YES We show the termination of the TRS R: app(g(),app(h(),app(g(),x))) -> app(g(),x) app(g(),app(g(),x)) -> app(g(),app(h(),app(g(),x))) app(h(),app(h(),x)) -> app(h(),app(app(f(),app(h(),x)),x)) app(app(map(),|fun|),nil()) -> nil() app(app(map(),|fun|),app(app(cons(),x),xs)) -> app(app(cons(),app(|fun|,x)),app(app(map(),|fun|),xs)) app(app(filter(),|fun|),nil()) -> nil() app(app(filter(),|fun|),app(app(cons(),x),xs)) -> app(app(app(app(filter2(),app(|fun|,x)),|fun|),x),xs) app(app(app(app(filter2(),true()),|fun|),x),xs) -> app(app(cons(),x),app(app(filter(),|fun|),xs)) app(app(app(app(filter2(),false()),|fun|),x),xs) -> app(app(filter(),|fun|),xs) Instead we prove termination of the uncurried system: app(cons_0(),y) -> cons_1(y) app(cons_1(x1),y) -> cons_2(x1,y) app(f_0(),y) -> f_1(y) app(f_1(x1),y) -> f_2(x1,y) app(filter_0(),y) -> filter_1(y) app(filter_1(x1),y) -> filter_2(x1,y) app(filter2_0(),y) -> filter2_1(y) app(filter2_1(x1),y) -> filter2_2(x1,y) app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) app(g_0(),y) -> g_1(y) app(h_0(),y) -> h_1(y) app(map_0(),y) -> map_1(y) app(map_1(x1),y) -> map_2(x1,y) g_1(h_1(g_1(x))) -> g_1(x) g_1(g_1(x)) -> g_1(h_1(g_1(x))) h_1(h_1(x)) -> h_1(f_2(h_1(x),x)) map_2(|fun|,nil_0()) -> nil_0() map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) filter_2(|fun|,nil_0()) -> nil_0() filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: app#(filter_1(x1),y) -> filter_2#(x1,y) p2: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p3: app#(g_0(),y) -> g_1#(y) p4: app#(h_0(),y) -> h_1#(y) p5: app#(map_1(x1),y) -> map_2#(x1,y) p6: g_1#(g_1(x)) -> g_1#(h_1(g_1(x))) p7: g_1#(g_1(x)) -> h_1#(g_1(x)) p8: h_1#(h_1(x)) -> h_1#(f_2(h_1(x),x)) p9: map_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p10: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) p11: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p12: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p13: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p14: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(filter2_0(),y) -> filter2_1(y) r8: app(filter2_1(x1),y) -> filter2_2(x1,y) r9: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r10: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r11: app(g_0(),y) -> g_1(y) r12: app(h_0(),y) -> h_1(y) r13: app(map_0(),y) -> map_1(y) r14: app(map_1(x1),y) -> map_2(x1,y) r15: g_1(h_1(g_1(x))) -> g_1(x) r16: g_1(g_1(x)) -> g_1(h_1(g_1(x))) r17: h_1(h_1(x)) -> h_1(f_2(h_1(x),x)) r18: map_2(|fun|,nil_0()) -> nil_0() r19: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r20: filter_2(|fun|,nil_0()) -> nil_0() r21: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r22: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r23: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The estimated dependency graph contains the following SCCs: {p1, p2, p5, p9, p10, p11, p12, p13, p14} {p6} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: app#(filter_1(x1),y) -> filter_2#(x1,y) p2: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p3: app#(map_1(x1),y) -> map_2#(x1,y) p4: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) p5: map_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p6: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p7: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p8: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p9: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(filter2_0(),y) -> filter2_1(y) r8: