YES

1 decompositions
 #0 -----------
   1: +(0(),x) -> x
   2: +(s(x),y) -> s(+(x,y))

@Mutually Orthogonal
--- R
   1: +(0(),x) -> x
   2: +(s(x),y) -> s(+(x,y))

--- S
   1: +(0(),x) -> x
   2: +(s(x),y) -> s(+(x,y))