YES

1 decompositions
 #0 -----------
   1: a(a(b(b(x)))) -> b(b(b(b(b(a(a(a(a(a(x))))))))))

@Mutually Orthogonal
--- R
   1: a(a(b(b(x)))) -> b(b(b(b(b(a(a(a(a(a(x))))))))))

--- S
   1: a(a(b(b(x)))) -> b(b(b(b(b(a(a(a(a(a(x))))))))))