app(filter2_1(x1),y) -> filter2_2(x1,y) r9: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r10: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r11: app(g_0(),y) -> g_1(y) r12: app(h_0(),y) -> h_1(y) r13: app(map_0(),y) -> map_1(y) r14: app(map_1(x1),y) -> map_2(x1,y) r15: g_1(h_1(g_1(x))) -> g_1(x) r16: g_1(g_1(x)) -> g_1(h_1(g_1(x))) r17: h_1(h_1(x)) -> h_1(f_2(h_1(x),x)) r18: map_2(|fun|,nil_0()) -> nil_0() r19: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r20: filter_2(|fun|,nil_0()) -> nil_0() r21: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r22: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r23: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r1, r2, r3, r4, r5, r7, r8, r13, r20 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: app#_A(x1,x2) = max{1, x1} filter_1_A(x1) = max{6, x1 + 4} filter_2#_A(x1,x2) = x1 + 3 cons_2_A(x1,x2) = max{9, x1 - 13, x2 - 13} map_1_A(x1) = max{10, x1 + 3} map_2#_A(x1,x2) = x1 + 2 filter2_3_A(x1,x2,x3) = max{x1 + 1, x2 + 3, x3 + 1} filter2_4#_A(x1,x2,x3,x4) = x2 + 3 false_0_A = 6 app_A(x1,x2) = max{21, x1 - 11, x2 + 5} true_0_A = 6 cons_0_A = 9 cons_1_A(x1) = max{10, x1 - 1} f_0_A = 9 f_1_A(x1) = max{10, x1 - 12} f_2_A(x1,x2) = max{9, x1 - 23, x2 - 45} filter_0_A = 5 filter2_0_A = 5 filter2_1_A(x1) = max{6, x1 - 1} filter2_2_A(x1,x2) = max{1, x1 - 13, x2 - 1} map_0_A = 9 filter_2_A(x1,x2) = max{9, x1 - 23, x2 - 10} nil_0_A = 0 base order 2: precedence: app > cons_2 > map_1 = f_2 > map_2# = f_1 > app# = filter2_3 = f_0 > filter_2# = filter2_4# = filter_0 > filter_1 = cons_1 = filter2_2 = map_0 = filter_2 > false_0 = true_0 = cons_0 = filter2_1 = nil_0 > filter2_0 partial status: pi(app#) = [1] pi(filter_1) = [] pi(filter_2#) = [] pi(cons_2) = [] pi(map_1) = [1] pi(map_2#) = [1] pi(filter2_3) = [2] pi(filter2_4#) = [] pi(false_0) = [] pi(app) = [2] pi(true_0) = [] pi(cons_0) = [] pi(cons_1) = [] pi(f_0) = [] pi(f_1) = [] pi(f_2) = [] pi(filter_0) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(map_0) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p6 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: app#(filter_1(x1),y) -> filter_2#(x1,y) p2: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p3: app#(map_1(x1),y) -> map_2#(x1,y) p4: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) p5: map_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p6: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p7: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p8: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(filter2_0(),y) -> filter2_1(y) r8: app(filter2_1(x1),y) -> filter2_2(x1,y) r9: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r10: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r11: app(g_0(),y) -> g_1(y) r12: app(h_0(),y) -> h_1(y) r13: app(map_0(),y) -> map_1(y) r14: app(map_1(x1),y) -> map_2(x1,y) r15: g_1(h_1(g_1(x))) -> g_1(x) r16: g_1(g_1(x)) -> g_1(h_1(g_1(x))) r17: h_1(h_1(x)) -> h_1(f_2(h_1(x),x)) r18: map_2(|fun|,nil_0()) -> nil_0() r19: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r20: filter_2(|fun|,nil_0()) -> nil_0() r21: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r22: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r23: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The estimated dependency graph contains the following SCCs: {p1, p2, p3, p4, p5, p6, p7, p8} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: