YES

Problem:
 0(1(2(3(4(x))))) -> 0(2(1(3(4(x)))))
 0(5(1(2(4(3(x)))))) -> 0(5(2(1(4(3(x))))))
 0(5(2(4(1(3(x)))))) -> 0(1(5(2(4(3(x))))))
 0(5(3(1(2(4(x)))))) -> 0(1(5(3(2(4(x))))))
 0(5(4(1(3(2(x)))))) -> 0(5(4(3(1(2(x))))))

Proof:
 Church Rosser Transformation Processor:
  
  critical peaks: joinable
  Qed