YES

1 decompositions
 #0 -----------
   1: +(0(),y) -> y
   2: +(s(x),y) -> s(+(x,y))
   3: +(x,0()) -> x
   4: +(x,s(y)) -> s(+(x,y))

@Strongly Commuting
--- R
   1: +(0(),y) -> y
   2: +(s(x),y) -> s(+(x,y))
   3: +(x,0()) -> x
   4: +(x,s(y)) -> s(+(x,y))

--- S
   1: +(0(),y) -> y
   2: +(s(x),y) -> s(+(x,y))
   3: +(x,0()) -> x
   4: +(x,s(y)) -> s(+(x,y))