app#(filter_1(x1),y) -> filter_2#(x1,y) p2: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p3: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p4: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p5: app#(map_1(x1),y) -> map_2#(x1,y) p6: map_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p7: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) p8: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(filter2_0(),y) -> filter2_1(y) r8: app(filter2_1(x1),y) -> filter2_2(x1,y) r9: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r10: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r11: app(g_0(),y) -> g_1(y) r12: app(h_0(),y) -> h_1(y) r13: app(map_0(),y) -> map_1(y) r14: app(map_1(x1),y) -> map_2(x1,y) r15: g_1(h_1(g_1(x))) -> g_1(x) r16: g_1(g_1(x)) -> g_1(h_1(g_1(x))) r17: h_1(h_1(x)) -> h_1(f_2(h_1(x),x)) r18: map_2(|fun|,nil_0()) -> nil_0() r19: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r20: filter_2(|fun|,nil_0()) -> nil_0() r21: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r22: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r23: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r1, r2, r3, r4, r7, r8, r9, r20 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: app#_A(x1,x2) = max{4, x1} filter_1_A(x1) = max{8, x1 + 7} filter_2#_A(x1,x2) = x1 + 6 cons_2_A(x1,x2) = max{3, x1 - 23, x2 - 23} filter2_4#_A(x1,x2,x3,x4) = x2 + 6 app_A(x1,x2) = max{8, x1 - 9, x2 - 9} true_0_A = 1 map_1_A(x1) = x1 + 6 map_2#_A(x1,x2) = max{6, x1 + 5} false_0_A = 4 cons_0_A = 1 cons_1_A(x1) = max{2, x1 - 10} f_0_A = 3 f_1_A(x1) = max{4, x1 - 9} f_2_A(x1,x2) = max{5, x1 - 19, x2 - 29} filter2_0_A = 7 filter2_1_A(x1) = max{8, x1 - 9} filter2_2_A(x1,x2) = max{6, x1 - 19, x2 - 10} filter2_3_A(x1,x2,x3) = max{7, x1 - 29, x2 - 44, x3 - 23} filter_2_A(x1,x2) = max{8, x1 - 29, x2 - 8} nil_0_A = 0 base order 2: precedence: filter_2 > app > filter_1 = map_1 = false_0 > filter_2# = filter2_4# = nil_0 > cons_2 = f_2 > app# = true_0 = cons_1 = f_1 = filter2_3 > map_2# = cons_0 = f_0 = filter2_2 > filter2_1 > filter2_0 partial status: pi(app#) = [1] pi(filter_1) = [] pi(filter_2#) = [] pi(cons_2) = [] pi(filter2_4#) = [] pi(app) = [] pi(true_0) = [] pi(map_1) = [1] pi(map_2#) = [1] pi(false_0) = [] pi(cons_0) = [] pi(cons_1) = [] pi(f_0) = [] pi(f_1) = [] pi(f_2) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(filter2_3) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p6 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: app#(filter_1(x1),y) -> filter_2#(x1,y) p2: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p3: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p4: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p5: app#(map_1(x1),y) -> map_2#(x1,y) p6: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) p7: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(filter2_0(),y) -> filter2_1(y) r8: app(filter2_1(x1),y) -> filter2_2(x1,y) r9: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r10: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r11: app(g_0(),y) -> g_1(y) r12: app(h_0(),y) -> h_1(y) r13: app(map_0(),y) -> map_1(y) r14: app(map_1(x1),y) -> map_2(x1,y) r15: g_1(h_1(g_1(x))) -> g_1(x) r16: g_1(g_1(x)) -> g_1(h_1(g_1(x))) r17: h_1(h_1(x)) -> h_1(f_2(h_1(x),x)) r18: map_2(|fun|,nil_0()) -> nil_0() r19: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r20: