YES

1 decompositions
 #0 -----------
   1: 0(1(2(3(4(x))))) -> 0(2(1(3(4(x)))))
   2: 0(5(1(2(4(3(x)))))) -> 0(5(2(1(4(3(x))))))
   3: 0(5(2(4(1(3(x)))))) -> 0(1(5(2(4(3(x))))))
   4: 0(5(3(1(2(4(x)))))) -> 0(1(5(3(2(4(x))))))
   5: 0(5(4(1(3(2(x)))))) -> 0(5(4(3(1(2(x))))))

@Mutually Orthogonal
--- R
   1: 0(1(2(3(4(x))))) -> 0(2(1(3(4(x)))))
   2: 0(5(1(2(4(3(x)))))) -> 0(5(2(1(4(3(x))))))
   3: 0(5(2(4(1(3(x)))))) -> 0(1(5(2(4(3(x))))))
   4: 0(5(3(1(2(4(x)))))) -> 0(1(5(3(2(4(x))))))
   5: 0(5(4(1(3(2(x)))))) -> 0(5(4(3(1(2(x))))))

--- S
   1: 0(1(2(3(4(x))))) -> 0(2(1(3(4(x)))))
   2: 0(5(1(2(4(3(x)))))) -> 0(5(2(1(4(3(x))))))
   3: 0(5(2(4(1(3(x)))))) -> 0(1(5(2(4(3(x))))))
   4: 0(5(3(1(2(4(x)))))) -> 0(1(5(3(2(4(x))))))
   5: 0(5(4(1(3(2(x)))))) -> 0(5(4(3(1(2(x))))))