YES

1 decompositions
 #1 -----------
   2: +(x1,s(x2)) -> s(+(x1,x2))
   3: +(x1,x2) -> +(x2,x1)

@Jouannaud and Kirchner's criterion
--- R
   2: +(x1,s(x2)) -> s(+(x1,x2))
   3: +(x1,x2) -> +(x2,x1)

--- S
   2: +(x1,s(x2)) -> s(+(x1,x2))
   3: +(x1,x2) -> +(x2,x1)


NOTE: input TRS is reduced

original is
   1: +(s(x1),x2) -> s(+(x1,x2))
   2: +(x1,s(x2)) -> s(+(x1,x2))
   3: +(x1,x2) -> +(x2,x1)

reduced to
   2: +(x1,s(x2)) -> s(+(x1,x2))
   3: +(x1,x2) -> +(x2,x1)