filter_2(|fun|,nil_0()) -> nil_0() r21: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r22: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r23: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The estimated dependency graph contains the following SCCs: {p1, p2, p3, p4, p7} {p6} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: app#(filter_1(x1),y) -> filter_2#(x1,y) p2: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p3: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p4: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p5: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(filter2_0(),y) -> filter2_1(y) r8: app(filter2_1(x1),y) -> filter2_2(x1,y) r9: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r10: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r11: app(g_0(),y) -> g_1(y) r12: app(h_0(),y) -> h_1(y) r13: app(map_0(),y) -> map_1(y) r14: app(map_1(x1),y) -> map_2(x1,y) r15: g_1(h_1(g_1(x))) -> g_1(x) r16: g_1(g_1(x)) -> g_1(h_1(g_1(x))) r17: h_1(h_1(x)) -> h_1(f_2(h_1(x),x)) r18: map_2(|fun|,nil_0()) -> nil_0() r19: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r20: filter_2(|fun|,nil_0()) -> nil_0() r21: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r22: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r23: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r1, r2, r3, r4, r7, r8, r9, r13, r20 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: app#_A(x1,x2) = max{1, x1 - 4} filter_1_A(x1) = x1 + 7 filter_2#_A(x1,x2) = max{2, x1 - 3} cons_2_A(x1,x2) = max{10, x1 - 28, x2 - 28} filter2_4#_A(x1,x2,x3,x4) = max{2, x2 - 3} app_A(x1,x2) = max{27, x1 - 13, x2 - 13} false_0_A = 1 true_0_A = 1 cons_0_A = 8 cons_1_A(x1) = max{9, x1 - 14} f_0_A = 11 f_1_A(x1) = max{12, x1 - 14} f_2_A(x1,x2) = max{13, x1 - 31, x2 - 61} filter2_0_A = 12 filter2_1_A(x1) = max{0, x1 - 14} filter2_2_A(x1,x2) = max{0, x1 - 28, x2 - 14} filter2_3_A(x1,x2,x3) = max{0, x1 - 42, x2 - 28, x3 - 14} map_0_A = 11 map_1_A(x1) = max{12, x1 - 28} filter_2_A(x1,x2) = max{8, x1 - 43, x2 - 22} nil_0_A = 0 base order 2: precedence: app > filter_2# = filter2_4# > app# > cons_2 > cons_1 = f_0 = filter2_3 = map_1 = filter_2 > filter_1 = false_0 = true_0 = cons_0 = f_2 = filter2_2 = map_0 = nil_0 > f_1 = filter2_1 > filter2_0 partial status: pi(app#) = [] pi(filter_1) = [1] pi(filter_2#) = [] pi(cons_2) = [] pi(filter2_4#) = [] pi(app) = [] pi(false_0) = [] pi(true_0) = [] pi(cons_0) = [] pi(cons_1) = [] pi(f_0) = [] pi(f_1) = [] pi(f_2) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(filter2_3) = [] pi(map_0) = [] pi(map_1) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p1 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p2: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p3: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p4: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(filter2_0(),y) -> filter2_1(y) r8: app(filter2_1(x1),y) -> filter2_2(x1,y) r9: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r10: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r11: app(g_0(),y) -> g_1(y) r12: app(h_0(),y) -> h_1(y) r13: app(map_0(),y) -> map_1(y) r14: app(map_1(x1),y) -> map_2(x1,y) r15: g_1(h_1(g_1(x))) -> g_1(x) r16: g_1(g_1(x)) -> g_1(h_1(g_1(x))) r17: h_1(h_1(x)) -> h_1(f_2(h_1(x),x)) r18: map_2(|fun|,nil_0()) -> nil_0() r19: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r20: