YES

1 decompositions
 #0 -----------
   1: f(x) -> f(f(x))
   2: g(x) -> f(x)
   3: f(x) -> g(x)

@Rule Labeling
--- R
   1: f(x) -> f(f(x))
   2: g(x) -> f(x)
   3: f(x) -> g(x)

--- S
   1: f(x) -> f(f(x))
   2: g(x) -> f(x)
   3: f(x) -> g(x)