NO

Problem:
 +(0(),y) -> y
 +(s(x),y) -> s(+(x,y))
 *(0(),y) -> 0()
 *(s(x),y) -> +(*(x,y),y)
 *(x,s(y)) -> +(x,*(x,y))

Proof:
 Nonconfluence Processor:
  terms: +(+(x182,*(x182,y)),s(y)) *<- *(s(x182),s(y)) ->* s(+(x182,+(*(x182,y),y)))
  Qed