filter_2(|fun|,nil_0()) -> nil_0() r21: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r22: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r23: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The estimated dependency graph contains the following SCCs: {p2, p3, p4} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p2: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p3: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(filter2_0(),y) -> filter2_1(y) r8: app(filter2_1(x1),y) -> filter2_2(x1,y) r9: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r10: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r11: app(g_0(),y) -> g_1(y) r12: app(h_0(),y) -> h_1(y) r13: app(map_0(),y) -> map_1(y) r14: app(map_1(x1),y) -> map_2(x1,y) r15: g_1(h_1(g_1(x))) -> g_1(x) r16: g_1(g_1(x)) -> g_1(h_1(g_1(x))) r17: h_1(h_1(x)) -> h_1(f_2(h_1(x),x)) r18: map_2(|fun|,nil_0()) -> nil_0() r19: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r20: filter_2(|fun|,nil_0()) -> nil_0() r21: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r22: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r23: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r1, r2, r3, r4, r5, r8, r9, r13, r20 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: filter_2#_A(x1,x2) = x2 + 8 cons_2_A(x1,x2) = max{20, x1 + 8, x2 + 10} filter2_4#_A(x1,x2,x3,x4) = max{x3 + 7, x4 + 9} app_A(x1,x2) = max{15, x1 + 11, x2 + 11} true_0_A = 18 false_0_A = 12 cons_0_A = 6 cons_1_A(x1) = max{16, x1 + 1} f_0_A = 1 f_1_A(x1) = max{13, x1 - 12} f_2_A(x1,x2) = max{12, x1 - 29, x2 - 57} filter_0_A = 1 filter_1_A(x1) = max{13, x1 - 34} filter2_1_A(x1) = max{16, x1 - 14} filter2_2_A(x1,x2) = max{17, x1 - 13, x2 + 10} filter2_3_A(x1,x2,x3) = max{8, x1 - 12, x2 - 12, x3 - 12} map_0_A = 1 map_1_A(x1) = max{14, x1 - 12} filter_2_A(x1,x2) = max{19, x1 - 24, x2 - 21} nil_0_A = 0 base order 2: precedence: filter_2 > app > f_0 = filter_1 = filter2_2 = filter2_3 = map_0 > cons_2 = filter_0 = filter2_1 = map_1 = nil_0 > filter_2# = filter2_4# = cons_1 = f_2 > true_0 = false_0 = cons_0 = f_1 partial status: pi(filter_2#) = [2] pi(cons_2) = [1, 2] pi(filter2_4#) = [] pi(app) = [1] pi(true_0) = [] pi(false_0) = [] pi(cons_0) = [] pi(cons_1) = [1] pi(f_0) = [] pi(f_1) = [] pi(f_2) = [] pi(filter_0) = [] pi(filter_1) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(filter2_3) = [] pi(map_0) = [] pi(map_1) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p3 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p2: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(filter2_0(),y) -> filter2_1(y) r8: app(filter2_1(x1),y) -> filter2_2(x1,y) r9: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r10: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r11: app(g_0(),y) -> g_1(y) r12: app(h_0(),y) -> h_1(y) r13: app(map_0(),y) -> map_1(y) r14: app(map_1(x1),y) -> map_2(x1,y) r15: g_1(h_1(g_1(x))) -> g_1(x) r16: g_1(g_1(x)) -> g_1(h_1(g_1(x))) r17: h_1(h_1(x)) -> h_1(f_2(h_1(x),x)) r18: map_2(|fun|,nil_0()) -> nil_0() r19: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r20: filter_2(|fun|,nil_0()) -> nil_0() r21: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r22: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r23: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The estimated dependency graph contains the following SCCs: {p1, p2} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p2: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(filter2_0(),y) -> filter2_1(y) r8: