YES

1 decompositions
 #1 -----------
   1: -(+(x(),-(x()))) -> 0()
   2: +(x(),-(x())) -> 0()
   3: 0() -> -(0())

@Rule Labeling
--- R
   1: -(+(x(),-(x()))) -> 0()
   2: +(x(),-(x())) -> 0()
   3: 0() -> -(0())

--- S
   1: -(+(x(),-(x()))) -> 0()
   2: +(x(),-(x())) -> 0()
   3: 0() -> -(0())