YES

2 decompositions
 #0 -----------
   1: b() -> c()

 #1 -----------
   2: a() -> a()

@Mutually Orthogonal
--- R
   1: b() -> c()

--- S
   1: b() -> c()


@Mutually Orthogonal
--- R
   2: a() -> a()

--- S
   2: a() -> a()