app(filter2_1(x1),y) -> filter2_2(x1,y) r9: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r10: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r11: app(g_0(),y) -> g_1(y) r12: app(h_0(),y) -> h_1(y) r13: app(map_0(),y) -> map_1(y) r14: app(map_1(x1),y) -> map_2(x1,y) r15: g_1(h_1(g_1(x))) -> g_1(x) r16: g_1(g_1(x)) -> g_1(h_1(g_1(x))) r17: h_1(h_1(x)) -> h_1(f_2(h_1(x),x)) r18: map_2(|fun|,nil_0()) -> nil_0() r19: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r20: filter_2(|fun|,nil_0()) -> nil_0() r21: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r22: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r23: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r1, r2, r3, r4, r5, r7, r8, r13, r20 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: filter_2#_A(x1,x2) = x2 + 2 cons_2_A(x1,x2) = max{x1 + 9, x2 + 6} filter2_4#_A(x1,x2,x3,x4) = max{x3 + 8, x4 + 3} app_A(x1,x2) = max{26, x1 - 10, x2 + 21} true_0_A = 22 cons_0_A = 1 cons_1_A(x1) = x1 + 20 f_0_A = 1 f_1_A(x1) = max{2, x1 - 1} f_2_A(x1,x2) = max{22, x1 - 120, x2 - 97} filter_0_A = 8 filter_1_A(x1) = max{9, x1 - 1} filter2_0_A = 7 filter2_1_A(x1) = max{8, x1 - 1} filter2_2_A(x1,x2) = max{9, x1 - 12, x2 - 1} map_0_A = 9 map_1_A(x1) = max{1, x1 - 12} filter_2_A(x1,x2) = max{23, x1 - 12, x2 - 8} nil_0_A = 0 base order 2: precedence: cons_2 > filter_2 = nil_0 > app > filter_2# = filter2_4# = cons_1 = filter_1 = filter2_0 = map_1 > true_0 = cons_0 = filter_0 = filter2_2 = map_0 > f_2 = filter2_1 > f_1 > f_0 partial status: pi(filter_2#) = [2] pi(cons_2) = [1, 2] pi(filter2_4#) = [] pi(app) = [2] pi(true_0) = [] pi(cons_0) = [] pi(cons_1) = [] pi(f_0) = [] pi(f_1) = [] pi(f_2) = [] pi(filter_0) = [] pi(filter_1) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(map_0) = [] pi(map_1) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p2 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(filter2_0(),y) -> filter2_1(y) r8: app(filter2_1(x1),y) -> filter2_2(x1,y) r9: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r10: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r11: app(g_0(),y) -> g_1(y) r12: app(h_0(),y) -> h_1(y) r13: app(map_0(),y) -> map_1(y) r14: app(map_1(x1),y) -> map_2(x1,y) r15: g_1(h_1(g_1(x))) -> g_1(x) r16: g_1(g_1(x)) -> g_1(h_1(g_1(x))) r17: h_1(h_1(x)) -> h_1(f_2(h_1(x),x)) r18: map_2(|fun|,nil_0()) -> nil_0() r19: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r20: filter_2(|fun|,nil_0()) -> nil_0() r21: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r22: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r23: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The estimated dependency graph contains the following SCCs: (no SCCs) -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(filter2_0(),y) -> filter2_1(y) r8: app(filter2_1(x1),y) -> filter2_2(x1,y) r9: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r10: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r11: app(g_0(),y) -> g_1(y) r12: app(h_0(),y) -> h_1(y) r13: app(map_0(),y) -> map_1(y) r14: app(map_1(x1),y) -> map_2(x1,y) r15: g_1(h_1(g_1(x))) -> g_1(x) r16: g_1(g_1(x)) -> g_1(h_1(g_1(x))) r17: h_1(h_1(x)) -> h_1(f_2(h_1(x),x)) r18: map_2(|fun|,nil_0()) -> nil_0() r19: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r20: