YES

1 decompositions
 #1 -----------
   1: H(F(x1,x2)) -> F(H(R(x1)),x2)
   2: F(x1,K(x2,x3)) -> G(P(x2),Q(x3,x1))
   3: H(Q(x1,x2)) -> Q(x1,H(R(x2)))
   4: Q(x1,H(R(x2))) -> H(Q(x1,x2))
   5: H(G(x1,x2)) -> G(x1,H(x2))

@Rule Labeling
--- R
   1: H(F(x1,x2)) -> F(H(R(x1)),x2)
   2: F(x1,K(x2,x3)) -> G(P(x2),Q(x3,x1))
   3: H(Q(x1,x2)) -> Q(x1,H(R(x2)))
   4: Q(x1,H(R(x2))) -> H(Q(x1,x2))
   5: H(G(x1,x2)) -> G(x1,H(x2))

--- S
   1: H(F(x1,x2)) -> F(H(R(x1)),x2)
   2: F(x1,K(x2,x3)) -> G(P(x2),Q(x3,x1))
   3: H(Q(x1,x2)) -> Q(x1,H(R(x2)))
   4: Q(x1,H(R(x2))) -> H(Q(x1,x2))
   5: H(G(x1,x2)) -> G(x1,H(x2))