YES

# Compositional parallel critical pair system (Shintani and Hirokawa 2022).

Consider the left-linear TRS R:

  +(0(),y) -> y
  +(x,0()) -> x
  +(s(x),y) -> s(+(x,y))
  +(x,s(y)) -> s(+(x,y))
  +(x,+(y,z)) -> +(+(x,y),z)
  +(+(x,y),z) -> +(x,+(y,z))

Let C be the following subset of R:

  +(0(),y) -> y
  +(x,0()) -> x
  +(s(x),y) -> s(+(x,y))
  +(x,s(y)) -> s(+(x,y))
  +(+(x,y),z) -> +(x,+(y,z))

The parallel critical pair system PCPS(R,C) is:

  (empty)

All pairs in PCP(R) are joinable and PCPS(R,C)/R is terminating.
Therefore, the confluence of R follows from that of C.

# Compositional parallel critical pair system (Shintani and Hirokawa 2022).

Consider the left-linear TRS R:

  +(0(),y) -> y
  +(x,0()) -> x
  +(s(x),y) -> s(+(x,y))
  +(x,s(y)) -> s(+(x,y))
  +(+(x,y),z) -> +(x,+(y,z))

Let C be the following subset of R:

  (empty)

The parallel critical pair system PCPS(R,C) is:

  +(0(),s(x0_2)) -> s(+(0(),x0_2))
  +(0(),s(x0_2)) -> s(x0_2)
  +(s(x0_1),0()) -> s(+(x0_1,0()))
  +(s(x0_1),0()) -> s(x0_1)
  +(+(x0_1,x0_2),0()) -> +(x0_1,+(x0_2,0()))
  +(+(x0_1,x0_2),0()) -> +(x0_1,x0_2)
  +(s(y1),0()) -> s(y1)
  +(s(y1),0()) -> s(+(y1,0()))
  +(s(y1),s(x0_2)) -> s(+(s(y1),x0_2))
  +(s(y1),s(x0_2)) -> s(+(y1,s(x0_2)))
  +(0(),s(y2)) -> s(y2)
  +(0(),s(y2)) -> s(+(0(),y2))
  +(s(x0_1),s(y2)) -> s(+(x0_1,s(y2)))
  +(s(x0_1),s(y2)) -> s(+(s(x0_1),y2))
  +(+(x0_1,x0_2),s(y2)) -> +(x0_1,+(x0_2,s(y2)))
  +(+(x0_1,x0_2),s(y2)) -> s(+(+(x0_1,x0_2),y2))
  +(+(y1,y2),0()) -> +(y1,y2)
  +(+(y1,y2),0()) -> +(y1,+(y2,0()))
  +(+(y1,y2),s(x0_2)) -> s(+(+(y1,y2),x0_2))
  +(+(y1,y2),s(x0_2)) -> +(y1,+(y2,s(x0_2)))
  +(+(0(),y2),y3) -> +(y2,y3)
  +(+(0(),y2),y3) -> +(0(),+(y2,y3))
  +(+(y1,0()),y3) -> +(y1,y3)
  +(+(y1,0()),y3) -> +(y1,+(0(),y3))
  +(+(s(x1_1),y2),y3) -> +(s(+(x1_1,y2)),y3)
  +(+(s(x1_1),y2),y3) -> +(s(x1_1),+(y2,y3))
  +(+(y1,s(x1_2)),y3) -> +(s(+(y1,x1_2)),y3)
  +(+(y1,s(x1_2)),y3) -> +(y1,+(s(x1_2),y3))
  +(+(+(x1_1,x1_2),y2),y3) -> +(+(x1_1,+(x1_2,y2)),y3)
  +(+(+(x1_1,x1_2),y2),y3) -> +(+(x1_1,x1_2),+(y2,y3))

All pairs in PCP(R) are joinable and PCPS(R,C)/R is terminating.
Therefore, the confluence of R follows from that of C.

# emptiness

The empty TRS is confluent.