YES

# parallel critical pair closing system (Shintani and Hirokawa 2022, Section 8 in LMCS 2023)

Consider the left-linear TRS R:

  a() -> b()
  a() -> d()
  b() -> a()
  c() -> a()
  c() -> b()

Let C be the following subset of R:

  b() -> a()
  c() -> b()
  a() -> b()
  a() -> d()

The TRS R is left-linear and all parallel critical pairs are joinable by C.
Therefore, the confluence of R is equivalent to that of C.

# parallel critical pair closing system (Shintani and Hirokawa 2022, Section 8 in LMCS 2023)

Consider the left-linear TRS R:

  b() -> a()
  c() -> b()
  a() -> b()
  a() -> d()

Let C be the following subset of R:

  a() -> b()
  b() -> a()
  a() -> d()

The TRS R is left-linear and all parallel critical pairs are joinable by C.
Therefore, the confluence of R is equivalent to that of C.

# Compositional parallel critical pair system (Shintani and Hirokawa 2022).

Consider the left-linear TRS R:

  a() -> b()
  b() -> a()
  a() -> d()

Let C be the following subset of R:

  a() -> b()
  b() -> a()
  a() -> d()

The parallel critical pair system PCPS(R,C) is:

  (empty)

All pairs in PCP(R) are joinable and PCPS(R,C)/R is terminating.
Therefore, the confluence of R follows from that of C.

# Parallel rule labeling (Zankl et al. 2015).

Consider the left-linear TRS R:

  a() -> b()
  b() -> a()
  a() -> d()

All parallel critical peaks (except C's) are decreasing wrt rule labeling:

  phi(a() -> b()) = 3
  phi(b() -> a()) = 1
  phi(a() -> d()) = 2

  psi(a() -> b()) = 3
  psi(b() -> a()) = 1
  psi(a() -> d()) = 2