YES

1 decompositions
 #1 -----------
   1: H(F(x1,x2)) -> F(H(R(x1)),x2)
   2: F(x3,K(x4,x5)) -> G(P(x4),Q(x5,x3))
   3: H(Q(x6,x7)) -> Q(x6,H(R(x7)))
   4: Q(x8,H(R(x9))) -> H(Q(x8,x9))
   5: H(G(x10,x11)) -> G(x10,H(x11))

@Rule Labeling
--- R
   1: H(F(x1,x2)) -> F(H(R(x1)),x2)
   2: F(x3,K(x4,x5)) -> G(P(x4),Q(x5,x3))
   3: H(Q(x6,x7)) -> Q(x6,H(R(x7)))
   4: Q(x8,H(R(x9))) -> H(Q(x8,x9))
   5: H(G(x10,x11)) -> G(x10,H(x11))

--- S
   1: H(F(x1,x2)) -> F(H(R(x1)),x2)
   2: F(x3,K(x4,x5)) -> G(P(x4),Q(x5,x3))
   3: H(Q(x6,x7)) -> Q(x6,H(R(x7)))
   4: Q(x8,H(R(x9))) -> H(Q(x8,x9))
   5: H(G(x10,x11)) -> G(x10,H(x11))