YES

1 decompositions
 #0 -----------
   1: a() -> c()
   2: c() -> a()
   3: d() -> a()
   4: b() -> d()
   5: a() -> b()
   6: a() -> e()
   7: d() -> e()

@Rule Labeling
--- R
   1: a() -> c()
   2: c() -> a()
   3: d() -> a()
   4: b() -> d()
   5: a() -> b()
   6: a() -> e()
   7: d() -> e()

--- S
   1: a() -> c()
   2: c() -> a()
   3: d() -> a()
   4: b() -> d()
   5: a() -> b()
   6: a() -> e()
   7: d() -> e()