YES # Compositional parallel rule labeling (Shintani and Hirokawa 2022). Consider the left-linear TRS R: +(x,0()) -> x +(x,s(y)) -> s(+(x,y)) +(0(),y) -> y +(s(x),y) -> s(+(x,y)) *(k(),0()) -> 0() *(k(),s(y)) -> +(k(),*(k(),y)) +(x,y) -> +(y,x) +(+(x,y),z) -> +(x,+(y,z)) Let C be the following subset of R: (empty) All parallel critical peaks (except C's) are decreasing wrt rule labeling: phi(+(x,0()) -> x) = 6 phi(+(x,s(y)) -> s(+(x,y))) = 3 phi(+(0(),y) -> y) = 6 phi(+(s(x),y) -> s(+(x,y))) = 3 phi(*(k(),0()) -> 0()) = 1 phi(*(k(),s(y)) -> +(k(),*(k(),y))) = 1 phi(+(x,y) -> +(y,x)) = 5 phi(+(+(x,y),z) -> +(x,+(y,z))) = 8 psi(+(x,0()) -> x) = 6 psi(+(x,s(y)) -> s(+(x,y))) = 1 psi(+(0(),y) -> y) = 6 psi(+(s(x),y) -> s(+(x,y))) = 2 psi(*(k(),0()) -> 0()) = 1 psi(*(k(),s(y)) -> +(k(),*(k(),y))) = 1 psi(+(x,y) -> +(y,x)) = 4 psi(+(+(x,y),z) -> +(x,+(y,z))) = 7 Therefore, the confluence of R follows from that of C. # Compositional parallel critical pair system (Shintani and Hirokawa 2022). Consider the left-linear TRS R: (empty) Let C be the following subset of R: (empty) The parallel critical pair system PCPS(R,C) is: (empty) All pairs in PCP(R) are joinable and PCPS(R,C)/R is terminating. Therefore, the confluence of R follows from that of C. # emptiness The empty TRS is confluent.