) = [] pi(-_0) = [] pi(-_1) = [] pi(-_2) = [] pi(cons_0) = [] pi(cons_1) = [] pi(cons_2) = [] pi(filter_0) = [] pi(filter_1) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(filter2_3) = [] pi(map_0) = [] pi(map_1) = [] pi(D_1) = [] pi(t_0) = [] pi(|1|_0) = [] pi(constant_0) = [] pi(|0|_0) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p2 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: D_1#(+_2(x,y)) -> D_1#(x) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(filter_0(),y) -> filter_1(y) r11: app(filter_1(x1),y) -> filter_2(x1,y) r12: app(filter2_0(),y) -> filter2_1(y) r13: app(filter2_1(x1),y) -> filter2_2(x1,y) r14: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r15: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: D_1(t_0()) -> |1|_0() r19: D_1(constant_0()) -> |0|_0() r20: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r21: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r22: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r23: map_2(f,nil_0()) -> nil_0() r24: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r25: filter_2(f,nil_0()) -> nil_0() r26: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r27: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r28: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The estimated dependency graph contains the following SCCs: {p1} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: D_1#(+_2(x,y)) -> D_1#(x) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(filter_0(),y) -> filter_1(y) r11: app(filter_1(x1),y) -> filter_2(x1,y) r12: app(filter2_0(),y) -> filter2_1(y) r13: app(filter2_1(x1),y) -> filter2_2(x1,y) r14: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r15: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: D_1(t_0()) -> |1|_0() r19: D_1(constant_0()) -> |0|_0() r20: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r21: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r22: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r23: map_2(f,nil_0()) -> nil_0() r24: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r25: filter_2(f,nil_0()) -> nil_0() r26: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r27: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r28: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of r1, r2, r3, r8, r9, r10, r12, r13, r14, r16, r18, r19, r25 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: D_1#_A(x1) = x1 + 13 +_2_A(x1,x2) = max{x1 + 14, x2 - 4} app_A(x1,x2) = max{6, x1 - 7, x2 - 5} *_0_A = 1 *_1_A(x1) = max{2, x1 - 6} *_2_A(x1,x2) = max{3, x1 - 17, x2 - 17} +_0_A = 4 +_1_A(x1) = max{5, x1 - 6} cons_0_A = 6 cons_1_A(x1) = max{1, x1 - 28} cons_2_A(x1,x2) = max{2, x1 - 35, x2 - 7} filter_0_A = 2 filter_1_A(x1) = max{3, x1 - 29} filter2_0_A = 3 filter2_1_A(x1) = max{4, x1 - 6} filter2_2_A(x1,x2) = max{5, x1 - 14, x2 - 6} filter2_3_A(x1,x2,x3) = max{6, x1 - 21, x2 - 14, x3 - 5} map_0_A = 3 map_1_A(x1) = max{4, x1 - 6} D_1_A(x1) = max{2, x1 - 23} t_0_A = 22 |1|_0_A = 0 constant_0_A = 22 |0|_0_A = 0 filter_2_A(x1,x2) = max{4, x1 - 37, x2 - 26} nil_0_A = 0 base order 2: precedence: filter_0 > +_2 = filter_1 = filter_2 = nil_0 > app > *_1 = *_2 = filter2_3 > D_1# = *_0 = +_1 = cons_0 = cons_2 = filter2_2 = map_1 = D_1 = t_0 = constant_0 > +_0 = cons_1 = filter2_1 = map_0 = |1|_0 = |0|_0 > filter2_0 partial status: pi(D_1#) = [1] pi(+_2) = [1] pi(app) = [] pi(*_0) = [] pi(*_1) = [] pi(*_2) = [] pi(+_0) = [] pi(+_1) = [] pi(cons_0) = [] pi(cons_1) = [] pi(cons_2) = [] pi(filter_0) = [] pi(filter_1) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(filter2_3) = [] pi(map_0) = [] pi(map_1) = [] pi(D_1) = [] pi(t_0) = [] pi(|1|_0) = [] pi(constant_0) = [] pi(|0|_0) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p1 Then no dependency pair remains.