YES

1 decompositions
 #0 -----------
   1: +(0(),y) -> y
   2: +(s(0()),y) -> s(y)
   3: s(s(x)) -> x

@Strongly Commuting
--- R
   1: +(0(),y) -> y
   2: +(s(0()),y) -> s(y)
   3: s(s(x)) -> x

--- S
   1: +(0(),y) -> y
   2: +(s(0()),y) -> s(y)
   3: s(s(x)) -> x