filter_2(|fun|,nil_0()) -> nil_0() r21: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r22: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r23: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r1, r3, r4, r5, r7, r8, r9, r13, r20 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: map_2#_A(x1,x2) = x2 + 12 cons_2_A(x1,x2) = max{x1 - 11, x2 + 13} app_A(x1,x2) = max{10, x1 - 16, x2 - 27} cons_0_A = 1 cons_1_A(x1) = max{2, x1 - 28} f_0_A = 15 f_1_A(x1) = max{7, x1 - 28} f_2_A(x1,x2) = max{8, x1 - 44, x2 - 73} filter_0_A = 8 filter_1_A(x1) = max{9, x1 - 28} filter2_0_A = 1 filter2_1_A(x1) = max{9, x1 - 28} filter2_2_A(x1,x2) = max{8, x1 - 45, x2 - 28} filter2_3_A(x1,x2,x3) = max{10, x1 - 61, x2 - 44, x3 - 27} map_0_A = 1 map_1_A(x1) = max{2, x1 - 28} filter_2_A(x1,x2) = max{11, x1 - 15, x2 - 15} nil_0_A = 0 base order 2: precedence: filter_2 = nil_0 > app > cons_2 = cons_0 = f_0 = filter_1 = filter2_3 = map_1 > map_2# = cons_1 = filter_0 = filter2_2 = map_0 > f_2 = filter2_1 > f_1 = filter2_0 partial status: pi(map_2#) = [] pi(cons_2) = [2] pi(app) = [] pi(cons_0) = [] pi(cons_1) = [] pi(f_0) = [] pi(f_1) = [] pi(f_2) = [] pi(filter_0) = [] pi(filter_1) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(filter2_3) = [] pi(map_0) = [] pi(map_1) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p1 Then no dependency pair remains. -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: g_1#(g_1(x)) -> g_1#(h_1(g_1(x))) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(filter2_0(),y) -> filter2_1(y) r8: app(filter2_1(x1),y) -> filter2_2(x1,y) r9: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r10: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r11: app(g_0(),y) -> g_1(y) r12: app(h_0(),y) -> h_1(y) r13: app(map_0(),y) -> map_1(y) r14: app(map_1(x1),y) -> map_2(x1,y) r15: g_1(h_1(g_1(x))) -> g_1(x) r16: g_1(g_1(x)) -> g_1(h_1(g_1(x))) r17: h_1(h_1(x)) -> h_1(f_2(h_1(x),x)) r18: map_2(|fun|,nil_0()) -> nil_0() r19: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r20: filter_2(|fun|,nil_0()) -> nil_0() r21: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r22: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r23: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r1, r2, r3, r4, r5, r7, r8, r12, r13, r15, r16, r17, r20 Take the reduction pair: generalized weighted path order (>=MG, >MG) base order 1: max/plus interpretation on natural numbers: g_1#_A(x1) = max{6, x1 + 1} g_1_A(x1) = x1 + 11 h_1_A(x1) = max{10, x1 - 9} app_A(x1,x2) = max{11, x1 - 13, x2 - 4} cons_0_A = 1 cons_1_A(x1) = max{2, x1 - 5} cons_2_A(x1,x2) = max{3, x1 - 38, x2 - 24} f_0_A = 10 f_1_A(x1) = max{11, x1 - 4} f_2_A(x1,x2) = max{8, x1 - 18, x2 - 19} filter_0_A = 3 filter_1_A(x1) = max{4, x1 - 5} filter2_0_A = 1 filter2_1_A(x1) = max{2, x1 - 5} filter2_2_A(x1,x2) = max{3, x1 - 19, x2 - 5} h_0_A = 9 map_0_A = 8 map_1_A(x1) = max{9, x1 - 38} filter_2_A(x1,x2) = max{5, x1 - 21, x2 - 26} nil_0_A = 0 base order 2: precedence: cons_0 > g_1 = filter2_2 = filter_2 = nil_0 > g_1# = app = filter2_1 > h_1 = filter_1 = filter2_0 > cons_1 = cons_2 = f_2 = filter_0 = h_0 = map_1 > f_1 = map_0 > f_0 partial status: pi(g_1#) = [1] pi(g_1) = [1] pi(h_1) = [] pi(app) = [] pi(cons_0) = [] pi(cons_1) = [] pi(cons_2) = [] pi(f_0) = [] pi(f_1) = [] pi(f_2) = [] pi(filter_0) = [] pi(filter_1) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(filter2_2) = [] pi(h_0) = [] pi(map_0) = [] pi(map_1) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p1 Then no dependency pair remains.