YES Confluence Proof

Confluence Proof

by csi

Input

The rewrite relation of the following TRS is considered.

+(x,0) x
+(x,s(y)) s(+(x,y))
-(0,x) 0
-(x,0) x
-(s(x),s(y)) -(x,y)

Proof

1 Redundant Rules Transformation

To prove that the TRS is (non-)confluent, we show (non-)confluence of the following modified system:

-(s(x),s(y)) -(x,y)
-(x,0) x
-(0,x) 0
+(x,s(y)) s(+(x,y))
+(x,0) x

All redundant rules that were added or removed can be simulated in 2 steps .

1.1 Critical Pair Closing System

Confluence is proven using the following terminating critical-pair-closing-system R:

There are no rules.

1.1.1 R is empty

There are no rules in the TRS. Hence, it is terminating.

Tool configuration

csi