YES

1 decompositions
 #0 -----------
   1: +(s(x),y) -> s(+(x,y))
   2: s(s(x)) -> x

@Jouannaud and Kirchner's criterion
--- R
   1: +(s(x),y) -> s(+(x,y))
   2: s(s(x)) -> x

--- S
   1: +(s(x),y) -> s(+(x,y))
   2: s(s(x)) -> x