YES

2 decompositions
 #0 -----------
   3: c() -> b()

 #1 -----------
   1: a() -> a()
   2: f(h(a(),a())) -> f(b())

@Mutually Orthogonal
--- R
   3: c() -> b()

--- S
   3: c() -> b()


@Strongly Commuting
--- R
   1: a() -> a()
   2: f(h(a(),a())) -> f(b())

--- S
   1: a() -> a()
   2: f(h(a(),a())) -> f(b())