YES

1 decompositions
 #1 -----------
   1: f(x1) -> f(f(x1))
   2: g(x2) -> f(x2)
   3: f(x3) -> g(x3)

@Rule Labeling
--- R
   1: f(x1) -> f(f(x1))
   2: g(x2) -> f(x2)
   3: f(x3) -> g(x3)

--- S
   1: f(x1) -> f(f(x1))
   2: g(x2) -> f(x2)
   3: f(x3) -> g(x3)