YES

1 decompositions
 #0 -----------
   1: +(0(),y) -> y
   2: +(x,0()) -> x
   3: +(s(x),y) -> s(+(x,y))
   4: +(x,s(y)) -> s(+(x,y))
   5: +(x,y) -> +(y,x)

@Strongly Commuting
--- R
   1: +(0(),y) -> y
   2: +(x,0()) -> x
   3: +(s(x),y) -> s(+(x,y))
   4: +(x,s(y)) -> s(+(x,y))
   5: +(x,y) -> +(y,x)

--- S
   1: +(0(),y) -> y
   2: +(x,0()) -> x
   3: +(s(x),y) -> s(+(x,y))
   4: +(x,s(y)) -> s(+(x,y))
   5: +(x,y) -> +(y,x)