YES

1 decompositions
 #1 -----------
   1: +(0(),x1) -> x1
   2: +(1(),-(1())) -> 0()
   3: +(+(x1,x2),x3) -> +(x1,+(x2,x3))
   4: +(x1,x2) -> +(x2,x1)

@Jouannaud and Kirchner's criterion
--- R
   1: +(0(),x1) -> x1
   2: +(1(),-(1())) -> 0()
   3: +(+(x1,x2),x3) -> +(x1,+(x2,x3))
   4: +(x1,x2) -> +(x2,x1)

--- S
   1: +(0(),x1) -> x1
   2: +(1(),-(1())) -> 0()
   3: +(+(x1,x2),x3) -> +(x1,+(x2,x3))
   4: +(x1,x2) -> +(x2,x1)